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8. Using Identity find the value of 97103 |
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Answer» 97 x 103=(100-3)(100+3) ; (a-b)(a+b)=(a^2-b^2); a=100; b=3; (100)^2-(3)^2=10000-9=999 97×103(100-3)(100+3)(100)^2-(3)^210000-99901 sorry 9991is answerthat is right (100-3)×(100+3) after it the answer will be 9991 97×103(100-3)(100+3)(a-b)(a+b)=a^2-b^2(100)^2-(3)^210000-9=9991 |
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