1.

Calculate the heat of reaction of the following reaction : C6H12O6(s) + 6O2(g) → 6CO2(g) + 6H2O(g) ; ΔH = ? C(graphite) + O2(g) → CO2(g); ΔH = -395.0 kJ  ....(1)H2(g) + O(g) → H2O(l); ΔH = -269.5 kJ ....(2)6C(graphite) + 6H2(g) + O2(g) → C6H12O6; ΔH = -1169.8 kJ .....(3)

Answer»

Multiplying equation (1) and (2) each by 6 reversing (3), we get, 

6C(graphite) + 6O2(g) → 6CO2(g); ΔH = -2370 kJ …(4) 

6H2(g) + 3O2(g) → 6H2O(l); ΔH = -1616.4 kJ … (5) 

C6H12O6(s) → 6C(graphite) + 3O2(g) ; ΔH = +1169.8 kJ …..(6) 

Adding (4), (5) and (6), 

C6H12O6(s) +6O2(g) → 6CO2(g) +6H2O(g)

ΔHg (C6H12O6) = -2370.0 – 1616.4 + 1169.8 = -2816.6 k



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