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This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 27851. |
Mrs. Brown has cleaned the house from ________ to bottom. A) attic B) first floor C) top D) roof E) upstairs |
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Answer» Correct option is C) top |
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| 27852. |
Which of the following statements wrong about aniline A. Positive isocyanide testB. 2,4, DNP (Positive -test)C. Reacts with `CH_(3)MgBr` and evole `CH_(4)` gasD. Give diazotization product by `NaNO_(2)+HCI "on" 0^(@)C "to" 5^(@)C` |
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Answer» Correct Answer - B 2,4 DNP test do not give by aniline |
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| 27853. |
Both ionic and covalent bond is present in the followingA. `CH_(4)`B. KCIC. `SO_(4)`D. NaOH |
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Answer» Correct Answer - D `Na^(+)` ionic `O-H^(-)` covalent |
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| 27854. |
I want to buy assassin creed 3 from flipkart, here i found two ways -(i)CD/DVD (ii)code in the box for pc.Please provide steps to install the game by "code in the box for pc' method . |
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Answer» Installing Assassin’s Creed on Windows Vista or Windows 7. To install Assassin’s Creed:follow these simple steps: 1. Insert the Assassin’s Creed: Installation DVD into your DVD-ROM drive. The Autorun menu should appear. If it does not, browse to your DVD drive and double-click on the Autorun.exe file. 2. Click the Install button. The Installation wizard will walk you through the setup and installation process for the game 3. After installing the game, select Start/ All Programs/ Games and click on Assassin’s Creed: double-click the Assassin’s Creed shortcut on your desktop. |
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| 27855. |
A capacitor is charged using an external battery with a resistance x in series. The dashed line showns the variation of In I with respect to time. If the resistance is changed to 2x, the new graph will be A. PB. QC. RD. S |
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Answer» Correct Answer - B b. The current in RC circuit is given by `I = I_0e^(-t//RC)` or `1nI = 1nI_0 - t/(RC) = (-t)/(RC) + 1NI_0` `=(-t/(RC))+1n(E_0)/R` On comparing with `y = mx + C`, we get Intercept `= 1n (E_0)/R and slope = -1/(RC)` When R is changed to 2R, then slope decreases in magnitude. New graph is Q. |
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| 27856. |
electron affiinitiy is maximum inAlkali metalalkaline earth metalhelogens |
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Answer» Halogen have seven valence electrons in the outermost shell so electron affinity will be high in the halogen as they need only one electron to complete their octet. There is no effect of electron affinity in alkali and alkaline earth metals. |
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| 27857. |
If you are under 18, you are not ________ to join this club. A) available B) legitimate C) capable D) eligible E) permissible |
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Answer» Correct option is D) eligible |
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| 27858. |
When I arrived in this country I had to start learning the language from ________. A) scratch B) nothing C) introduction D) ignorance E) blank |
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Answer» Correct option is A) scratch |
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| 27859. |
In the given circuit, no current is passing through the galvanometer. If the cross sectional diameter of the wire `AB` is doubled, then for null point of galvanometer, the value of `AC` would be: A. `2X`B. `X`C. `(X)/(2)`D. `3X` |
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Answer» Correct Answer - B `L.C=(1)/(50)mm=0.02mm` `M.S.R=3mm` `C.S.R=31xx0.02mm=0.62 mm` Zero eror correction` = -0.12mm` So diameter `=3.50mm` |
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| 27860. |
Formula of the compound in which the element Y forms CCP lattice and atoms of X occupy 1/3rd of THV :-A. `XY_3`B. `X_3Y`C. `X_2Y_3`D. `X_3Y_2` |
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Answer» Correct Answer - C Y `to` CCP = 4 `X to 8 xx 1/3=8/3` `X_2Y_3` |
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| 27861. |
Potentiometer measures potential more accurately because? |
| Answer» Potentiometer measures the emf of a cell when no current flows through its galvanometer, following the laws of wheatstone bridge. Since the circuit is open(no current in balanced state), the accuracy of the measurement is more as compared to the other methods. | |
| 27862. |
Heating pyrites to remove sulphur is called :A. SmeltingB. CalcinationC. LiquationD. Roasting. |
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Answer» Correct Answer - D Sulphur is removed as `SO_(2)` gas in roasting. |
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| 27863. |
For the following elementary first order reaction: If `k_(2)=2k_(1)`, then `%` of B in overall product is:A. `25%`B. `50%`C. `75%`D. `100%` |
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Answer» Correct Answer - B `(1)/(2)(d[B])/(dt)=k_(1)[A] rArr (d[B])/(dt)=2k_(1)[A]` `(d[C])/(dt)=k_(2)[A]` `rArr([B])/([C])=(2k_(1))/(k_(2))=1` `rArr %[B]=(1)/(1+1)xx100=50%` |
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| 27864. |
A compound of vanadium has magnetic moment of 1.73 BM . The vanadium chloride has what formula? |
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Answer» Number of unpaired electron are given by Magnetic moment = √n(n+2) Where n is the No. of unpaired electrons Or 1.73 = √n(n+2) 1.73×1.73=n2+2n ∴ n = 1 Vanadium atom must have one unpaired electron and thus its configuration is 23V4+:1s2,2s22p6,3s23p63d1 |
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| 27865. |
How many statement(s) is/are correct? (a). In every case, a pair of enantiomers have a mirror-image relation (b). Mirror-image molecules are known as enantiomers. (c). If a compound has an enantiomer it must be criral. (d). Every chiral compound has a diastereomer. (e). All diastereomers are chiral. (f). Any molecule containing stereocentre must be chiral. (g). Some diastereomers have a mirror-image relationship. (h). All asymmetric carbon are stereocentres (i). Gauche form of n-butane along `(C_(2)-C_(3))` is chiral is chiral, howerver anti form is achiral. |
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Answer» Correct Answer - 4 (a,c,h,i) |
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| 27866. |
Chloro compound of vanadium has only spin magnetic moment of 1.73 BM. This vanadium chloride has the formula :- (at no. of V=23)A. `VCl_(4)`B. `VCl_(3)`C. `VCl_(2)`D. `VCl_(5)` |
| Answer» Correct Answer - A | |
| 27867. |
Which of the following is not correctly matched :-A. `[Cu(NH_(3))_(2)Cl_(2)]rArr` Hetroleptic complexB. `[Pt(NO_(2))(NH_(3))(H_(2)O)Cl]rArr` Show optical isomerismC. `[Fe(COO^(2-))_(2)]^(-3)rArr` Paramagnetic, show optical isomerismD. `[Co(NH_(3))_(3)Cl_(3)]^(-3)rArr` Show fac-mer isomer |
| Answer» Correct Answer - B | |
| 27868. |
How many total possible products are formed in following reaction: `CH_(3)-CH_(2)-overset(CH_(3))overset(|)CH-CH_(2)-CH_(3)underset("monochlorination")overset((Cl_(2))//hv)to`? |
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Answer» Correct Answer - 8 `C-C-overset(O)overset(|)C-C-underset(Cl)underset(|)C` `R//S` (2) `C-C-overset(C)overset(|)C-underset(Cl)underset(|)C-C` `{:(R R),(SS),(RS),(SR):}]` (4) `C-C-underset(Cl)underset(|)overset(C)overset(|)C-C-C` .(1) `underset(C-C-C-C-C)underset(|)(C-Cl)` (1) |
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| 27869. |
In which of the following including metal at least 5 atoms are in a line? (A) `[Ag(NH_(3))_(2)]^(+)` (B) `[Ag(CN)_(2)]^(-)` (C) `[Ag(SCN)_(2)]^(-)` (D) `[Pt(CN)_(4)]^(-2)`A. A,CB. B,DC. A,BD. A,D |
| Answer» Correct Answer - B | |
| 27870. |
In following how many structures show geometrical isomerism? |
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Answer» Correct Answer - 6 [II,III,IV,VI,VIII,IX] In case of II,III,IV,VI geometrical isomerism exist along `sp^(3)-sp^(3)` carbon. In these cases ring should have at least two `sp^(3)` hybridised carbon with two different group. In case of VIII & IX geometrical isomerism exist with `sp^(2)-sp^(2)` carbon. in cycloalkene geometrical isomerism along with C `=C` exist with eight of more carbon atoms. |
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| 27871. |
Meso-tartaric acid and d-tartaric acid areA. B. C. D. |
| Answer» Correct Answer - 3 | |
| 27872. |
In following how many structures are chiral? |
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Answer» Correct Answer - 3 [II,VI,VIII] The dissymmetric molecules are always chiral. Molecules in which plane of symmetry, centre of symmetry and alternating axis of symmetry are absent, called dissymmetric molecules. |
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| 27873. |
In following how many molecules contain plane of symmetry. (9). `PCl_(5)` |
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Answer» Correct Answer - 7 2,3,4,6,7,8,9 |
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| 27874. |
For a blue coloured solution obtained in column-2, select the only correct option.A. 1,d,SB. 2,d,QC. 3,b,QD. 4,a,P |
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Answer» Correct Answer - B `Ni^(2+)+"excess"NH_3(aq)tounderset("deep blue coloured solution")([Ni(NH_3)_6]^(2+))` `Ni^(2+), 3d^8, t_(2g)^(2,2,2)e_g^(1,1)implies sp^3d^2` n=2 paramagnetic & octahedral complex `Co^(3+), 3d^8, t_(2g)^(2,2,2)e_g^(1,1)implies sp^3d^2` n=2, paramagnetic & octahedral complex |
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| 27875. |
How many of the following are bidentate ligan? Oxalate, Glycinate, Hydrazine, Xyanide, Acetylacetonate, Diethylenetriamine, `dmg^(ɵ)`, ammonia, sulphate, water. |
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Answer» Correct Answer - 5 Bidentate are oxalate, glycinate, acetyl acetonate, `dmg^(ɵ)` suplhate |
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| 27876. |
For a yellow coloured solution obtained in column-1, select the only correct option.A. 1, c, PB. 2,a, PC. 3, b,SD. 1,d,S |
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Answer» Correct Answer - A `Co^(2+)+"excess"CN^(-)underset(air)tounderset("yellow coloured solution")([Co(CN)_6]^(3-))` `Co^(2+)+"excess"CN^(-)underset(air)tounderset("yellow coloured solution")([Co(CN)_6]^(3-))` `Co^(3+), 3d^6 ,S.F.Limplies d^2sp^3`& Octahedral complex n=0 `implies` Diamagnetic |
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| 27877. |
An alkene on ozonolysis gives only one product `(Z)`. `Z` on reaction with Fehling solution give red precipitate of `Cu_(2)O`. Alkene will be?A. `Ph-CH=CH-Ph`B. `(CH_(3))_(2)C=C(CH_(3))_(2)`C. `CH_(3)-CH=C(CH_(3))_(2)`D. `CH_(3)-CH=CH-CH_(3)` |
| Answer» Correct Answer - 4 | |
| 27878. |
How many isomers of the complex `Pt(NH_3)_2(SCN)_2` are possible ? |
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Answer» Correct Answer - 6 `[Pt(NH_3)_2(SCN)_2]` - cis and trans isomers = 2 `[Pt(NH_3)_2(NCS)(SCN)]` - cis and trans isomers = 2 `[Pt(NH_3)_2(NCS)_2]` - cis and trans isomers = 2 The complex is square planar , so it does not have a pari of enantiomer on account of the presence of plane of symmetry. |
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| 27879. |
In how many of the following reactions one of the products is obtained as a black precipitate ? (i)`Bi(OH)_3 darr +[Sn(OH)_4]^(2-)(aq)to`Products (ii)`Bi^(3+)(aq)+I^(-)(aq)("not in excess")to`Products (iii)`Bi^(3+)(aq)+H_2S(g)overset(H^+)to`Products (iv)`[Bil_4]^(-)(aq)+H_2O(l)overset("dilution")to`Products (v)`Bi^(3+)(aq)+C_9H_7ON(5%)+H^(+)(aq)+I^(-)(6M)to` Products (vi)`Bi^(3+)(aq)+C_6H_3(OH)_3(10%)to`Products (vii)`BiO. OH darr + H_2O_2(aq)to` Products |
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Answer» Correct Answer - 4 (i)`2Bi(OH)_3darr+3[Sn(OH)_4]^(2-)(aq)to2Bidarr("black")+3[Sn(OH)_6]^(2-)` (ii)`Bi^(3+)(aq)+3I^(-)(aq)("not in excess")to Bil_3`(black) (iii)`2Bi^(3+)(aq)+3H_2S(g)overset(H^+)toBi_2S_3darr`(black)+`6H^(+)` (iv)`[Bil_4]^(-)(aq)+H_2O(l)overset("dilution")toBil_3darr`(black)+`I^(-)` (v)`Bi^(3+)(aq)+C_9H_7ON(5%)+H^(+)(aq)+4l^(-)(6M)toC_9H_7ON.HBil_4darr("red")` (vi)`Bi^(3+)(aq)+C_6H_3(OH)_3(10%)toBi(C_6H_3O_3)darr("yellow")+3H^(+)` (vii)`BiO. OHdarr+H_2O_2(aq)toBiO_3^(-)("yellowish-brown")+H^(+)+H_2O` |
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| 27880. |
What happens if we use a fuse made up of same wire which is used to make the electric circuit ? |
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Answer» (1) If we use a fuse made up of same wire which is used to make the electric circuit having high melting point, it does not melt when high voltage occurs. (2) So, it cannot protect electrical appliances from getting damaged due to overloading. |
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| 27881. |
What is the cause of presbyopia ? |
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Answer» Presbyopia is caused due to decrease in the power of accommodation of the eyes due to ageing and weakening of ciliary muscles diminishing flexibility of eye lens. A person with this defect cannot see nearby objects and as well as far off objects clearly. It can be corrected by using bi - focal lens with both concave and convex lens in it. |
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| 27882. |
Why acetic acid is called weak acid though there are four H atoms in the molecule ? |
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Answer» Only one of the four H atoms of the CH3COOH is released as H+ ion in solution. So, acetic acid is called weak acid and also acetic acid does not undergo complete ionisation. |
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| 27883. |
The speed of light in a diamond is 1,24,000 km/s. Find the refractive index of diamond if the speed of light in air is 3,00,000 km/s. |
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Answer» airnmedium = (Speed of light in air/Speed of light in medium) = c/v airndiamond = 3,00,000 kms-1/1,24,000 kms-1 = 2.42. |
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| 27884. |
An electron is revolving round the nucleus of `He^(+)` ion with speed `2.2 xx 10^(6) m//s`. The potential energy of the electron is (if atomic number of `He = 2, 1 eV = 16 xx 10^(-19) J`. Mass of electron `= 9 xx 10^(-31) kg` )A. `- 13.61 eV`B. `- 6.8 eV`C. `- 27.22 eV`D. zero |
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Answer» Correct Answer - C `KE = (1)/(2)m xx v^(2) = (1)/(2) xx 9 xx 10^(-31) xx (2.2 xx 10^(6))^(2)` `KE = (1)/(2) xx (9 xx 10^(-31) xx (2.2 xx 10^(6))^(2))/(1.6 xx 10^(-19))` `KE = 13.61 eV` `PE = -2 xx KE = -2 xx 13.61 = -27.22 eV` |
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| 27885. |
In a mechanism, the number of Instantaneous centres (I-centres) N is(a) \(\cfrac{n(n-1)}2\)(b) \(\cfrac{n(2n-1)}2\)(c) \(\cfrac{2n(n-1)}3\)(d) \(\cfrac{n(2n-1)}3\) |
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Answer» Correct option is (a) \(\cfrac{n(n-1)}2\) I-centre is defined for the relative motion. For relative motion two links are involved. Therefore two links in combination will give the one I-centre. Number of IC = Number of relative motions If n is the number of links. Number of IC = nc2 \(\cfrac{n(n-1)}2\) |
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| 27886. |
Write moderate reactivity metal ores.Observe the table and answer the following questions.Ore FormulaCinnabarHgSMagnetiteFe3O4GalenaPbS |
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Answer» Magnetite,Galena. |
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| 27887. |
Which one of the following is an incorrect statement ?A. Ozone is diamagnetic in natureB. Ozone oxidizes `PbS` to `PbSO_(4)`C. ozone oxidizes acidic solution of `Kl`D. Ozone is used an oxidizing agent in the manufacture of `KMnO_(4)` |
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Answer» Correct Answer - C Ozone oxidizes alakaline solution of `Kl`. |
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| 27888. |
What are the most likely questions we should expect on strength of materials exams? |
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Answer» In order for a material or object to have a high impact strength, the stresses must be distributed evenly throughout the object. It also must have a large volume with a low modulus of elasticity and a high material yield strength. |
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| 27889. |
Aqueous solution of `Na_(2)S_(2)O_(3)` on reaction with `CI_(2)`, givesA. `Na_(2)S_(4)O_(6)`B. `NaHSO_(4)`C. `NaCl`D. `NaOH` |
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Answer» Correct Answer - B `Na_(2)S_(2)O_(3) + Cl_(2) + H_(2)O rarr NaHSO_(4) + HCl` |
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| 27890. |
How would you account for the increasing oxidising power in the series `VO_2^(o+)ltCr_2O_7^(2-)< MnO_4^(ɵ)`?A. `VO_(2)^(+) lt Cr_(2)O_(7)^(2-) lt MnO_(4)`B. `Cr_(2)O_(7)^(2) lt VO_(2)^(+) lt MnO_(4)^(-)`C. `Cr_(2)O_(7)^(2-) lt MnO_(4)^(-) lt VO_(2)^(-)`D. `MnO_(4)^(-) lt Cr_(2)O_(7)^(2-) lt VO_(2)^(+)` |
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Answer» Correct Answer - A Oxidising power increases with increase of oxidation number of central atom. `Mn (O.S.)` in `MnO_(4)^(-) = +7` `Cr (o .S.)` in `Cr_(2)O_(7)^(2-) = +6` `V (O.S.)` in `VO_(2)^(+) = +5` |
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| 27891. |
What is Hund's rule ? |
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Answer» Hund's rule : According to this rule, electron pairing in orbitals starts only when all available empty orbitals of the same energy are singly occupied. |
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| 27892. |
Observe the following table and answer the following questions.Material Refractive indexx 1 y1.33z1.52t1.52In which material speed of light is more ? |
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Answer» Material 'x'. |
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| 27893. |
Hitesh, a fisherman, faced a lot of problems in selling the fish he caught. His entire community was facing this problem and most of the time they had to dump the fish they caught back into the sea. He read a newspaper article on how people have started ordering online for most of the essentials. He spoke to his fellow fishermen about selling their fish online and started their business with a small delivery truck and an app and slowly and steadily their business started to flourish. What trend has Hitesh spotted? a. Read trends b. Watch trends c. Talk trends d. Think trends |
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Answer» a. Read trends |
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| 27894. |
What not to do during an interview a) Do take notes b) Let your achievements speak for you. c) Answer questions fast and use slangs. d) Ask questions |
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Answer» Correct option: d) Ask questions |
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| 27895. |
Automotive starting motors are a. Series wound b. Series –shunt wound c. Shunt-wound d. Both (a) and (b) above |
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Answer» Correct option: d. Both (a) and (b) above |
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| 27896. |
In which city do the rivers Mula and Mutha merge to form the Mula-Mutha ? |
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Answer» Correct answer is Pune |
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| 27897. |
Find the velocity of a bullet fired in standard air if its Mach angle is 40° |
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Answer» Mach angle, α = 40° γ = 1.4 For standard air : R = 287 J/kg K, t = 15°C or T = 15 + 273 = 288 K Velocity of the bullet, V : Sonic velocity, C = \(\sqrt{γRT}\) = \(\sqrt{1.4\times287\times228}\) = 340.2 m/s Now, sin α = \(\cfrac CV\) sin 40° = \(\cfrac{340.2}V\) or V = \(\cfrac{340.2}{sin40^\circ}\) = 529.26 m/s |
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| 27898. |
The ________allows you to access object and start programme.A. Default menuB. XP menuC. Start menuD. stop menu |
| Answer» Correct Answer - A | |
| 27899. |
The main circuit-board of the system unit is theA. computer programB. control unitC. motherboardD. RAM |
| Answer» Correct Answer - C | |
| 27900. |
Which of the following is billionth of a second?A. GigabyteB. TerabyteC. NanosecondD. microsecond |
| Answer» Correct Answer - C | |