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8. The sum of three consecutive multiples of 9 is 999. Find the multiples. |
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Answer» we start the solution let first digits x, x+1,x+2x+(x+1)+(x+2)=999x+x+1+x+2=9993x+3=9993x=999-33x=996x=996/3x=332x+1=332+1=333x+2=332+2=334I hope u understand |
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