This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 25001. |
The telescope ‘Chandra’ is installed on the outer space. Identify the correct statements related to it. a. There is no scattering of light in the outer spaceb. There is a greater scattering in the outer spacec. The vision is more accurate and cleard. Presence of dust in the outer space helps in better vision and clarity |
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Answer» Correct statements: a. There is no scattering of light in the outer space c. The vision is more accurate and clear |
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| 25002. |
What is ductility of a metal? |
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Answer» It is a property of metals by virtue of which they can be drawn into thin wire without breaking. |
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| 25003. |
Which of the following hydrocarbons undergo addition reactions?C2H6, C3H8, C3H6, C2H2 and CH4 |
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Answer» Molecule containing minimum one double or triple bond in its molecules (unsaturated hydrocarbon) shows addition reaction. As per question C3H6, C2H2 . |
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| 25004. |
Analyse the picture given below.a. Identify ‘A’. b. Write the chemical equation at ‘B’. c. Add few drops of phenolphthalein to the remaining solution after electrolysis. What change will take place? Why? |
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Answer» a. A – cathode. b. Chemical equation at ‘B’: 2Cl- → Cl2 + 2e- c. Solution turns pink. Because, after electrolysis K+ and OH- ions are present in the remaining solution. That means KOH, an alkali is formed. |
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| 25005. |
Analyse the picture given below and find out whether the places marked are inter visible or notA and B areInter versibilltyB and C areC and D areD and A are |
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| 25006. |
Where is the image formed in these cases? Write down the answer analysing.1. When the object at O is away from the eye, where will be the image formed? Can the object be seen clearly?2. Can the object be seen clearly when it is at O1?3. Why is it not possible to see objects placed at long distances?4. What is its remedy? |
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Answer» 1. In front of retina. Objects can’t be seen clearly. 2. Yes 3. damages are formed in front of retina. 4. This can be overcome by using concave lens of suitable power. |
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| 25007. |
If you didn’t keep scratching that spot on your face, it would soon ________. A) remedy B) cure C) restore D) heal E) mend |
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Answer» Correct option is D) tie for |
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| 25008. |
What is a dominant character ? |
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Answer» The character that will appear in F1 generation is called as dominant character. |
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| 25009. |
What is meant by power of accommodation of the eye? |
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Answer» Power of accommodation is the ability of the eye lens to focus near and far objects clearly on the retina by adjusting its focal length with the help of ciliary muscles. |
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| 25010. |
Five years ago, the sum of the ages of a father and two sons was x years, then after five years, the sum of the ages of all will be _________ years. |
| Answer» 5 years after age of each of father and his two sons will be 10 years more than it was 5years ago. Hence after 5years the sum of thieir age will be x +30 years | |
| 25011. |
Find out the uses of lenses in our day to day life and record them in the science dairy. |
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| 25012. |
Take about 3mL of sodium sulphate solution in a test tube. In another test tube, take about 3mL of barium chloride solution. Mix the two solutions and answer the following:(a) Write the observation of the above experiment.(b) Write the chemical equation of the above observation and mention the type of the reaction. |
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Answer» (a) A white precipitate is sedimentate at the bottom of test tube. (b) Na2SO4 (aq) + BaCl2 (aq) → BaSO4 ↓(s) + 2NaCl (aq) |
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| 25013. |
What has the doctor indicated in the prescription? |
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Answer» The doctor indicated about the type and power of lens. |
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| 25014. |
An object is placed at a distance of 10 cm from a convex mirror of focal length 15 cm. Find the position and nature of the image. |
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Answer» Given f = +15 cm, u = – 10 cm, v = ? By mirror formula 1/v + 1/10 = 1/15 …. (i) Put the given values in eq. (i) with their sign conventions 1/v - 1/10 = 15 We get, v = 6 cm image is formed at 6 cm away from the mirror on right side i.e. virtual m = –v/u = –6/-10 = 0.6 Here, m is less than unity and also positive so image will be diminished, erect and virtual in nature. |
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| 25015. |
Ratio- proportion |
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Answer» A ratio is an ordered pair of numbers a and b, written a / b where b does not equal 0. A proportion is an equation in which two ratios are set equal to each other. |
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| 25016. |
If R be a relation from set A to B defined by xRy`rArr`(x-y) is positive than R is. If A={4,3},B={2,3,4}A. `R={(4,2),(4,3),(3,2)}`B. `R={(4,3),(3,4)}`C. `R={(2,3),(2,5)}`D. `R=phi` |
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Answer» Correct Answer - 1 R : A`to`B where xRy`rArr`x-y is positive i.e., x-y`gt`0`rArrxgtty` |
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| 25017. |
A metal compound A reacts with dilute hydrochloric acid to produce effervescence. The gas evolved extinguishes a burning candle.(a) Name the gas that extinguishes a burning candle.(b) Write a balanced chemical equation for the reaction if one of the compounds formed is calcium chloride |
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Answer» (a) CO2 (b) A must be a metal carbonate. CaCO3(s) + 2HCl → CaCl2(s) + H2O(l) + CO2↑ |
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| 25018. |
What is the importance of DNA copying in reproduction ? |
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Answer» Importance of DNA copying in reproduction : – Due to DNA copying during reproduction parental characters are transferred to progeny. – DNA copying allows, equal separation and distribution of DNA in offspring. |
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| 25019. |
Equation of the tangent to the curve y=`e^(-abs(x))` at the point where it cuts the line x=1-A. is ey+x=2B. is x+y=eC. is ex+y=1D. does not exist |
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Answer» Correct Answer - 1 The point of intersection is (1,`e^(-1)`) `because` x=1, so equation of the curve is =`e^(-x)` `rArr(dy)/(dx)=-e^(-x)` `[(dy)/(dx)]_(x=1)=-e^(-1)`. Hnce equation of tangent is `y-e^(-1)=-e^(-1)(x-1)or,ey+x=2` |
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| 25020. |
Write two differences between axon and dendrite. |
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| 25021. |
Name the respiratory pigment present in our blood state its function |
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Answer» Respiratory pigment present in our blood – Haemoglobin. Function : haemoglobin binds with oxygen and helps in transport of oxygen to the tissues. |
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| 25022. |
What is a neutralisation reaction? Give two examples. |
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Answer» Addition of acid with base to forms salt & water is neutralisation. Reaction 1 NaOH + HNO3 → NaNO3 + H2O Reaction 2 NaOH + HCl → NaCl + H2O |
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| 25023. |
What is time period and frequency ? |
Answer» Time period :The time period is defined as the time taken by a particle to complete one oscillation.It is usually denoted by T. wT=2π=>T=2π/w Frequency :The number of oscillations produced by the particle per second is called frequency.It is denoted by f. It's unit is s–¹ f=1/T |
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| 25024. |
Which is the smallest country in the World ?1. Tuvalu2. Republic of Nauru3. Vatican City4. Republic of San Marino |
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Answer» Correct Answer - Option 3 : Vatican City The correct answer is Vatican City.
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| 25025. |
Which reaction is NOT feasible? (A) \( 2 KI + Br _{2} \longrightarrow 2 KBr + I _{2} \) (B) \( 2 KBr + I _{2} \longrightarrow 2 KI + Br _{2} \) (C) \( 2 KBr + Cl _{2} \longrightarrow 2 KCl + Br _{2} \) (D) \( 2 H _{2} O +2 F _{2} \longrightarrow 4 HF + O _{2} \) |
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Answer» Correct option is (B) 2KBr + I2 → 2KI + Br2 As we know the oxidizing power of halogens decrease as we move from top to bottom, it means the order of oxidizing strength will be F2 > Cl2 > Br2 > I2 ∵ Br2 is more powerful oxidizing agent than I2 it means I2 can not reduce Br- to Br2. ∴ 2KBr + I2 → KI + Br2 is not a feasible reaction. |
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| 25026. |
A ball is thrown vertically upwards with velocity 10 m/s from a trolley moving horizontally with velocity of 8 m/s. A person standing on ground observe its motion. The range observed by him is (g = 10m/s). |
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Answer» Vertical velocity of ball uy=v1 Horizontal velocity of ball ux=v2 Horizontal range of projectile R=2uxuy/g ⟹ R= 2v1v2/g = 2* 10*8/ 10= 16 m Horizontal velocity of ball is trolley S = uHt R = uHt Sg = ugt - \(\frac12\)agt2 Sy = 0 uyt - \(\frac12\)gt2 = 0 uyt = \(\frac12\)gt2 uy = \(\frac{gt}2\) t = \(\frac{2u_y}g\) t = \(\frac{2\times10}{10}\) t = 2 sec Range observed by him is Given uH = 8m/s R = uHt R = 8 x 2 R = 16 m |
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| 25027. |
The sugar seen in DNA. a. Ribose b. Ribosome c. Ribulose d. Deoxyribose sugar |
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Answer» Correct option: d. Deoxyribose sugar |
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| 25028. |
One man and one woman together can complete a piece of work in 12 days. A man alone can complete the work in 30 days. In how many days can one woman alone complete the work?1. 27 days2. 51 days3. 18 days4. 20 days |
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Answer» Correct Answer - Option 4 : 20 days Given: One man and one Woman together can complete a piece of work = 12 days A man can complete the work = 30 days Concept used: Total work = LCM Formula used: Efficiency = Work/Time Calculation Let efficiency of a man and a woman be M and F respectively Total efficiency of a man and a woman = M + F Work done a man and a woman in 12 days = 12(M + F) Total work done a man in 30 days = 30M According to the question, ⇒ 12(M + F) = 30M ⇒ 12 M + 12F = 30 M ⇒ 12F = 18 M ⇒ F ∶ M = 3 ∶ 2 Total work = total efficiency × together work done Total work = 5 × 12 = 60 One woman completes the work = 60/3 = 20 days ∴ One woman completes the work in 20 days |
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| 25029. |
The non-essential amino acid among the following is (1) Valine(2) Leucine(3) Alanine(4) Lysine |
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Answer» Correct option (3) Alanine |
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| 25030. |
Solubility of AgCl in 0.2 M NaCl is x and that in 0.1 M `AgNO_(3)` is y. Then which of the following is correct?A. x=yB. xgtyC. xltyD. we cannot predict |
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Answer» Correct Answer - C More is the concentration of common, lesser is the solubility |
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| 25031. |
The `pK_(a)` for acid A is greater than `pK_(a)` for acid B, the strong acid is :-A. BB. AC. Both Aand BD. None of these |
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Answer» Correct Answer - A `pKa=-logKa" "&" "pKb=-logKb` `uarrpKaKadarr` (Acidic strength) |
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| 25032. |
`(X)overset(KOH+CHCl_(3))rarr(Y)overset(LiAlH_(4))rarrCH_(3)CH_(2)NHCH_(3)` Identify compound XA. ` CH_(3) - CH_(2)- overset(O)overset(||)(C)-OH`B. `CH_(3)-CH_(2)-overset(O)overset(||)(C)-NH_(2)`C. `CH_(3)-CH_(2)- overset(O)overset(||)(C)-Cl`D. `CH_(3)-CH_(2)-NH_(2)` |
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Answer» Correct Answer - D `underset((A))(CH_(3)-CH_(2)-NH_(2)) to underset((B))(CH_(3)- CH_(2)to CH_(3)-CH_(2)-NH-CH_(3))` |
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| 25033. |
500ml of 0.1M HCOOH (formic acid) is mixed with 1500ml of 0.05M H2SO4 solution calculate pH of the solution |
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Answer» In formic acid solution, millimole of COOH2 = Molarity x Volume(ml) = 0.90 |
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| 25034. |
2.4 g of pure Mg (at. Mass = 24) is dropped in 100 mL of 1 M HCl . Which of the following statement is wrong ?A. `1.12` L of hydrogen is produce as S.T.P.B. `0.05` mol of magnesium is left behindC. HCl is the limiting reagent .D. None of these |
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Answer» Correct Answer - D `{:("Mg" " " + " " 2HCl " " to MgCl_(2) + H_(2)), (2.4 g """""" " (1M, 100"ml")" ), (0.1 "mol" " " 0.1 "mol"), (underline(-0.05)), (0.05 "mol"):}` HCl is a limiting reagent `0.1` mol HCl give `(0.1)/(2)` mol `H_(2)` or `1.12` lit `H_(2)` at STP `0.05` mol Mg left `therefore` None of these is wrong. |
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| 25035. |
What will be the mass of one `.^(12)C` atom in `g`? |
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Answer» `1 mol` of `.^(12)C` atoms `=6.022xx10^(23)` atoms`=12 g` Thus, `6.022xx10^(23)` atoms of `.^(12)C` have mass`=12 g` Therefore, `1 "atoms"` of `.^(12)C` will have mass `=12/(6.022xx10^(23))g=1.9927xx10^(-23) g` |
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| 25036. |
In which of the following solvents is silver chloride most soluble and why |
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Answer» Silver chloride form a soluble complex with aqueous ammonia AgCl + 2NH3 → [Ag(NH3)2]Cl so silver chloride is more soluble in aqueous ammonia. |
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| 25037. |
Identify Bronsted -Lowry acids in the reactions given . `[Al(H_(2)O)_(6)]^(+3) + HCO_(3)^(-) hArr` `underset(C)([Al(H_(2)O)_(5)(OH^(-))]^(2+)) + underset(D)(H_(2)CO_(3))` The correct AnswerA. (a) , (d)B. (b) , (c)C. (b) , (d)D. (a) , (c) |
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Answer» Correct Answer - A For forward reaction `[Al(H_(2)O)_(6)]^(+3)` is an acid and for backward reaction `H_(2)CO_(3)` is an acid. |
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| 25038. |
Principle behind the desalination of sea water is ……(a) Endosmosis (b) Diffusion (c) Reverse osmosis (d) Deplasmolysis |
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Answer» (c) Reverse osmosis |
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| 25039. |
In Emerson’s first effect, the photosynthetic yield was dropped in the region above ………(a) 720 nm (b) 620 nm (c) 680 nm (d) 600 nm |
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Answer» In Emerson’s first effect, the photosynthetic yield was dropped in the region above 600 nm. |
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| 25040. |
Main ore of lead is gaalena.This is mined and separated from other minerals by froth flotation.There are two methods of extracting the lead. (i)First method involves the roasting of ore followed by reduction with coke or CO. (ii)Second method involves the partial roasting of ore followed by self reduction. Partial roasting of galena gives :A. only PbSB. only PbOC. PbS+PbOD. PbO+Pb |
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Answer» Correct Answer - C `3PbS+3O_2 (air) to PbS+2PbO+2SO_4` |
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| 25041. |
Main ore of lead is gaalena.This is mined and separated from other minerals by froth flotation.There are two methods of extracting the lead. (i)First method involves the roasting of ore followed by reduction with coke or CO. (ii)Second method involves the partial roasting of ore followed by self reduction. In self reduction process, the species which bring about the reduction is :A. `O_2`B. `S^(2-)`C. `O^(2-)`D. `H_2S` |
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Answer» Correct Answer - B `Pboverset(2-)S + 2PbO underset("absence of air")overset(Delta)to3Pb(l)+overset(+4)(SO_2)uarr` |
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| 25042. |
Which of the following statements is/are false ?A. The halides of beryllium are electron deficient and are polymeric with halogen bridges.B. `BeF_2` is very soluble in water owing to high solvation energy of Be but fluorides of other alkaline earth metals are almost insolubleC. CaO, SrO and BaO react exothermically with water forming soluble hydroxideD. The bicarbonates of alkaline earth metals are only stable in solution |
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Answer» Correct Answer - A,B,C,D All statements are correct. |
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| 25043. |
A metal (M) burns with dazzling brilliance in air to give a white powder.The white powder reacts with water to form a white precipitate and a colourless gas with a characteristic smell.The metal (M) decomposes hot water but not cold water, liberating the inflammable hydrogen gas. The metal (M) is:A. KB. CaC. MgD. Rb |
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Answer» Correct Answer - C Hydrogen is liberated when Mg reacts with hot water. Rb, K and Ca gives hydrogen gas even with cold water. `Mg+O_2toMgO , Mg+N_2toMg_3N_2` `Mg_3N_2+6H_2O to 3Mg(OH)_2 + 2NH_3 uarr` `Mg+2H_2O("hot")toMg(OH)_2+H_2` |
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| 25044. |
When conc. H2SO4 is added to dry KNO3, brown fumes are evolved. These fumes are of (a) SO2 (b) SO3 (c) N2O (d) NO2 |
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Answer» When conc. H2SO4 is added to dry KNO3, brown fumes are evolved. These fumes are of NO2. |
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| 25045. |
When orthoboric acid is heated strongly, it gives (a) B2O3 (b) H2B4O7 (c) HBO2 (d) B |
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Answer» When orthoboric acid is heated strongly, it gives B2O3 . |
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| 25046. |
Pyrene (a fire extinguisher)is (a) SiCl4 (b) CCl4 (c) GeCl4 (d) SbCl5 |
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Answer» Pyrene (a fire extinguisher)is CCl4 . |
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| 25047. |
Calculate the heat of reaction of the following reaction : C6H12O6(s) + 6O2(g) → 6CO2(g) + 6H2O(g) ; ΔH = ? C(graphite) + O2(g) → CO2(g); ΔH = -395.0 kJ ....(1)H2(g) + O(g) → H2O(l); ΔH = -269.5 kJ ....(2)6C(graphite) + 6H2(g) + O2(g) → C6H12O6; ΔH = -1169.8 kJ .....(3) |
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Answer» Multiplying equation (1) and (2) each by 6 reversing (3), we get, 6C(graphite) + 6O2(g) → 6CO2(g); ΔH = -2370 kJ …(4) 6H2(g) + 3O2(g) → 6H2O(l); ΔH = -1616.4 kJ … (5) C6H12O6(s) → 6C(graphite) + 3O2(g) ; ΔH = +1169.8 kJ …..(6) Adding (4), (5) and (6), C6H12O6(s) +6O2(g) → 6CO2(g) +6H2O(g) ; ΔHg (C6H12O6) = -2370.0 – 1616.4 + 1169.8 = -2816.6 k |
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| 25048. |
Which one has the lowest boiling point ?(a) NH3 (b) PH3 (c) AsH3 (d) SbH3 |
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Answer» (b) The order of boiling points of the group 15 hydrides is : BiH3 > SbH3 > NH3 > AsH3 > PH3 |
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| 25049. |
Most acidic oxide among the following is –(a) N2O5 (b) P2O5 (c) N2O4 (d) As2O3 |
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Answer» (a) Oxide in which central atom has higher charge and more electronegativity is more acidic, i.e. N2O5 > N2O4 > P2O5 > As2O3 . |
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| 25050. |
Which of the following species has the highest dipole moment?(a) NH3 (b) PH3 (c) AsH3 (d) SbH3 |
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Answer» (a) Order of dipole moment NH3 > PH3 > AsH3 > SbH3 (Based upon electronegativity) |
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