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For the following elementary first order reaction: If `k_(2)=2k_(1)`, then `%` of B in overall product is:A. `25%`B. `50%`C. `75%`D. `100%` |
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Answer» Correct Answer - B `(1)/(2)(d[B])/(dt)=k_(1)[A] rArr (d[B])/(dt)=2k_(1)[A]` `(d[C])/(dt)=k_(2)[A]` `rArr([B])/([C])=(2k_(1))/(k_(2))=1` `rArr %[B]=(1)/(1+1)xx100=50%` |
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