1.

cosec^2*(((7*pi)/6)*cos(pi/3)^2) %2B 2*sin(pi/6)^2=3/2

Answer»

To prove:

2sin²π/6 +cosec² 7π/6 cos²π/3=3/2

Solution:2sin²π/6 +cosec² 7π/6 cos²π/3

=2sin²30°+cosec² 210 cos ²60°

=2(1/2)²+(-2)²(1/2)²

=(1/2) + 1

=(1+2)/2

=3/2

RHS

Hence proved



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