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Find the velocity of a bullet fired in standard air if its Mach angle is 40° |
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Answer» Mach angle, α = 40° γ = 1.4 For standard air : R = 287 J/kg K, t = 15°C or T = 15 + 273 = 288 K Velocity of the bullet, V : Sonic velocity, C = \(\sqrt{γRT}\) = \(\sqrt{1.4\times287\times228}\) = 340.2 m/s Now, sin α = \(\cfrac CV\) sin 40° = \(\cfrac{340.2}V\) or V = \(\cfrac{340.2}{sin40^\circ}\) = 529.26 m/s |
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