Explore topic-wise InterviewSolutions in .

(a) The humanistic study of language and literature

Chandragupta Maurya was a benevolent despot.

(a) Megasthanes

The reverential title of 'The Liberator' had been earned by Ashoka.

When Alexander invaded India, Taxila was ruled  Ambhi.

(b) A study about the history and origin of a word

(b) A study about the history and origin of a word

The original Buddhist religious texts had been written in Pali.

Ashoka has been particularly Influenced by the Buddhist monk Upagupta.

(d) Bhadrabahu

(c) believed in the theory of Karm

(d) Mahavibhasha Sutra

The proceedings of the Third Buddhist Council led to the issue of Edic Sarnath.

The Buddhist Doctrines were written in Pali.

Ashoka was much influenced by Buddhist monk called Upagupta.

The first Buddhist Council was held at Rajagriha.

(b) Vasumitra

Given:

Distance = 4 km

Formula used:

Distance = {(Speed1 × Speed2)/(Speed1 - Speed2)} × time difference

Calculation:

Let the speed be 'S'.

Distance

⇒ Distance = {[S × (S + 2)]/2} × (10/60)

⇒ 4 = {[S × (S + 2)]/2} × (10/60)

⇒ S² + 2S = 48

⇒ S = 6, -8

Speed can never be negative

⇒ S = 6 km/h

∴ The speed is 6 km/h.

(d) Kanishka

Correct Answer is Rumtek

Given:

The cost price of the article A is 20% more than that of B.

 A is sold for Rs. 1,800 at a loss of 20%

Calculation:

Let cost price of B be Rs.a.

Cost price of A = Rs.120a/100

 A is sold for Rs. 1,800 at a loss of 20%

⇒ Cost price of A is 1800 × 100/80

Accordingly,

120a/100 = 1800 × 100/80

⇒ a = Rs.1875

Cost price of A = 1875 × 120/100 = Rs.2250

Total cost price of A and B = 2250 + 1875 = Rs.4125

Total selling price = 4125 × 120/100 = Rs.4950

∴ Selling price of B = 4950 - 1800 = Rs.3150

Given:

Selling price = Rs. 36,000

Loss % = 10%

Profit % = 15%

Formula used:

S.P. = C.P. × (100 – L%)/100

S.P. = C.P. × (100 + P%)/100

Where

S.P. → Selling price

CP → Cost price

L% → Loss %

P% ⇒ Profit %

Calculations:

S.P. = C.P. × (100 – L%)/100

So, CP = (SP × 100)/(100 – L%)

The cost price = (36000 × 100)/(100 – 10) = 36000 × (100/90)

⇒ CP = 40000

For 15% profit

S.P. = C.P. × (100 + P%)/100

⇒ S.P. = 40000 × (100 + 15)/100 = Rs. 46,000

∴ The required selling price of the product is Rs. 46,000.

Given:

Fruit vendor bought bananas at the rate of 6 bananas for Rs. 5 and sold them at the rate of 4 bananas for Rs. 3

Formula used:

Loss percent = (Loss/CP) × 100

Calculation:

Number of bananas bought = LCM of (6 and 4) = 24

C.P = (5/6​) × 24 = Rs. 20

S.P = (3/4) × 24 = Rs. 18

Loss = 20 – 18 = Rs. 2

Loss percent = (2/20) × 100 = 10%

Given:

Selling price = Rs.17000

Loss % = 17%

Formula:

Selling price = cost price × (100 - loss %)/100

Calculation:

Cost price = 17000 × 100/85 = Rs.20000

∴ Profit percentage = (20448 - 20000)/20000 × 100 = 2.24%

The rational no between 2/3 and 1/4 are 4/12 , 5/12 , 6/12 , 7/12 .

Given:

The selling price of a book = Rs. 24

Loss = 20% of the price of a book

New selling price of a book = Rs. 27

Formula used:

Gain or loss percent = (Loss or gain/Cost price) × 100

Concept used:

Profit = Selling Price – Cost Price

Loss = Cost Price – Selling Price

Calculation:

Let the cost price of a book is Rs.x 

Loss = 20% of the price of a book

Loss = 20% of x = x/5

selling price of a book = x - x/5 = 4/5x

According to question

⇒  4/5x  =  Rs. 24

⇒  x  =  Rs. 30

New selling price of a book = Rs. 27

∴  Loss = 30 -27 = Rs. 3 

Given:

Investment of M = ₹ 10000

Investment of N = ₹ 12000

Investment of O = ₹ 15000

Time of investment = 1 year

Concept used:

Loss = Investment × Time period

Calculation:

Loss ratio = 10000 : 12000 : 15000

⇒ Loss ratio = 10 : 12 : 15

Total Loss = (10 + 12 + 15) = 74000

⇒ 37 = 74000

Loss share of M = (74000/37) × 10

⇒ 20000

∴ The loss share of M is ₹ 20000.

Calculation∶

The series follows following pattern

1 × 0.5 = 0.5

0.5 × 1 = 0.5

0.5 × 2 = 1

1 × 4 = 4

4 × 8 = 32

32 × 16 = 512

Calculation:

The series follows the following pattern

22 + 1² = 23

23 + 2² = 27

27 + 3² = 36

36 + 4² = 52

52 + 5² = 77

Tenth place of 1.21 is greatest among all.

The tenth place of 1.1 and 1.120 is the same but the hundredth place is 2 of 1.120. so, 1.120 is greater between 1.1 and 1.120

So, the smallest among all is 1.01

Concept:

First, find the LCM (Lowest Common Factor) of the given fraction.

Then arranged it according to the given question.

Given:

\([ - \frac{{11}}{{20}},\;\frac{7}{{ - 15}},\;\frac{{17}}{{ - 30}}\;and - \frac{3}{{10}}]\)

Calculation:

LMC of the (20, 15, 30, 10) = 60

Multiply each fraction with the LCM i.e. 60

⇒ - 11/20 × 60 = - 33

⇒ - 7/15 × 60 = - 28

⇒ - 17/30 × 60 = - 34

⇒ - 3/10 × 60 = - 18

After arrange in decreasing order (descending order), We find that

\( - \frac{3}{{10}}\; > \;\frac{7}{{ - 15}}\; > \; - \frac{{11}}{{20}}\; > \;\frac{{17}}{{ - 30}}\)

Given:

2/9, 2/7, 2/5, 3/7,3/5

Calculation:

Here,

2/9 = 0.22,

2/7 = 0.28,

2/5 = 0.40,

3/7 = 0.42, 

3/5 = 0.60

In descending order

⇒ 0.60, 0.42, 0.40, 0.28, 0.22

⇒ 3/5, 3/7, 2/5, 2/7, 2/9

∴ The correct descending order is 3/5, 3/7, 2/5, 2/7, 2/9.

Given:

The number series:

5, 7, 11, 19, 36, 67

Concept Used:

Number series following a fixed pattern.

Calculation;

The given number series follows the pattern:

5 + 2¹ = 7

7 + 2² = 11

11 + 2³ = 19

19 + 2⁴ = 35

35 + 2⁵ = 67

∴ The Wrong Number in the given number series is 36

Given:

Time taken by A and B to complete the work = 6 days

Time taken by A and C to complete the work = 10 days

Time taken by A, B and C to complete the work = 5 days

Calculation:

⇒ 1/A  + 1/B  = 1/6

⇒ 1/A + 1/C = 1/10

⇒ 1/A + 1/B + 1/C = 1/5

⇒ 2/A + 1/B + 1/C = 4/15

Solving,

A = 15, B = 1/10 and C = 1/30

∴ B alone can complete the work in 10 days

(d) The series is based on the following pattern :
7 + 9 = 16
9 + 16 = 25
16 + 25 = 41
25 + 41 = 66; 68
41 + 66 = 107
66 + 107 = 173
Clearly, 68 should be replaced by 66

The series is as follows
+ 5, +9, + 13, +17 ....difference of two consecutive terms (9 – 5 = 13 – 9 = 17 – 13) is 4.
Hence, 35 is wrong number in the series. It should be 37.

The ratio of efficiencies of Raghav, Dharmendra and Anmol is 5 ∶ 6 ∶ 10

∴ Ratio of time taken by them to complete the job = 6 ∶ 5 ∶ 3      ----(LCM of 5,6 and 10 = 30)

Let time taken by Raghav, Dharmendra and Anmol be 6x, 5x and 3x days

Using statement I

Binod is 50% more efficient than Dharmendra

⇒ Time taken by Binod = 5x × (100/150) = 10x/3

⇒ Time taken by Simran be y 

Binod, Dharmendra and Simran completed the work in 60/13 days

⇒ (3/10x) + (1/5x) + (1/y) = 13/60

⇒ 1/y = (13/60) – (5/10x)      ----(i)

Statement I alone is not sufficient to answer the question 

Using statement II

Simran, Raghav and Anmol completed the work in 180/39 days

⇒ (1/y) + (1/6x) + (1/3x) = 39/180

⇒ 1/y = (39/180) – (3/6x)      ----(ii)

Statement II alone is not sufficient to answer the question 

Using statement I and statement II together 

Equating (i) and (ii)

⇒ (13/60) – (1/2x) = (39/180) – (1/2x)

∴ Value of x cannot be determined

∴ The data even in both statements I and II together are not sufficient to answer the question.

Calculation:

The logic behind the given series is as follows:

10,000 × (3/10) = 3000

3,000 × (6/10) = 1800

1,800 × (9/10) = 1620

1620 × (12/10) = 1,944

∴ The value of '?' is 1,944.

(b) The series is based on the following pattern:
16 × 0.25 = 4
4 × 0.50 = 2
2 × 0.75 = 1.5
1.5 × 1.00 = 1.5 ; not 1.75
1.5 × 1.25 = 1.875
Clearly, 1.75 should be replaced by 1.5.

12

12 × 2 = 24

24 × 3 = 72

72 × 5 = 360

360 × 7 = 2520

2520 × 11 = 27720

⇒ Multiplication of Prime number.

∴ The correct answer is option 4.

Given:

Time taken by Ragini alone = 3 days more than both of them worked together

Time taken by Raghav alone = 12 days more than both of them worked together

Calculation:

Let the time both of them took to make the carpet be x.

Time taken by Ragini alone = x + 3

Time taken by Raghav alone = x + 12

∴ one day of work when they both work together = Sum of their individual per day work

⇒ 1/x = 1/(x + 12) + 1/(x + 3)

⇒ 1/x = (2x + 15)/(x² + 15x + 36)

⇒ x² + 15x + 36 = 2x² + 15x

⇒ x = 6

∴ time taken by Ragini alone = 6 + 3

⇒ 9 days

Ragini alone make the carpet in 9 days.

(d) The series is as follows
(2)², (4)2, (6)², (8)², (10)², (12)²
Hence, ? = (12)² = 144

(b) The series is as follows
×1 + 2, ×2 + 4, ×3 + 6, ×4 + 8, × 5 + 10, × 6 + 12...
Hence, ? = 2090 × 6 + 12 = 12552

10

10 – 1² = 9

9 + 2² = 13

13 – 3² = 4

4 + 4² = 20

20 – 5² = -5

∴ The correct answer is option 5.

Calculation∶

The series follows following pattern

There are two pattern series i.e., alternate series

1^st pattern

1² = 1

3² = 9

5² = 25

7² = 49

2^nd pattern

2, 4, 6, …

Given:

Ratio of volume of three containers = 3 ∶ 4 ∶ 5

Ratio of milk and water in container 1 = 4 ∶ 1

Ratio of milk and water in container 2 = 3 ∶ 1

Ratio of milk and water in container 3 = 3 ∶ 2

Calculation:

First we have to make the sum of ratios equal

Ratio of milk and water in container 1 = 4/1 = (4 × 4)/(1 × 4) = 16/4

Ratio of milk and water in container 2 = 3/1 = (3 × 5)/(1 × 5) = 15/5

Ratio of milk and water in container 3 = 3/2 = (3 × 4)/(2 × 4) = 12/8

As they are mixed in the ratio 3 ∶ 4 ∶ 5

Milk = 16 × 3 + 15 × 4 + 12 × 5 = 168

Water = 3 × 4 + 5 × 4 + 8 × 5 = 72

Ratio of milk to water = 168 ∶ 72 = 7 ∶ 3

∴ Ratio of milk and water is 7 ∶ 3

Calculation:

The given number series follows this pattern:

2 × 1 = 2

2 × 2 = 4

4 × 3 = 12

12 × 4 = 48

48 × 5 = 240

240 × 6 = 1440

∴ The wrong number in the given series is 200.

(c) The series is as follows
×3, ×8, × 15, ×24, ×35, ×48
Hence, ? = 302400 × 48
= 14515200

Concept:

• The ways of arranging n different things = n!
• The ways of arranging n things, having r same things and rest all are different = \(\rm n!\over r!\)
• The no. of ways of arranging the n arranged thing and m arranged things together = n! × m!
• The number of ways for selecting r from a group of n (n > r) = nCr 

Calculation:

For a number to be divisible by 5 only if the number end with 0 or 5, here the case is 0, hence the unit digit has to be 0.

Now, remaining are 3 digits 3, 4 and 8

If the number is between (101 and 999), the ways = 3² × 1 = 9

If the number is between (1000 and 9999), the ways = 33 × 1 = 27

If the number is between (10000 and 99999), the ways = 34 × 1 = 81 

∴ Total number of ways = 9 + 27 + 81

Total number = 117