This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 7751. |
Why do noble gases have comparatively large atomic sizes? |
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Answer» Noble gases do not form molecules. In case of noble gases, the atomic radii corresponds to van der Waal’s radii. On the other hand, the atomic radii of other elements correspond to their covalent radii. By definition, van der Waal’s radii are larger than covalent radii. It is for this reason that noble gases are very large in size as compared to other atoms |
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| 7752. |
(i) Noble gases have large positive values of electron gain enthalpy.(ii) Helium is used by scuba divers.(iii) No chemical compound of helium is known. |
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Answer» [Hint : (i) Due to their electron conflguration. |
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| 7753. |
Explain why O3 is thermodynamically less stable than O2 ? |
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Answer» [Hint : Because O3 is endothermic compound/decomposition of O3 is exothermic and ΔG is negative/decomposition of O3 is spontaneous.] |
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| 7754. |
Among F, Cl, Br and I the lowest ionization potential will be of(a) fluorine (b) chlorine (c) bromine (d) iodine |
| Answer» (d) Ionisation potential decreases down the group | |
| 7755. |
Which compound produces only one alkene when treated with sodium methoxide? (A) 2-chloro-2-methylpentane (B) 3-chloro-3-ethylpentane (C) 3-chloro-2-methylpentane (D) 2-chloro-4-methylpentane (E) 2-chloro-3-ethylpentane |
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Answer» (B) 3-chloro-3-ethylpentane |
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| 7756. |
Which of the following mechanisms feature carbocation intermediates? (A) SN1 only (B) SN2 only (C) E1 only (D) E2 only (E) both SN1 and E1 |
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Answer» (E) both SN1 and E1 |
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| 7757. |
Explain the question completely |
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Answer» I think the option (D) is correct. Here are the reasons. 1. Pairs (x,y) in (A) and (C) do not support the reaction (1) where two isomers give same hyrogenathydr product (Z) 2. Pairs (x,y) in (A),(B),and (C)do not support the formation of same two ozonolysis products (W) and (S) as stated in reaction (2). 3. Pairs (x,y) in D are two geomtrical isomers (trans and cis respectively). They support all the reactions in steps 1 to 3 and the melting point of trans isomer (x) is higher than the cis one(y). |
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| 7758. |
Explain about energy barrier and orientation barrier |
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Answer» Energy barrier : For the reacting species to make effetive collisions they should havesufficient energy to break the chemical bonds in the reacting molecules. The minimum amount of energy which the colliding moleccules must possess is known as threshold energy. This means that only thosecollisions of reactants which possess energies greater than thresholdenergy will give products. In the case of conformational isomerism, the energy barrier which prevents one conformer to convert into another by rotation, is called as orientation barrier. |
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| 7759. |
a ring of mass m=0.25kg free to slide on a fixed smooth horizom |
| Answer» It looks like your question is not complete please try to post your complete question............... | |
| 7760. |
A `50-kg` ball is attached to one end of a `1m` cord that has a mass of `0.10kg`. The other end o the cord is attached to a ring that can slide on a frictionless horizontal shaft `AB`, as shown in the diagram. A horizontal blow is delivered to the cord and excites the fundamental vibratiion with a maximum transverse velocity of `15m//s`. Assume that the ball remains essentially stationary as the cord vibrates. `[g=9.8m//s^(2)]` A. The frequency of the fundamental vibration is `17.5Hz`B. The amplitude of the motion is `13.6xx10^(-2)m`C. If the blow is delivered as an impulse to a stationary cord, the wave function for the cord is `y(x,t)=Asin(pix//2L)sinomegat`, where the ball is located at `x=0` and positive `x`-axis is along the string.D. The period of the pendulum motion of the hanging ball is 2 sec, approximately. |
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Answer» Correct Answer - A::B::C::D `v=sqrt(T/(mu))=sqrt((50xx1xx9.8)/0.1)=70m//s` `(lamda)/4=1implieslamda=4mimpliesf=f/(lamda)=70/4=17.5Hz` `v_("pmax")=omegaAimpliesA=(v_("pmax"))/(2pif)=15/(2xx3.14xx17.5)=0.136m=13.6xx10^(-2)m` |
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| 7761. |
We are given the following atomic masses: `._(92)^(238)U=238.05079u ._(2)^(4)He=4.00260u` `._(90)^(234)Th=234.04363u ._(1)^(1)H=1.00783u` `._(91)^(237)Pa=237.05121u` Here the symbol `Pa` is for the element protactinium `(Z=91)`A. The energy released during the `alpha-` decay of `._(92)^(238)U` is `4.75MeV` approximatelyB. The energy released during the `alpha-` decay of `._(92)^(238)U` is `4.25MeV` approximatelyC. The emission of proton from `._(92)^(238)U` can be spontaneousD. The emission of proton from `._(92)^(238)U` can not be spontaneous. |
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Answer» Correct Answer - B::D The energy released in `alpha`- decay is given by `Q=(M_(U)-M_(Th)-M_(He))c^(2)` Substituting the atomic masses as given in the data, we find `Q=(238.05079-234.04363-4.00260)uxxc^(2)=(0.00456u)c^(2)=(0.00456u)c^(2)` `=(0.00456u)(931.5MeV//u)=4.25MeV` If `._(92)^(238)U` spontaneously emits a proton, the decay process would be `._(92)^(238)Uto_(92)^(237)Pa+._(1)^(1)H` The `Q` for this process to happen is `=(M_(U)-M_(Pa)-M_(H))c^(2)=(238.05079-237.05121-1.00783)uxxc^(2)=(-0.00825u)c^(2)` `=-(0.00825u)(931.5MeV//u)=-7.68MeV` Thus, the `Q` of the process is negative and therefore it cannot proceed spiontaneously. We will have to supply an energy of `7.68MeV` to `._(92)^(238)U` nucleus to make it emit a proton. |
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| 7762. |
Calculate the ground state `Q` value of the induced fission raction in the equation `n+._(92)^(235) Urarr._(92)^(236)Uastrarr._(40)^(99)Zr+._(52)^(134)Te+2n` If the neutron is thermal. A thermal neutorn is in thermal equilibrium with its envitronmnet, it has an avergae kinetic energy given by `(3//2) kT`. Given : `m(n) =1.0087 am u, M(.^(235)U)=235.0439) am u`, `M(.^(99)Zr)=98.916 am u, M(.^(134)Te)=133.9115 am u`.A. 184.84 MeVB. 200 MeVC. 130 MeVD. 300 MeV |
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Answer» Correct Answer - A `Q=Deltamxx931` = [(235.0439 + 1.0087) – (98.916 + 133.9115+3.0261] × 931 Q = 184.84 MeV |
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| 7763. |
A particle moves along the curve `6y = x^(3)+2`. Find the points on the curve at which the y-coordinate is changing 8 times as fast as the x-coordinateA. `(1,(1)/(2))`B. `(4,11)`C. `(2,(5)/(3))`D. None of these |
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Answer» Correct Answer - B As per the question `(dy)/(dt) = 8` `rArr (3x^(2))/6 = 8 rArr x = +- 4` |
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| 7764. |
An escalator is used to move `5` people (`60kg` each) per minute from the first floor of a department store to the second floor. `20m` above. Neglecting friction calculate the power required ?A. `1kW`B. `2kW`C. `3kW`D. `4kW` |
| Answer» Correct Answer - A | |
| 7765. |
For conservative force field, `vec(F)=-(delU)/(delx)hat(i)-(delU)/(dy)hat(j)-(delU)/(delz)hat(k)` where `Frarr` Maginitude of Force. `Urarr` Potential energy and `(delU)/(delx)=` Differentiation of `U` w.r.t. `x` keeping `y` and `z` constant and so on. Choose incorrect matching `:-`A. `(A)rarr(P,Q,R,S)`B. `(B)rarr(Q,R)`C. `(C)rarr(P,S)`D. `(D)rarr(P,R,S)` |
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Answer» Correct Answer - D For `(A)` `:` `vec(F)=-2xyzhat(i)-x^(2)zhat(j)-x^(2)yhat(k)rArrF_(x)=0`, `F_(y)=0,F_(z)=0,U=0` For`(B)` :`vec(F)=-2xhat(i)-zhat(j)-yhat(k)rArrF_(x)ne0,F_(y)=0, F_(z)=0, Une0` For `(C )` `:` `vec(F)=-2x(y+z)hat(i)-x^(2)hat(j)-x^(2)hat(k)rArrF_(x)=0,F_(y)ne0, F_(z)ne0, U=0` For `(D)` `:` `vec(F)=-2xyhat(i)-x^(2)hat(j)-hat(k)rArrF_(x)=0,F_(y)ne0, F_(z)ne0, U=0` |
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| 7766. |
A stone is dropped into a quiet lake and waves move in circles at the speed of `5 cm//s`. At the instant when the radius of the circular wave is `8 cm`, how fast is the enclosed area increasing?A. `80 pi cm^(2)//s`B. `90 pi cm^(2)//s`C. `85 pi cm^(2)//s`D. `40 pi cm^(2)//s` |
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Answer» Correct Answer - A Enclosed area `:``A=pir^(2)` so `(dA)/(dt)=2pir(dr)/(dt),` Here `r=8cm`, `(dr)/(dt)=5cm//s` `rArr(dA)/(dt)=(2n)(8)(5)=80picm^(2)//s` |
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| 7767. |
A stone is dropped into a quiet lake and waves move in circles at the speed of `5 cm//s`. At the instant when the radius of the circular wave is `8 cm`, how fast is the enclosed area increasing?A. `80 pi cm^(2)//s`B. `90 pi cm^(2)//s`C. `85 pi cm^(2)//s`D. `89 pi cm^(2)//s` |
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Answer» Correct Answer - A Enclosed area: `A= pi r^(2)` so `(dA)/(dt)=2pi r(dr)/(dt)` Here `r=8 cm, (dr)/(dt)=5 cm//s` `rArr (dA)/(dt)=(2pi) (8)(5)=80 pi cm^(2)//s` |
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| 7768. |
फ्रिज और टी.वी. की कीमत का अनुपात `5:3`है। यदि फ्रिज की कीमत टी.वी. से 5500 अधिक है तो फ्रिज की कीमत क्या होगी।A. रू 27500B. रू 8250C. रू 13750D. रू 16500 |
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Answer» Correct Answer - C Refrigerator : Television Price 5 : 3 Let 5x : 3x Given 5x-3x=2x 2x=5500 x=2750 `therefore` (रेफ़्रिजेरेटर का मूल्य ) `implies 5xx2750= Rs. 13750` |
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| 7769. |
The distance between `Na^(+)` and`CI^(-)` ion ion NaCI is 281 pm. What is the edge length of the cubeA. 1405 pmB. 562 pmC. 843 pmD. 281 pm |
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Answer» Correct Answer - B `r_(Na^(+))+r_(CI^(-))=(a)/(2)` `281 "pm"=(a)/(2)` `562"pm"=a` |
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| 7770. |
Kossel postulated alkalies and halogens are separated by noble gases. But they are separated by transition elements then how is that true? |
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Answer» Kössel’s explanation of chemical bonding:
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| 7771. |
The correct order of reactivity of halogens with alkalies is(a) F > Cl > Br > I (b) F < Cl > Br < I (c) F < Cl < Br < I (d) F < Cl < Br > I |
| Answer» (a) Reactivity follows the order F > Cl > Br > I | |
| 7772. |
Which one of the following order is correct for the bond energies of halogen molecules ?(a) I2 > Cl2 > Br2 (b) Br2 > Cl2 > I2 (c) I2 > Br2 > Cl2 (d) Cl2 > Br2 > I2 |
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Answer» (d) Cl2 > Br2 > I2 |
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| 7773. |
Total number of electrons having `n + l = 4` in `V(23)` atom in its ground state is |
| Answer» Correct Answer - 8 | |
| 7774. |
What happens when (a) magensium in burnt in air, (b) quicklime is heated with silica, (c ) chlorine reacts with slaked lime and (d) calcium nitrate is heated? |
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Answer» a.`2Mg_((s))+O_(2g)overset(Delta)rarr2MgO_((s))` b. `underset("Quicklime")(CaO_(s))+underset("Silica")(SiO_(2(s)))overset(Delta)rarrunderset("Calcuim silicate")(CaSiO_(3)(s))` c. It reacts with `Cl_(2)` to form calcuim hypochlorite, `Ca(OC l)_(2)`-a constituent of bleaching powder. b. `underset("Slaked lime")(2Ca(OH)_(2))+2Cl_(2)rarrubrace(CaCl_(2)+Ca(OCl)_(2))_("Bleaching powder")+2H_(2)O` d. `2Ca(Na_(3))_2(s)overset(Delta)rarr 2CaO_(s)+4NO_2(g)+O_2(g)` |
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| 7775. |
How many of the following elements show `+2` as their most stable oxidation state ? `Sc, Sn, Zn, Be, Pb, Co, Ag, Ti, Fe` |
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Answer» Correct Answer - 5 `Fe, Zn, Be, Pb, Co` are most stable in their `+2` states. |
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| 7776. |
Symbols `._(35)^(79)Br` and `.^(79)Br` can be written, whereas symbols `._(79)^(35)Br` and `.^(35)Br` are not acceptable. Answer briefly. |
| Answer» Atomic number of an element is fixed. However, mass number is not fixed as it depends upon the isotope taken. Hence, it is essential to indicate mass number. | |
| 7777. |
Which of the following compounds on boiling with alkaline `KMnO_4` and subsequent acidification will not give benzoic aicd ?A. TolueneB. AcetopehenoneC. AnisoleD. Benzyl alcohol |
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Answer» Correct Answer - C `C_2H_5-OCH_3` (being ether) is not oxidised by `KMnNO_4`. |
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| 7778. |
Write the expression for Freundich adsorption isotherm. |
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Answer» Freudich adsorption isotherm is given by \(\frac{x}{m}= kp^{1/n}\) where n > 1 |
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| 7779. |
(i) Name the product formed for the reaction of isopropyl iodide on alcoholic KOH. (ii) What is the condition to be satisfied for a compound to be chiral? |
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Answer» (i) Propene (ii) The absence of the plane of symmetry. |
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| 7780. |
What is heterogeneous catalysis? Give an example? |
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Answer» A catalytic process in which reactants and catalyst are in different phases are known as heterogenous catalysis. E.g: 1. N2(g) + 3H2(g) \(\overset{Fe(s)}{\longrightarrow}\) 2NH3 Here the reactants are gases, catalyst iron is a solid 2. Vegetable oil(l) + H2(g) \(\overset{Ni(s)}{\longrightarrow}\) Vanaspathi ghee Here reactants and catalyst are in different phases. |
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| 7781. |
Explain Wurtz – Fittig’s reaction. |
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Answer» A mixture of an alkyl halide and aryl halide gives an alkylarene when treated with sodium in dry ether and is called as wurtz – fitting reaction. |
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| 7782. |
How does entropy change (ΔS) for adsorption? |
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Answer» Entropy decreases OR ΔS = -ve |
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| 7783. |
ter-Butyl methyl ehter on heating with HI (g) in the presence of ehter gives a mixture ofA. ter-Butyl alcohol and methyl iodideB. ter-Butyl iodide and methyl alcoholC. Isobutylene and methyl iodideD. Isobutylene and methyl alcohol |
| Answer» Correct Answer - A | |
| 7784. |
ter-Butyl methyl ehter on heating with anhydrous HI in dry ether gives a mixture ofA. ter-Butyl alcohol and methyl iodideB. ter-Butyl iodide and methyl alcoholC. Isobutylene and methyl iodideD. None of these. |
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Answer» Correct Answer - A See the Reactions due to oxygen. |
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| 7785. |
ter-Butyl methyl ether on heating with HI gives a mixture ofA. ter-Butyl alcohol and methyl iodideB. ter-Butyl iodide and methanolC. Isobutylene and methyl iodideD. Isobutylene and methanol. |
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Answer» Correct Answer - B `(CH_3)_2C-O-CH_3+Hito(CH_3)_2C-I+CH_3OH` |
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| 7786. |
the _____ income is also called as percapita income |
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Answer» The average income is also called per capita income. |
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| 7787. |
Assertion : ter-Butyl methyl ether on cleavage with conc. HI at 373K gives tert-butyl iodide and methanol. Reason : The reaction occurs by `S_N2` mechanism.A. Both A and B are true and R is the correct explanation of A.B. A is true but R is False.C. A is False but R is True.D. Both A and R are false. |
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Answer» Correct Answer - C The reaction proceeds by `S_N1` Mechanism. |
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| 7788. |
What is the motive of writing a business or official letter? a. To place a business query b. To place an order c. To promote a product d. All of the above |
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Answer» Correct option is d. All of the above. |
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| 7789. |
Statement (I) : Coolant and antifreeze refer to the same product Statement (II) : Gas engines do not require cooling(a) Both Statement (I) and Statement (II) are individually true and Statement (II) is the correct explanation of Statement (I) (b) Both statement (I) and Statement (II) are individually true but Statement (II) is NOT the correct explanation of Statement (I) (c) Statement (I) is true but Statement (II) is false (d) Statement (I) is false but Statement (II) is true |
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Answer» (c) Statement (I) is true but Statement (II) is false Antifreeze is mixed with coolant to avoid freezing of coolant in cold climate application of engine. All engines whether gas, or liquid or coal or steam requires cooling. |
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| 7790. |
Which one is asexual reproductions method as given below ?(A) Fission (B) Budding(C) Binary fission (D) All of these |
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Answer» Fission, Budding and Binary fission is asexual reproductions method. |
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| 7791. |
Name the worms that cause lymphatic filariasis. |
| Answer» Wuchereria bancrofit, Brugia malayi, Brugia timori are worms that cause lymphatic filariasis. | |
| 7792. |
Filariasis is caused by worms. |
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Answer» Filariasis is caused by worms Filarial worms. |
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| 7793. |
Write about the malarial fever, its causes, symptoms, control and prevention. |
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Answer» People who get malaria are typically very sick with high fevers, shaking chills, and flue-like illness is called malarial fever. Cause of Malaria: Malaria is caused by the bites from the female Anopheles mosquito which then infect the body with the parasite plasmodium. This is the only mosquito that can cause malaria. Symptoms: Sensation of cold, shivering fever, headache and vomiting sweats followed by a return to normal temperature with tiredness deep breating and respiratory distress. Prevention and control: Prevention and control measures involved the elimination of insect vector i.e. mosquito. Spray of DDT or thin films of oil in ditches helps in checking mosquito breeding. Treatment is through chloroquine and primaquine preparations. |
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| 7794. |
Munch hypothesis is based onA. translocation of food due to turgor Pressure (TP) gradient and imbibition forceB. translocation of food due to Turgor Pressure (TP) gradientC. translocation of food due to imbition forceD. None of the above |
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Answer» Correct Answer - B Munch hypothesis is based on the movement of phloem sap along a turgor pressure gradient. The mass flow of organic solutes takes place from the site of higher concentration, (source) to the site of lower concentration (sink). |
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| 7795. |
Explain the mechanism of ascent of sap |
Answer»
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| 7796. |
Briefly explain alcoholic fermentation |
Answer»
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| 7797. |
Given below is the schematic diagram of calvin cycle, which completes in three stages.1. Where does this cycle takes place? 2. State the three stages of calvin cycle? 3. Calculate the energy budget for each stage to synthesise one molecule of glucose during the process. |
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Answer» 1. Stroma 2.
3.
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| 7798. |
Half-life of a radioactive substance A is 4 days. The probability that a nucleus will decay in two half-lives is : (a)1/2(b)1/4(c)3/2(d)3/4 |
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Answer» Answer : (d) 3/4 Explanation: After two half-lives 1/4th fraction of nuclei will remain undecayed . or 3/4th fraction will decay hence the probability that a nucleus decays in two half-lives is 3/4 |
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| 7799. |
Give the diagrammatic representation of HSK-path-way and answer the following questions : Name the `CO_(2)` acceptor in mesophyll cells during HSK pothway. |
| Answer» PEP-Carboxylase (PEP case ) is the `CO_(2)` acceptor in mesophyll cells during HSK pathway. | |
| 7800. |
Give the diagrammatic representation of HSK-path-way and answer the following questions : Why is photorespiration avoided in `C_(4)` pathways ? |
| Answer» In `C_(4) ` plants, PEP carboxylase (PEP case) fixes `CO_(2)` concentration in the mesophyll cells. In bundle sheath cells, `CO_(2)` concentration is moer, so that RUBISCO functions as carboxylase and photorespiration is avoided. | |