This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 11151. |
Which of the following short cuts is used to move cursor one word right while editing data in a cell in MS-Excel?1. Ctrl+Shift+←2. Ctrl+→3. Ctrl+Shift+→4. Ctrl+Shift |
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Answer» Correct Answer - Option 2 : Ctrl+→ The correct answer is Ctrl+→
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| 11152. |
What is the key combination to print a document?1. ctrl + X2. ctrl + Z3. ctrl + C4. ctrl + P |
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Answer» Correct Answer - Option 4 : ctrl + P The correct answer is ctrl + P.
Word shortcut keys
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| 11153. |
While writing a function in Excel, it should start with _____.1. =2. |
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Answer» Correct Answer - Option 1 : = The correct answer is "=".
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| 11154. |
The default orientation of the page is in Word processor. a. Landscape b. Print Layout c. Portrait d. Normal |
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Answer» The correct option is c. Portrait. The default orientation of a page in Writer is Portrait. Whenever a new word document is opened on the computer, the portrait orientation is the default orientation of the new word document. Portrait and landscape orientations are the two types of orientation modes available. |
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| 11155. |
Which of the following options is used to view the page or make adjustments before any document gets printed in MS-Word?1. Print Preview 2. Outline 3. Web Layout 4. Draft |
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Answer» Correct Answer - Option 1 : Print Preview The correct answer is Print Preview.
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| 11156. |
Which of the following is a correct orientation while printing a document?1. Margin2. Landscape3. Collated4. Picture |
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Answer» Correct Answer - Option 2 : Landscape The correct answer is Landscape.
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| 11157. |
While printing an MS Word document, we can set the number of copies to be printed. By default, you will have ______ copy/copies of the document.1. one2. two3. three4. eight |
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Answer» Correct Answer - Option 1 : one The correct answer is One.
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| 11158. |
An IP version 4 address is ______ long.1. 32 bits2. 32 bytes3. 64 bits4. 16 bytes |
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Answer» Correct Answer - Option 1 : 32 bits The correct answer is 32 bits.
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| 11159. |
Which of the following notations is generally used to represent an IP address in an understandable format?1. Binary notation2. Hexadecimal notation3. Octal notation4. Dotted-decimal notation |
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Answer» Correct Answer - Option 4 : Dotted-decimal notation The correct answer is Dotted-decimal notation.
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| 11160. |
Match the following:Lift ProjectSupply drinking water to(A) Kanwar Sen Lift Canal(i) Nagaur(B) Gandheli - Sahawa lift Project(ii) Jodhpur(C) Rajiv Gandhi Lift Canal(iii) Churu(D) Gajner Lift Project(iv) Bikaner1. (A) - (i), (B) - (iv), (C) - (iii), (D) - (ii)2. (A) - (ii), (B) - (i), (C) - (iv), (D) - (ii)3. (A) - (iv), (B) - (iii), (C) - (ii), (D) - (i)4. (A) - (iii), (B) - (ii), (C) - (i), (D) - (iv) |
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Answer» Correct Answer - Option 3 : (A) - (iv), (B) - (iii), (C) - (ii), (D) - (i) The correct answer is (A) - (iv), (B) - (iii), (C) - (ii), (D) - (i).
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| 11161. |
In the classic film 'Citizen Kane', Orson Welles portrays William Randolph Hearst. _____ The failures that are often not seen outside of a very private circle of friends and family of well known people, usually include shyness and loneliness as in the case of Hearst. A) His famous portrayal of this well known man revealed to the public not only his successes but also some of his failures. B) All people can become as famous as Hearst if they want to but one must always be careful. C) Films give people an idea of the lives of rich people which they will never he able to see in real life. D) Private lives can be best revealed when actors as famous as Orson Wells, play these roles. E) Orson Wells received an Academy Award for this role |
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Answer» Correct option is A) His famous portrayal of this well known man revealed to the public not only his successes but also some of his failures. |
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| 11162. |
____ As a student she studied dancing in the University of Michigan. Then in 1982, she recorded her first successful song: 'Everybody". A) Madonna has been interested in singing all her life, as can be seen from her early student years. B) The famous pop singer Madonna, was born in Bay City, Michigan in the U.S.A. C) The University of Michigan is where Madonna started her singing career. D) Recording 'Everybody' started her musical career. E) Madonna got married after making her first hit song |
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Answer» Correct option is B) The famous pop singer Madonna, was born in Bay City, Michigan in the U.S.A |
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| 11163. |
Mary Shelly, the wife of the well known romantic poet, wrote 'Frankenstein. _____ This was probably due to the strange subject of life from non-living matters which was a subject greatly discussed in her circle of acquaintances at those times. A) When she had it published in 1818 she did so anonymously. B) Frankenstein was later made into famous movies. C) The classic horror character of Frankenstein is still famous today. D) She wrote this book as a fantasy. E) The public liked the book and it is still enjoyed today. |
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Answer» Correct option is A) When she had it published in 1818 she did so anonymously. |
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| 11164. |
In the old Roman calendar the month of March was considered the first month of the year. _____ This was later changed to our present calendar in which January is the first month of the year. The Scottish were the first people of the British Isles to change to this new calendar in 1599. A) January was named for the legendary Janus. B) The British were not very interested in the calendar during these years. C) No one knows who changed the calendar to the way it is now. D) In fact, the first day of the year was the 25th of March. E) The Romans preferred the spring to the winter months. |
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Answer» Correct option is D) In fact, the first day of the year was the 25th of March |
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| 11165. |
Which of the following is/are correctly matched?LokdevtaBirth Place1. Teja JiKhadnaal in the Nagaur district2. Pabu JiPhalodi in the Jodhpur district3. Veer Kalla JiMerta in the Nagaur district.1. 1 Only2. 1 and 2 Only3. 1 and 3 Only4. 1, 2 and 3 |
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Answer» Correct Answer - Option 4 : 1, 2 and 3 The correct answer is 1, 2 and 3. The table below is correctly matched:
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| 11166. |
Match the following:List - IList - II(a) 9th month of the Islamic calendar(i) Prophet Mohammad's birthday(b) Moharram(ii) Bakrid(c) 10th day of 12th month of the Islamic calendar(iii) Ramdan(d) Milad-un-Nabi(iv) Shiyas1. (a) - (ii), (b) - (i), (c) - (iv), (d) - (iii)2. (a) - (iii), (b) - (iv), (c) - (ii), (d) - (i)3. (a) - (i), (b) - (iv), (c) - (ii), (d) - (iii)4. (a) - (iv), (b) - (ii), (c) - (i), (d) - (iii) |
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Answer» Correct Answer - Option 2 : (a) - (iii), (b) - (iv), (c) - (ii), (d) - (i) The correct answer is (a) - (iii), (b) - (iv), (c) - (ii), (d) - (i).
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| 11167. |
Diphenyl Ketone does not show tautomerism. Why? |
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Answer» Diphenyl Ketone show tautomerism because it contains 2-α H atom. |
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| 11168. |
If A = \(\begin{bmatrix}-3\\5\\2\end{bmatrix}\) and B = \(\begin{bmatrix}1&6&-4\end{bmatrix}\), then verify that (AB)' = B'A'. |
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Answer» We have A = \(\begin{bmatrix}-3\\5\\2\end{bmatrix}\) and B = \(\begin{bmatrix}1&6&-4\end{bmatrix}\). ⇒ A' = \(\begin{bmatrix}-3&5&2\end{bmatrix}\) and B' = \(\begin{bmatrix}1\\6\\-4\end{bmatrix}\) Now, AB = \(\begin{bmatrix}-3\\5\\2\end{bmatrix}\)\(\begin{bmatrix}1&6&-4\end{bmatrix}\) = \(\begin{bmatrix}-3&-18&12\\5&30&-20\\2&12&-8\end{bmatrix}\). Therefore, (AB)' = \(\begin{bmatrix}-3&5&2\\-18&30&-20\\12&-20&-8\end{bmatrix}\). Now, B'A' = \(\begin{bmatrix}1\\6\\-4\end{bmatrix}\)\(\begin{bmatrix}-3&5&2\end{bmatrix}\) = \(\begin{bmatrix}-3&5&2\\-18&30&-20\\12&-20&-8\end{bmatrix}\) = (AB)' Hence, (AB)' = B'A' |
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| 11169. |
If \(\vec a, \vec b\) are vectors such that \(|\vec a + \vec b| = \sqrt {29}\) and \(\vec a \times (2\hat i + 3\hat j + 4\hat k) = (2\hat i + 3\hat j + 4\hat k) \times \vec b\) then possible value of \((\vec a + \vec b).(-7\hat i + 2\hat j + 3\hat k)\) is |
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Answer» Correct Answer - Option 3 : 4 Concept:
Calculation: Given: \(\rm\vec a × (2\hat i + 3\hat j + 4\hat k) = (2\hat i + 3\hat j + 4\hat k) × \vec b\) ⇒ \(\rm\vec a × (2\hat i + 3\hat j + 4\hat k) - (2\hat i + 3\hat j + 4\hat k) × \vec b=0\) ⇒ \(\rm\vec a × (2\hat i + 3\hat j + 4\hat k) + \vec b × (2\hat i + 3\hat j + 4\hat k) =0\) ⇒ \(\boldsymbol{\rm(\vec a + \vec b) × (2\hat i + 3\hat j + 4\hat k) =0}\) It means the \(\rm\vec a + \vec b\) and \(\rm2\hat i + 3\hat j + 4\hat k\) are collinear vectors. ∴ \(\rm\vec a + \vec b = \left|\vec a + \vec b\right| × {2\hat i + 3\hat j + 4\hat k\over \left|2\hat i + 3\hat j + 4\hat k\right|}\) ⇒ \(\rm\vec a + \vec b = \sqrt{29}× {2\hat i + 3\hat j + 4\hat k\over\sqrt{29}}\) ⇒ \(\boldsymbol{\rm\vec a + \vec b = 2\hat i + 3\hat j + 4\hat k}\) \(\rm (\vec a + \vec b)\cdot(-7\hat i + 2\hat j + 3\hat k) = \left(2\hat i + 3\hat j + 4\hat k\right)\cdot\left(-7\hat i + 2\hat j + 3\hat k\right)\) ⇒ \(\rm (\vec a + \vec b)\cdot(-7\hat i + 2\hat j + 3\hat k) = \left(2\times(-7) + 3\times2 + 4\times3\right)\) ⇒ \(\rm (\vec a + \vec b)\cdot(-7\hat i + 2\hat j + 3\hat k) = \left(-14 +6 + 12\right)\) ⇒ \(\boldsymbol{\rm (\vec a + \vec b)\cdot(-7\hat i + 2\hat j + 3\hat k) = 4}\) |
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| 11170. |
If \(\vec{a}, \vec{b}\) and \(\vec{a}+\vec{b}\) are vectors of magnitude α then the magnitude of the vector \(\vec{a}-\vec{b}\) is1. \(\sqrt{2}\alpha\)2. \(\sqrt{3}\alpha\)3. 2α 4. 3α |
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Answer» Correct Answer - Option 2 : \(\sqrt{3}\alpha\) Concept: Let two vectors are \(\rm \vec {a}\) and \(\rm \vec {b}\) Magnitude of sum of \(\rm \vec {a}\) and \(\rm \vec {b}\): \(\rm \left|\vec a+\vec b\right| = \sqrt{a^2+b^2+2ab\cosθ}\) Magnitude of difference of \(\rm \vec {a}\) and \(\rm \vec {b}\): \(\rm \left|\vec a-\vec b\right| = \sqrt{a^2+b^2-2ab\cosθ}\) where a, b are magnitude of vectors \(\rm \vec a \text{ and } \vec b\); and θ is angle between them.
Calculation: Given: \(\rm \left|\vec a\right|=\alpha\text{, }\left|\vec b\right|=\alpha\text{ and }\left|\vec a+\vec b\right|=\alpha\) As we know, \(\rm \left|\vec a+\vec b\right| = \sqrt{a^2+b^2+2ab\cosθ}\) ⇒ \(\rm \alpha = \sqrt{\alpha^2+\alpha^2+2(\alpha)(\alpha)\cosθ}\) ⇒ \(\rm \alpha^2 = 2\alpha^2+2\alpha^2\cosθ\) ⇒ \(\rm -1=2\cosθ\) ⇒ \(\boldsymbol{\rm \cosθ=-\frac{1}{2}}\) Now, \(\rm \left|\vec a-\vec b\right| = \sqrt{a^2+b^2-2ab\cosθ}\) ⇒ \(\rm \left|\vec a-\vec b\right| = \sqrt{\alpha^2+\alpha^2-2(\alpha)(\alpha)\cosθ}\) \(∵ \cos θ = -\frac{1}{2}\) ⇒ \(\rm \left|\vec a-\vec b\right| = \sqrt{2\alpha^2-2\alpha^2 (\frac{-1}{2})}\) ⇒ \(\rm \left|\vec a-\vec b\right| = \sqrt{2\alpha^2+\alpha^2}\) ⇒ \(\boldsymbol{\rm \left|\vec a-\vec b\right| = \sqrt{3}\alpha}\) |
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| 11171. |
A force of 78 grams acts at the point (2, 3, 5), the direction ratios of the line of action being 2, 2, 1. The magnitude of its moment about the line joining the origin to the point (12, 3, 4) is:1. 242. 1363. 364. 0 |
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Answer» Correct Answer - Option 2 : 136 Concept:
Calculation: The direction ratios of the line of action of the force are 2, 2, 1. So the force vector is given by: \(\rm \vec F=78\frac{2\hat i+2\hat j+\hat k}{\sqrt{2^2+2^2+1^2}}\) ⇒ \(\rm \vec F=26\left(2\hat i+2\hat j+\hat k\right)\) Now, the vector joining the point of action (2, 3, 5) with the origin is: 2î + 3ĵ + 5k̂. The moment \(\rm \vec M\) of the force \(\rm \vec F\) about the origin = (2î + 3ĵ + 5k̂) × 26 (2î + 2ĵ + k̂) = 26(-7î + 8ĵ - 2k̂). The moment of this force about the line joining the origin to the point (12, 3, 4) will be component of the above moment along this line. The unit vector along this line is: \(\rm \frac{12\hat i+3\hat j+4\hat k}{\sqrt{12^2+3^2+4^2}}\) = \(\rm \frac{1}{13}\left(12\hat i+3\hat j+4\hat k\right)\). The required magnitude of the component of the moment along the given line is: \(|\rm 26\left(-7\hat i+8\hat j-2\hat k\right).\frac{1}{13}\left(12\hat i+3\hat j+4\hat k\right)|\). = |2(-84 + 24 - 12)| = |2(-72)| = 136. |
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| 11172. |
Mr. Sunil covers his upward journey at 55 km/h and downward journey at 45 km/h. Find his average speed.1. 35.5 km/h2. 45.5 km/h3. 49.5 km/h4. 39.5 km/h |
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Answer» Correct Answer - Option 3 : 49.5 km/h Given: Speed at upward journey = 55 km/h Speed at downward journey = 45 km/h Formula used: Average speed = Total distance/Total time Calculation: Let distance be 495 (LCM of 55 and 45) ⇒ (495 + 495)/[(495/55) + (495/45)] ⇒ 990/20 ⇒ 49.5 ∴ Average speed is 49.5 km/h |
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| 11173. |
A train x running at 74 km/h crosses another train y running at 52 km/h in the opposite direction in 12 seconds. If the length of y is two-thirds that of x, then what is the length of x (in m)?1. 2002. 1683. 2104. 252 |
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Answer» Correct Answer - Option 4 : 252 Given: A train x running at 74 km/h crosses another train y running at 52 km/h in the opposite direction in 12 seconds. The length of y is two-thirds that of x. Concept Used: When two trains crossing each other, their relative speed will be the sum of their speed. 1 km/h = (5/18) m/s Distance = Time × speed Calculation: Relative speed (74 + 52) = 126 km/h ⇒ 126 × (5/18) ⇒ 35 m/s Time taken to cross each other 12 second Total distance covered (12 × 35) = 420 m The length of y is two-thirds that of x Let, the length of the train x is a meter Accordingly, (a + (2a/3) = 420 ⇒ a = 420 × (3/5) ⇒ a = 252 ∴ The length of the train X is 252 m |
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| 11174. |
The ratio of the present age of Ravi and his wife is 8 : 5 and 6 years hence the ratio of their ages will be 12 : 8 If the ratio of their ages at the time of their marriage was 9 : 3, how many years ago were they married?1. 102. 243. 164. 215. None of the above/More than one of the above |
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Answer» Correct Answer - Option 4 : 21 Given: The ratio of the present age of Ravi and his wife is 8 : 5 and 6 years hence the ratio of their ages will be 12 : 8 If the ratio of their ages at the time of their marriage was 9 : 3 Calculation Let the age of Ravi and his wife in present be 8x and 5x Age 6 years from now = 8x + 6 and 5x + 6 But (8x + 6) ÷ (5x + 6) = 12 ÷ 8 64x + 48 = 60x + 72 ⇒ 4x = 72 – 48 ⇒ 4x = 24 ⇒ x = 6 Their current age = 8 × 6 = 48 and 5 × 6 = 30 Let they married x years ago Age at married = 48 – x and 30 – x But (48 - x) ÷ (30 - x) = 9 ÷ 3 ⇒ 270 – 9x = 144 – 3x ⇒ 6x = 126 ⇒ x = 21 ∴ They married 21 years ago |
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| 11175. |
The ratio of the present ages of Ram and Sham is 7 : 11. Six years hence, the ratio of their ages will be 2 : 3. What is the difference between the present ages?1. 422. 243. 664. 325. 52 |
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Answer» Correct Answer - Option 2 : 24 Given: The ratio of present ages of Ram and Sham is 7 : 11 Ratio of their ages six years hence is 2 : 3 Calculation: Let the present age of Ram be 7x Let the present age of Sham be 11x According to the question (7x + 6)/(11x + 6) = 2/3 ⇒ 21x + 18 = 22x + 12 ⇒ 18 – 12 = 22x – 21x ⇒ x = 6 ⇒ Ram’s present age = 7 × 6 = 42 ⇒ Sham’s present age = 11 × 6 = 66 Difference between their present age = 66 – 42 = 24 ∴ The difference between their present age is 24. |
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| 11176. |
निम्नलिखित अनुक्रमों में अगला पद ज्ञात कीजिए। \[ \begin{array}{l} \frac{1}{6}, \frac{1}{3}, \frac{1}{2}, \ldots \ldots \\ \frac{1}{6}, \frac{1}{3} \cdot \frac{2}{3}, \ldots . \end{array} \] |
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Answer» (i) 1/6, 1/3, 1/2, .... is an A.P. common difference is 1/6. d = 1/3 - 1/6 = 2-1/ 6 = 1/6 or d = 1/2 - 1/3 = \(\frac{3-2}6\) = 1/6 \(\therefore\) a4 = a3 + d = \(\frac12 + \frac16 =\frac{3+1}6\) = 4/6 = 2/3 (ii) a1 = 1/6, a2 = 1/3, a3 = 2/3 \(\frac{a_2}{a_1}=\cfrac{\frac13}{\frac{1}{6}}\) = \(\frac63=2\) \(\frac{a_3}{a_2}=\cfrac{\frac23}{\frac{1}{3}}\) = 2 \(\therefore\) 1/6, 1/3, 2/3., is a G.P. whose common ratio is 2. a4 = a3r = 2/3 x 2 = 4/3 |
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| 11177. |
If \( a, b, c \) are in A.P and \( a^{2}, b^{2}, c^{2} \) are in H. P then \( b^{2}= \) A) \( \frac{c a}{2} \) B) \( -2 ca \) C) \( \frac{-c a}{2} \) D) \( 2 ca \) |
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Answer» Correct option is C) \(\frac{-ca}2\) a, b, c are in A.P. \(\therefore b = \frac{a + c}2\) ....(1) \(\because\) a2, b2, c2 are in H.P. \(\therefore \frac1{a^2}, \frac 1{b^2}, \frac 1{c^2}\) are in A.P. \(\therefore \frac1{b^2 } - \frac1{a^2} = \frac1{c^2} - \frac1{b^2}\) ⇒ \(\frac{a^2 -b^2}{a^2b^2} = \frac{b^2 - c^2}{b^2c^2}\) ⇒ \(\frac{(a -b)(a +b)}{a^2} = \frac{(b - c)(b + c)}{c^2}\) ⇒ \(\frac{(a -b)(a +b)}{a^2} = \frac{(a - b)(b + c)}{c^2}\) \(\begin{pmatrix}\because \text{a, b,c are in A.P.}\\\therefore b -a = c-b\\⇒a -b = b-c\end{pmatrix}\) ⇒ \(\frac{a +b}{a^2} = \frac{b +c}{c^2}\) ⇒ \(a^2 (b + c) = c^2(a + b)\) ⇒ \(a^2b + a^2c = c^2 a + c^2b\) ⇒ \(a^2b - c^2b + a^2c - c^2a = 0\) ⇒ \(b(a^2 - c^2) + ac(a - c) = 0\) ⇒ \(b(a -c)(a + c) + ac(a -c) = 0\) ⇒ \((a -c) (b(a +c) + ac) = 0\) either \(a -c = 0\, or\, b(a + c) + ac =0\) If \(a- c = 0\) ⇒ \(a = c\) which is possible when a = b = c but a, b, c are different \(\therefore b(a +c) + ac = 0\) \(b(2b) + ac = 0 \) (From(i)) ⇒ \(b^2 = \frac{-ac}2\) |
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| 11178. |
एक दूधवाले के पास एक केन में 75 ली0 दूध है तथा दूसरे केन में 45 ली0 दूध है। उसके पात्र की अधिकतम क्षमता क्या होगी, जो दोनों केनों के दूध की मात्रा को माप सके?A. 1 litreB. 5 litreC. 15 litresD. 25 litres |
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Answer» ( c) 75 litre, 45 litre for maximum capacity take HCF ( अधिकतम क्षमता के लिए म. स. ले) (75,45)(=15 |
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| 11179. |
The common difference of the Arithmetic progression 8, 5 ,2 , -1 is (A) \( -3 \) (B) \( -2 \) (C) 3 (D) 8 |
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Answer» Common difference is, d = - 3 d = 5 - 8= - 3 2 - 5 = -3 -1 - 2 = -3 -4 - (-1) = -4 + 1 = - 3 So, d = - 3 |
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| 11180. |
tan^-11/2+tan^-11/3= |
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Answer» Arctan(1/2)+ Arctan (1/3) =Arctan {(1/2+1/3)/1-1/2×1/3)} =Arctan(5/6÷5/6) =Arctan 1= π/4 |
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| 11181. |
If the radius of a circle is diminished by 10%, then its area is diminished by |
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Answer» Let the radius of the circle be r Then area of cirlce =πr 2 Given that radius of the circle is diminished by 10% Hence the new radius =r−(10%ofr)=90%ofr= 10 9r Area of the new circle =π( 10 9r ) 2 = 100 81 πr 2 Change in area πr 2 − 100 81 πr 2 = 100 19 πr 2 =0.19πr 2 “Percentage of area diminished is 19”% Let the radius of the circle be r Then area of circle = πr2 Given that radius of the circle is diminished by 10% Hence the new radius = r − (10% of r) = 90% of r = 9r/10 Area of the new circle = π (9r/10)2 = 81/100 πr2 Change in area πr2 − 81/100 πr2 = 19/100 πr2 = 0.19 πr2 Percentage of area diminished is 19%. |
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| 11182. |
If Mayank doubles the selling price of an item, the profit becomes 4 times. Find the original profit percent (before increasing the selling price)A. 50%B. 100%C. 125%D. 25%1. A2. B3. C4. D |
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Answer» Correct Answer - Option 1 : A Given: Mayank doubles the selling price of an item then profit becomes 4 times. Formula Used: Profit percentage = {(Selling price – Cost price)/Cost price}×100 Calculation: Let the initial cost price and selling price be CP, SP. Let initial profit be P. As 1st time Profit P = (SP – CP) ----(1) When selling price be doubled 2SP Then profit in 2nd case P = (2SP – CP) ----(2) As given profit in 2nd case is 4 times of 1st ⇒ (2SP – CP) = 4(SP – CP) ⇒ 2SP – CP = 4SP – 4CP ⇒ 3CP = 2SP ⇒ SP/CP = 3x/2x Profit percentage = {(Selling price – Cost price)/Cost price}×100 ⇒ The profit % = (3x – 2x)/2x = (x/2x)×100 = 50% ∴ The initial profit % is 50% |
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| 11183. |
If selling price is tripled, the profit becomes four times. Find the profit percentage.1. 180%2. 200%3. 220%4. 190%5. 210% |
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Answer» Correct Answer - Option 2 : 200% Given: Selling price is triple, the profit four time Formula used: Percentage profit = [(selling price – cost price)/cost price] × 100 Calculation: Let the C.P be Rs.100 and S.P be Rs.x, Then The profit is (x-100) Now the S.P is triple, then the new S.P is 3x New profit is (3x-100) Now as per the given condition; => 4(x - 100) = 3x - 100 By solving, we get x = 300 Then the Profit percent = [(300-100)/100] × 100 = 200 ∴ The profit percentage is 200%. |
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| 11184. |
Ken borrowed $2000 from Sam at 8% per annum. After 6 year he cleared the amountby giving $2600 cash and a watch. Find the cost of the watch |
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Answer» let us find the interest for 6 years , |
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| 11185. |
दो संख्याओं का गुणनफल 1280 है तथा म0स0 8 है तो उन संख्याओं का ल0 स0 क्या होगा?A. 160B. 150C. 120D. 140 |
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Answer» Correct Answer - A दो संख्याओं का गुणनफल `=1280` HCF `=8` LCM `=1280/8=160` |
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| 11186. |
दो संख्याओं का म0स0 तथा ल0 स0 क्रमशः 15 तथा 300 है। यदि एक संख्या 60 है तो दूसरी संख्या ज्ञात करें?A. 50B. 75C. 65D. 100 |
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Answer» Correct Answer - B `HCF=15` `LCM=300` 1st number `=60` माना कि दूसरी संख्या `=x` HCF `xx` LCM `=` 1st Number `xx` 2nd number `15xx300=60xx x` `x=75` `:.` अन्य संख्या `=75` |
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| 11187. |
If x = sin–1(sin10) and y = cos–1(cos10), then y – x is equal to :(1) 10 (2) 0 (3) π (4) 7π |
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Answer» The correct option (3) π Explanation: x = 3p – 10 ; y = 4π – 10 ⇒ y – x = π |
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| 11188. |
If the selling price is tripled, the profit goes up to 5 times, Find the profit.1. 80%2. 100%3. 125%4. 150% |
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Answer» Correct Answer - Option 2 : 100% Given: Selling price gets “tripled” Profit becomes 5 times Formula Used: Profit % = 100 × (Profit/Cost price) Calculation: Let the initial Selling price is SP Now Selling Price is tripled = 3SP Profit becomes 5 times of it ⇒ (3SP – CP) = 5 × (SP – CP) ⇒ 2SP = 4CP ⇒ SP/CP = 2/1 Profit % = 100 × (2 - 1)/1 = 100% ∴ The profit is 100%. |
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| 11189. |
If the circles x2 + y2 – 16x – 20y + 164 = r2 (x – 4)2 + (y – 7)2 = 36 intersect at two distinct points, then : (1) r > 11 (2) 0 < r < 1 (3) 1 < r < 11 (4) r = 11 |
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Answer» The correct option (3) 1 < r < 11 Explanation: (x – 8)2 + (y – 10)2 = r2 ; (x – 4)2 + (y – 7)2 = 36 C1(8, 10); C2(4, 7) : |r – 6| < C1C2 < |r| + 6 ⇒ |r – 6| < 5 < |r| + 6 ⇒ r ∈ (1, 11) |
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| 11190. |
दो संख्याएं 3:4 के अनुपात में है। यदि उनका म0स0 4 है तो उनका ल0 स0 ज्ञात करें।A. 48B. 42C. 36D. 24 |
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Answer» (a) Let number be ( माना कि संख्याएँ) =x,y x:y =3:4 (given ) HCF=4 `therefore` Number are= x=`4xx3`=12 y=`4xx4`=16 LCM of (12,16) `=4xx4`=48 |
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| 11191. |
Kavita sold a mobile phone at the price of Rs.1950 and made a loss of 25%. At what price will she have to sell it to get a profit of 30% ?1. Rs.26002. Rs.27803. Rs.30004. Rs.3380 |
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Answer» Correct Answer - Option 4 : Rs.3380 Given: SP of mobile phone = Rs. 1950 Loss = 25% Formula used: CP = (100 × SP)/(100 – L%) SP = [CP × (100 + P%)]/100 Here, SP, CP, P and L are selling price, cost price, profit and loss respectively Calculation: CP = (100 × SP)/(100 – L%) ⇒ (100 × 1950)/(100 – 25) ⇒ 2600 Now, SP = [CP × (100 + P%)]/100 ⇒ [2600 × (100 + 30)]/100 = 3380 ∴ The required selling price of the mobile phone is Rs 3380 |
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| 11192. |
The profit made by selling an article for Rs. 8,800 is equal to the amount of loss incurred on selling the same article for Rs. 7,200. What will be the profit per cent, if it was sold for Rs. 9,600?1. 15%2. 25%3. 20%4. 18% |
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Answer» Correct Answer - Option 3 : 20% Given: The profit made by selling an article for Rs. 8,800 is equal to the amount of loss incurred on selling the same article for Rs. 7,200 Formula used: Profit = selling price - cost price Profit% = Profit × 100/cost price. Calculation: let cost price be Rs. X According to the question: (8800 - X) = (X - 7200) ⇒ 16000 = 2X ⇒ X = 8000 if sp = 9,600 Then, Profit = selling price - cost price ⇒ Profit = 9600 - 8000 = Rs.1600 ∴ Profit % = Profit × 100/cost price ⇒ Profit = (1600 × 100)/8000 = 20 % ∴ The profit percent is 20 %
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| 11193. |
23 का न्यूनतम गुणक ज्ञात करें, जिससे 18,21 तथा 24 से भाग देने पर क्रमशः 7,10 तथा 13 शेष बचें?A. 3013B. 3024C. 3002D. 3036 |
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Answer» (a) 18-7=11 21-10=11 24-13=11 take LCM of (18,21 ,24)`implies 9xx2xx7xx4=504` `implies` required number = (504k-11) which is divided by 23. `therefore` For `(504k-11)/(23)`, Remainder should be zero ( शेषफल शुन्य होना चाहिए ) Put minimum value of k so that it completely divides 23. `implies` at k=6, 504k-11=3013 completely divisible by 23 (23 से पूर्णतः विभाजित है ) `therefore` requried number is ( अभीष्ट संख्या )=3013 |
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| 11194. |
दो संख्याओं का गुणनफल 4107 है। यदि उनका म0 स0 37 है तो बड़ी संख्या क्या है?A. 185B. 111C. 107D. 101 |
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Answer» ( b) HCF =37 `therefore` Let the no. are ( माना कि संख्याएँ ) `=37x & 37y` given, 37x `xx`37y=4107 =xy=3 possible factors of xy ( xy से संभवित गुणक ) =(1,3) `therefore` numbers are (37, 37`xx`3) `=(37,111) ` greater number is (बड़ी संख्या )=111 |
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| 11195. |
What do you mean by financial institutions? |
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Answer» The institution that undertakes economic transactions like accepting deposits and giving loans are called financial institutions. |
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| 11196. |
The recently released book 'Dastak Dete Rahenge' is a compilation of speeches by-1. Lalu Prasad Yadav2. Nitish Kumar3. Shashi Tharoor4. Dr. Jagannath Mishra |
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Answer» Correct Answer - Option 4 : Dr. Jagannath Mishra The correct answer is Dr. Jagannath Mishra.
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| 11197. |
RBI was nationalized in: a) 1935 b) 1945 c) 1947 d) 1949 |
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Answer» Correct option: d) 1949 |
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| 11198. |
Why are banks classified differently though they basically perform the same functions? |
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Answer» Banks differ in their operations, though all of them basically perform the same functions. Based on the operations, banks are classifieds commercial banks, co-operative banks, development banks and specialized banks. |
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| 11199. |
Which river basin has the highest total replenishable ground water resources?1. Periyar2. Ganga3. Krishna4. Brahmaputra |
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Answer» Correct Answer - Option 2 : Ganga The correct answer is Ganga.
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| 11200. |
The data collection for national income estimation is conducted in India by-(a) The Finance Ministry of the Government of India(b) The RBI(c) The NSSO (National Sample Survey Organization)(d) None of these |
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Answer» (c) The NSSO (National Sample Survey Organization) |
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