(v)The sum of three consecutive multiples of 8 is 888. Find the multip – InterviewSolution

1.

(v)The sum of three consecutive multiples of 8 is 888. Find the multiples.

Answer»

Let the numbers be 8x , 8(x+1) and 8(x+2)

now sum = 888

=> 8x+8x+8+8x+16 = 888=> 24x+24 = 888=> 24x = 888-24=> 24x = 864=> x = 864/24 =36

so, the multiples are 36*8 = 288 =8(36+1)= 296 and = 8(36+2) = 304

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