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How many isomers of the complex `Pt(NH_3)_2(SCN)_2` are possible ? |
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Answer» Correct Answer - 6 `[Pt(NH_3)_2(SCN)_2]` - cis and trans isomers = 2 `[Pt(NH_3)_2(NCS)(SCN)]` - cis and trans isomers = 2 `[Pt(NH_3)_2(NCS)_2]` - cis and trans isomers = 2 The complex is square planar , so it does not have a pari of enantiomer on account of the presence of plane of symmetry. |
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