OAB is a sector of the circle havingcentre at 0 and radius 12 cm. Ifm

1.	OAB is a sector of the circle havingcentre at 0 and radius 12 cm. Ifm ZAOB = 45", find the differencebetween the area of sector OAB andsector AOB.
Answer» Area of Sector is = (Theta/360) ✖ pi ✖ r^2 = (45/360)(22/7)12*12 = 88 sq. cm. Area of circle = pi ✖ r^2 = (22/7) 12 ✖ 12 = 3168/7 sq.cm area of Sector AOB = (3168/7) - 88 = 2552/7 sq cm.. difference between area of Sector AOB and area of Sector OAB = (2552/7) - 88 = 1936/7 sq.cm (ANS) if you like the answer, Mark it as best bro.. if u like the answer,mark it as best o is center of the circle then :-45°=[45×π÷180]=π/4r=12 then 1/2×12×12×π/418πsq cm

OAB is a sector of the circle havingcentre at 0 and radius 12 cm. Ifm ZAOB = 45", find the differencebetween the area of sector OAB andsector AOB.

Answer»

Area of Sector is = (Theta/360) ✖ pi ✖ r^2 = (45/360)*(22/7)*12*12 = 88 sq. cm.

Area of circle = pi ✖ r^2 = (22/7) 12 ✖ 12 = 3168/7 sq.cm

area of Sector AOB = (3168/7) - 88 = 2552/7 sq cm..

difference between area of Sector AOB and area of Sector OAB = (2552/7) - 88 = 1936/7 sq.cm (ANS)

if you like the answer, Mark it as best bro..

if u like the answer,mark it as best

o is center of the circle then :-45°=[45×π÷180]=π/4r=12 then 1/2×12×12×π/418πsq cm