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\sin ^{2} \frac{\pi}{6}+\cos ^{2} \frac{\pi}{3}-\tan ^{2} \frac{\pi}{4}=-\frac{1}{2} |
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Answer» sin² (pi/6) + cos²(pi/3) - tan²(pi/4)(1/2)² + (1/2)² - 1²1/4 + 1/4 - 11/2 -1-1/2 √3+1/2√2 |
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