1.

In a mechanism, the number of Instantaneous centres (I-centres) N is(a) \(\cfrac{n(n-1)}2\)(b) \(\cfrac{n(2n-1)}2\)(c) \(\cfrac{2n(n-1)}3\)(d) \(\cfrac{n(2n-1)}3\)

Answer»

Correct option is (a) \(\cfrac{n(n-1)}2\) 

I-centre is defined for the relative motion. For relative motion two links are involved. Therefore two links in combination will give the one I-centre.

Number of IC = Number of relative motions

If n is the number of links.

Number of IC = nc2

\(\cfrac{n(n-1)}2\)



Discussion

No Comment Found

Related InterviewSolutions