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Count the numbers that can be formed by the digits 0, 3, 4 and 8 which is divisible by 5. The number must range between 100 to 100000 (both inclusive) and digits can be repeated.1. 1422. 2043. 2734. 117 |
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Answer» Correct Answer - Option 4 : 117 Concept:
For a number to be divisible by 5 only if the number end with 0 or 5, here the case is 0, hence the unit digit has to be 0. Now, remaining are 3 digits 3, 4 and 8 If the number is between (101 and 999), the ways = 32 × 1 = 9 If the number is between (1000 and 9999), the ways = 33 × 1 = 27 If the number is between (10000 and 99999), the ways = 34 × 1 = 81 ∴ Total number of ways = 9 + 27 + 81 Total number = 117 |
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