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(b) Madhya Pradesh

(c) soil conservation

(c) Barley and mustard

Wheat is not primarily a kharif crop in India.

Rihand hydro-electric stations is situated in Uttar Pradesh.

Gujarat is state has the longest coastline.

Kanchenjunga is situated in Sikkim.

(d) Madhya Pradesh

(d) situated about 30 º east of Dwaraka and the earth rotates from west to east

(a)  Idukki.

The highest multipurpose dam built on the river Ravi is Ranjit Sagar dam.

(d) Barley and Mustard

Majuli the largest river island in the world lies in the stale of Assam.

(c) Krishna, Nalgonda

The multipurpose project irrigating maximum area in India is Hirakud.

(d) situated about 30 º east of Dwaraka and the earth rotates from west to east

Narmada originates from its source situated in the State of Madhya Pradesh.

(d) irrigation, flood control and power generation

Bhakra dam of India is the highest.

Ganga beyond Farakka when it enters Bangladesh is known as Padma.

(c) preserving the port of Kolkata 

GIma Project is situated in Maharashtra.

Loktak Lake, a big lake of North East India, is located in Manipur.

Narmada is  rivers makes an estuary.

Loktak is a Lake.

The Loktak Lake on which ahydroelectric project was constructed is situated in the State of Manipur.

(b) West Bengal

Mahi Project will greatly benefit Gujarat.

Indira Gandhi Canal is the longest irrigation canal in India.

Rihand Dam Project provides irrigation to Uttar Pradesh and Bihar.

Chilka lake is located in Orissa.

The answer is

6.25%

Relationship b/n commercial unit of energy & S.I. unit of energy can be given by—

1 kwh = 3.6 x 10⁶ J

Expression of Joule's heating effect of current, H = I² Rt

. 4.98 x 10^-4 sec^-1

Correct option: D. 22 days

\(\lim\limits_{x \to 0^-}\) f(x) = \(\lim\limits_{x \to 0}\)(2x + 3) = 3

\(\lim\limits_{x \to {0^+}}\) f(x) = \(\lim\limits_{x \to 0}\)3(x +1) = 3

Therefore; \(\lim\limits_{x \to 0}\) f(x) = 3

\(\lim\limits_{x \to 1}\) f(x) = \(\lim\limits_{x \to 1}\) 3(x+1) = 3 x 2 = 6

Concept:

A spherical balloon is filled with 3536 π cubic meters of helium gas.

The leakage rate of Helium gas from a balloon is \(\frac{{dV}}{{dt}} = - 70π ~\frac{{{m^3}}}{{min}}\)

The volume of spherical balloon is, \(V = \frac{4}{3}π {r^3}\)

The radius of the balloon decreases after the leakage after "t" time period is, \(\frac{{dV}}{{dt}} = 4π {r^2}\frac{{dr}}{{dt}}\).............(1)

Calculation:

Given:

V_o = 3536π m³, t = 50 min

The rate of leakage from balloon is, \(\frac{{dV}}{{dt}} = - 70π \)

After integration, we will get

∴ V = -70πt + C 

At t = 0, ⇒ V = V_o ∴ C = V_o

⇒ V = V_o -70πt 

Volume of balloon of after 50 minutes:

V = 3536π - (70π × 50) 

V = 36π m³

But the volume of balloon is, \(V = \frac{4}{3}π {r^3}\)

Therefore, \( \frac{4}{3}π {r^3}=36\pi\)

r = 3 m ..............(at 50 min)

The radius of balloon decreases after the leakage after "t" time period is, 

\(\frac{{dr}}{{dt}} = \left[ {\frac{{dV}}{{dt}}} \right]\frac{1}{{4\pi {r^2}}}\)................(from eq.1)

Let x km/hr be the speed.

Let the time required to travel in the same speed be \(\frac{300}{x}\) hour. 

If the speed is increased by 5 km/ hr the time will decreased by 2 hours.

\(\frac{300}{x}-2=\frac{300}{x+5}\)

\(\frac{300-2x}{x}=\frac{300}{x+5}\)

-2x² + 290x + 1500 = 300x

x² + 5x - 720 = 0

\(x=\frac{-5\pm \sqrt{25+3000}}{2}=\frac{-5\pm55}{2}=25,-30\)

Speed will not be negative, therefore x = 25

Speed = 25 km/hour

The relative speed between police and thief = 10-8 = 2 km/h = 10/18 m/s

Distance between police and thief = 100 m

Time = Distance/Speed = 180 s = 3 min

Correct answer is (ii) Median

Answer is (2) Median

There are two types of positional average: the median and the mode. 

The median is the average value of the series in which half the values are less than the median and half the values are greater than the median.