1.

500ml of 0.1M HCOOH (formic acid) is mixed with 1500ml of 0.05M H2SO4 solution calculate pH of the solution

Answer»

In formic acid solution, millimole of COOH2 = Molarity x Volume(ml)
                                              = 0.1 x 500
                                              = 50
  So, Millimole of H+ in COOH2 = 2 x 50
In H2SO4 solution, millimole of H2SO4 = 0.05 x 1500
                                                        = 75
  So, millimole of H+ in H2SO4 = 2 x 75
Total millimole of H+ = (100+150) = 250
Total volume of mixture = 1500+500 = 2000ml.
final concentration of H+ = 250/2000
                                   0.125 M
So, final pH= -log[H+] = -log(0.125)

= 0.90



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