1.

Count the numbers that can be formed by the digits 0, 3, 4 and 8 which is divisible by 5. The number must range between 100 to 100000 (both inclusive) and digits can be repeated.1. 1422. 2043. 2734. 117

Answer» Correct Answer - Option 4 : 117

Concept:

  • The ways of arranging n different things = n!
  • The ways of arranging n things, having r same things and rest all are different = \(\rm n!\over r!\)
  • The no. of ways of arranging the n arranged thing and m arranged things together = n! × m!
  • The number of ways for selecting r from a group of n (n > r) = nCr 


Calculation:

For a number to be divisible by 5 only if the number end with 0 or 5, here the case is 0, hence the unit digit has to be 0.

Now, remaining are 3 digits 3, 4 and 8

If the number is between (101 and 999), the ways = 3× 1 = 9

If the number is between (1000 and 9999), the ways = 3× 1 = 27

If the number is between (10000 and 99999), the ways = 3× 1 = 81 

∴ Total number of ways = 9 + 27 + 81

Total number = 117



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