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Let the first term and common differrence be a and d respectivly.

so,a/q3rd term=a+2d7th term=a+6d

so, a+2d+a+6d=62a+8d=62(a+4d)=6a+4d=3a=3-4d..... (1)

and, (a+2d)(a+6d)=8(3-4d+2d)(3-4d+6d)=8 [from (1)](3-2d)(3+2d)=8(3)^2-(2d)^2=89-4d^2=89-8=4d^21=4d^21/4=d^21/2=d

so, a=3-4da=3-2a=1

Therefore, 20th term=a+19d. =1+19*1/2. =1+19/2. =21/2

It is given that the circle circumscribes a square.

•°•

Diameter of circle = Diagonal of square

Now,

Side of square = 6 cm

Diagonal of square = 2 √side = 2√6 cm

Now,

Diameter of circle = 2√6 cm

Radius of circle = ( 2√6 ) / 2 = √6 cm

Now,

Area of circle = πr²

= 22 / 7 × ( √6 )²

= ( 22 / 7 ) × 6

= 18.85 cm²

AB =BC....... (1)BP=BQ........(2)ON SUBTRACTING (1)-(2)AB-BP=BC-BQAP=CQ

=

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is the answer

no

Let the numbers be 8x , 8(x+1) and 8(x+2)

now sum = 888

=> 8x+8x+8+8x+16 = 888=> 24x+24 = 888=> 24x = 888-24=> 24x = 864=> x = 864/24 =36

so, the multiples are 36*8 = 288 =8(36+1)= 296 and = 8(36+2) = 304

we start the solution let first digits x, x+1,x+2x+(x+1)+(x+2)=999x+x+1+x+2=9993x+3=9993x=999-33x=996x=996/3x=332x+1=332+1=333x+2=332+2=334I hope u understand

sin² (pi/6) + cos²(pi/3) - tan²(pi/4)(1/2)² + (1/2)² - 1²1/4 + 1/4 - 11/2 -1-1/2

√3+1/2√2

As there is 0 black ball in the bag. Then probability should be 0.

25^2=625 again the end digit is 5 and as 5^5=25 hence 25^n cannot end with 2

hgcbyhb to you bhaiya please find the attached file

the given is5/5 ×6/21×3=3

3 is the correct answer of the given question

the solution is=3*1=3

thd correct soln of the problem is :3

4.5 is the right answer

4.5 is the correct answer of the given question

4.5 is the correct answer

4.5 is the correct answer.

x=6*3/44x=18x=18/4x=4.5

right ans is 4.5approx 5 not actually 5

4.5 is the answer hope you like it

4.5 is the correct answer

4.5 is correct answer 🤓😎😊☺😃🦄😉😊😂🤗🤔😚😗🤥🤗(●´∀｀●)

81 of [59-56+(13-10)]= 81 of [ 3+3 ]= 81 of [6]= 81×6= 486

plz accept as best

81of [59-(7×8)+(13-(2×5))] =81of [59-56+(13-10)]=81×[3+3]=81×6=486

To prove:

2sin²π/6 +cosec² 7π/6 cos²π/3=3/2

Solution:2sin²π/6 +cosec² 7π/6 cos²π/3

=2sin²30°+cosec² 210 cos ²60°

=2(1/2)²+(-2)²(1/2)²

=(1/2) + 1

=(1+2)/2

=3/2

RHS

Hence proved

Let's suppose √2is a rational number. Then we can write it √2 =a/bwherea,bare whole numbers,bnot zero.

We additionally assume that thisa/bis simplified to lowest terms, since that can obviously be done with any fraction. Notice that in order fora/bto be in simplest terms, both ofaandbcannot be even. One or both must be odd. Otherwise, we could simplifya/bfurther.

From the equality √2 =a/bit follows that 2 =a2/b2, or a2= 2 ·b2. So the square ofais an even number since it is two times something.

From this we know thataitself isalsoan even number. Why? Because it can't be odd; ifaitself was odd, thena·awould be odd too. Odd number times odd number is always odd. Check it if you don't believe me!

Okay, ifaitself is an even number, thenais 2 times some other whole number. In symbols,a= 2k where k is this other number. We don't need to know what k is; it won't matter. Soon comes the contradiction.

If we substitutea= 2k into the original equation 2 =a2/b2, this is what we get:

2=(2k)2/b22=4k2/b22*b2=4k2b2=2k2

This means thatb2is even, from which follows again thatbitself is even. And that is a contradiction!!!

WHY is that a contradiction? Because we started the whole process assuming thata/bwas simplified to lowest terms, and now it turns out thataandbboth would be even. We ended at a contradiction; thus our original assumption (that √2is rational) is not correct. Therefore √2cannot be rational

since value of 17/30=0.5666666.....Therefore it is non terminating and repeating decimal

it is non terminating decimal is the correct answer of the given question

17/30=0.566.... is correct answer of the given question

17/30=0.5666666.....is correct answer

non terminating is a correct option

it is a non terminating decimal

c*c - (c-3d)*(c-3d) = c*c - (c*c - 6cd + 9d*d) = c*c - c*c + 6cd - 9d*d = 6cd - 9d*d = 3d(2c-3d)

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hey listen i have done this in a way of 9 class if any quieres tha comment ok

14/72 answer2) 5/9+4/9+11/920/9 is the right answer

14/7 (2) 20/9answer (3)124/45

= 5040 and it is a composite no.

y²-5y²

= -4y²

is the correct answer

the question answer is 17 apons 5.

T हाँक

Let a be the positive odd integer which when divided by 6 gives q as quotient and r as remainder.

according to Euclid's division lemmaa=bq+r

a=6q+rwhere , a=0,1,2,3,4,5then,a=6qora=6q+1ora=6q+2ora=6q+3ora=6q+4ora=6q+5

but here,a=6q+1 & a=6q+3 & a=6q+5 are odd.

PA=PB=6cm(tangents from P)angle APB=60now in triangle APB PA=PBthereforeangle A= angle B(angle opposite to equal sides are equal)therefore angle A and angle B will be both 60 which means that APB is equilateral triangle and since in an equilateral triangle all sides are equalso chord AB also will be 6cmso correct option is (c) 6cm

PA=PB because they are tangents and so angle A=angle B by property of triangle and Angle APB=60.. since sum of all angle in triangle is 180 degree A and B because they are equal they should be 60 degree each to make 180 degree... and so form equilateral Δso AB=PA=PB=6 cm

the right and is 6 by the concepts of tangents

Thanks

(1) 7 +( -6)7-61 (2)rtsjfjfigugo1

(2) -8-2 =-10

(3 ) -6-5+2 = -11+2 = -9(4) -8-9+17 = -17+17 = 0

(5) -3-8-5 = -16(6) -1+7-3 = -4+7 = 3

a..1b..-11c..-9d...0e...-16f...3

l² = r² + h²

l² = 12² + 3.5²

l² = 156.25

l = √156.25 = 12.5m .

Now,Lateral surface Area = π rl = 3.14 ( 12.5)( 12 ) = 471 m²

Therefore, Required length of canvas = 471m²

area of canvas required to make a conical tent of height 3.5m and radius 12m .

Here, We need to find Lateral surface Area of the cone with given measures.

Before going to find that out, We need to find slant height of the cone ( l) because L. S. A = πrl

We know that, l² = r² + h²

l² = 12² + 3.5²

l² = 156.25

l = √156.25 = 12.5m .

Now, Lateral surface Area = π rl = 3.14 ( 12.5)( 12 ) = 471 m²

Therefore, Required length of canvas = 471m²

inner radius of tank(r)=1mthickness =1cm=0.001m (convert into m )External radius of tank(R)=(1+0.001)=0.01m= 2/3π(cube of big R-cube of small r)= 2/3×22/7×(1.01)3-(1)3=2/3×22/7×0.030301 m3=0.06348m3.

ok

a + ib = [(1 - i) /(1 + i)] ^10= [(1 - i)(1 - i) /(1 + i)(1 - i) ] ^100=[(1 - 2i + i^2)/ (1- i^2)] ^100=[(-2i)/(1+1)]^100= (-i) ^100 = (-i^4)^25= 1

Therefore, (a, b) = (1,0)