Saved Bookmarks
| 1. |
A ball is thrown vertically upwards with velocity 10 m/s from a trolley moving horizontally with velocity of 8 m/s. A person standing on ground observe its motion. The range observed by him is (g = 10m/s). |
|
Answer» Vertical velocity of ball uy=v1 Horizontal velocity of ball ux=v2 Horizontal range of projectile R=2uxuy/g ⟹ R= 2v1v2/g = 2* 10*8/ 10= 16 m Horizontal velocity of ball is trolley S = uHt R = uHt Sg = ugt - \(\frac12\)agt2 Sy = 0 uyt - \(\frac12\)gt2 = 0 uyt = \(\frac12\)gt2 uy = \(\frac{gt}2\) t = \(\frac{2u_y}g\) t = \(\frac{2\times10}{10}\) t = 2 sec Range observed by him is Given uH = 8m/s R = uHt R = 8 x 2 R = 16 m |
|