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बहुपदों के शून्यक ज्ञात कीजिए:() x* +6x° +11x+6et —2x% - Tx* +8x+12(४) x*=3x*-9x-5 |
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Answer» x*x*x*x - 2x*x*x - 7x*x + 8x + 12 = x*x*x*x - 2x*x*x - 7x*x + 14x - 6x + 12 = x*x*x(x-2)-7x(x-2)-6(x-2) = (x-2)(x*x*x-7x-6) = (x-2)(x*x*x+x*x-x*x-x-6x-6) = (x-2)(x+1)(x*x-x-6) = (x-2)(x+2)(x-3)(x+2) zeroes are -2,2,3 |
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