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100Ifa + ib, then find (a, b). |
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Answer» a + ib = [(1 - i) /(1 + i)] ^10= [(1 - i)(1 - i) /(1 + i)(1 - i) ] ^100=[(1 - 2i + i^2)/ (1- i^2)] ^100=[(-2i)/(1+1)]^100= (-i) ^100 = (-i^4)^25= 1 Therefore, (a, b) = (1,0) |
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