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23 का न्यूनतम गुणक ज्ञात करें, जिससे 18,21 तथा 24 से भाग देने पर क्रमशः 7,10 तथा 13 शेष बचें?A. 3013B. 3024C. 3002D. 3036 |
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Answer» (a) 18-7=11 21-10=11 24-13=11 take LCM of (18,21 ,24)`implies 9xx2xx7xx4=504` `implies` required number = (504k-11) which is divided by 23. `therefore` For `(504k-11)/(23)`, Remainder should be zero ( शेषफल शुन्य होना चाहिए ) Put minimum value of k so that it completely divides 23. `implies` at k=6, 504k-11=3013 completely divisible by 23 (23 से पूर्णतः विभाजित है ) `therefore` requried number is ( अभीष्ट संख्या )=3013 |
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