OAB is a sector of the circle with centre O andradius 12 cms. If m ang

1.	OAB is a sector of the circle with centre O andradius 12 cms. If m angleAOB 60°, find the differencebetween the areas ofsectors AOB and ΔΟΑΒ
Answer» Area of Sector is Theta/360pir^2 = 60/36022/71212 = 75.4 sq. cm. Area of equilateral triangle. Since the triangle is an equilateral triangle, then height is sqrt (1212-66) = sqrt(144-36) = sqrt(108) = 10.39 Therefore area = 1/2 10.3923 * 12 = 10.39 * 6 = 62.35 sq. cm Thus, the difference between areas of sector and triangle is = 75.4 - 62.35 = 13.05 sq. cm.

OAB is a sector of the circle with centre O andradius 12 cms. If m angleAOB 60°, find the differencebetween the areas ofsectors AOB and ΔΟΑΒ

Answer»

Area of Sector is Theta/360*pi*r^2 = 60/360*22/7*12*12 = 75.4 sq. cm.

Area of equilateral triangle.

Since the triangle is an equilateral triangle, then height is sqrt (12*12-6*6) = sqrt(144-36) = sqrt(108) = 10.39

Therefore area = 1/2 * 10.3923 * 12 = 10.39 * 6 = 62.35 sq. cm

Thus, the difference between areas of sector and triangle is = 75.4 - 62.35 = 13.05 sq. cm.