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In a mechanism, the number of Instantaneous centres (I-centres) N is(a) \(\cfrac{n(n-1)}2\)(b) \(\cfrac{n(2n-1)}2\)(c) \(\cfrac{2n(n-1)}3\)(d) \(\cfrac{n(2n-1)}3\) |
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Answer» Correct option is (a) \(\cfrac{n(n-1)}2\) I-centre is defined for the relative motion. For relative motion two links are involved. Therefore two links in combination will give the one I-centre. Number of IC = Number of relative motions If n is the number of links. Number of IC = nc2 \(\cfrac{n(n-1)}2\) |
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