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An object is placed at a distance of 10 cm from a convex mirror of focal length 15 cm. Find the position and nature of the image. |
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Answer» Given f = +15 cm, u = – 10 cm, v = ? By mirror formula 1/v + 1/10 = 1/15 …. (i) Put the given values in eq. (i) with their sign conventions 1/v - 1/10 = 15 We get, v = 6 cm image is formed at 6 cm away from the mirror on right side i.e. virtual m = –v/u = –6/-10 = 0.6 Here, m is less than unity and also positive so image will be diminished, erect and virtual in nature. |
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