94420 + Interview Questions in Chemistry in Class 12

1.	Aluminium is most abundant in earth crust yet it is obtained from bauxite because
Answer» BAUXITE is avilable in larger QUANTITY Of easy EXTRACTION of ALUMINIUM from it Bauxite CONTAINS maximum aluminium Bauxite is less impure Answer :A

Discussion

2.	Aluminium is mainly extracted from :
Answer» Magnetite Haematite Alumina Bauxite Answer :D

Discussion

3.	Aluminium is extracted from alumina (Al_2O_3) by electrolysis of a molten mixture of
Answer» `Al_2O_3+HF +NaAlF_4` `Al_2O_3+CaF_2+NaAlF_4` `Al_2O_3 +Na_3AlF_6+CaF_2` `Al_2O_3+KF +Na_3AlF_6` ANSWER :C

Discussion

4.	Aluminium is extracted from alumina (Al_(2)O_(3)) by electrolysis of a molten mixture of
Answer» `Al_(2)O_(3)+HF+NaAlF_(4)` `Al_(2)O_(3)+CaF_(2)+NaAlF_(4)` `Al_(2)O_(3)+Na_(3)AlF_(6)+CaF_(2)` `Al_(2)O_(3)+KF+Na_(3)AlF_(6)` Solution :Fused alumina `(Al_(2)O_(3))` is a bad conductor of electrieity. Therefore,cryolite `(Na_(3)AlF_(6))` and fluorspar `(CaF_(2))` are added to purified alumina which not only MAKE alumina a good conductor of electriety but also REDUCE the melting point of the mixture to around 1140 K.

Discussion

5.	Aluminium is extracted from alumina (Al_(2)O_(3)) by electrolysis of a molten mixture of ……….
Answer» `Al_(2)O_(3)+KF+Na_(3)AlF_(6)` `Al_(2)O_(3)+HF+NaAlF_(4)` `Al_(2)O_(3)+HF+NaAlF_(4)` `Al_(2)O_(3)+Na_3AlF_(6)+CaF_(2)` ANSWER :D

Discussion

6.	Aluminium is extracted from alumina (Al_(2)O_(3)) by electrolysis of a molten mixture of :
Answer» `Al_(2)O_(3)+HF+NaAlF_(4)` `Al_(2)O_(3)+CaF_(2)+NaAlF_(4)` `Al_(2)O_(3)+Na_(3)AlF_(6)+CaF_(2)` `Al_(2)O_(3)+KF+Na_(2)AlF_(6)` Solution :Fused Alumina `(Al_(2)O_(3))` is a bad conductor of electricity. THEREFORE, cryoliter `(Na_(2)AlG_(6))` and fluospar`)(CaF_(2)`) areadded to PURIFIED alumina which not only make alumina a good conductor of electricity but also reduce the MELTING point of the mixture to around 1140K.

Discussion

7.	Aluminium isextractedfromalumina (Al_2 O_3)byelectrolysisofa moltenmixture of
Answer» ` Al_2O_3 + HF + NaAlF_4` `Al_2O_3 + CaF_ 2+ NaAlF_ 4` ` Al_2 O_ 3 + Na_3AlF_6 + CaF_ 2` `Al_2O_3 + KF + Na_2AlF_6 ` Solution : ` AL _2O_3+Na_3 AlF_6 + C aF_2`

Discussion

8.	Aluminium is diagonally related to:
Answer» Li Be Mg B Answer :B

Discussion

9.	Aluminium is diagonally related to (in periodic table)
Answer» Li C B Be Answer :D

Discussion

10.	Aluminium (III) chloride froms a dimer because
Answer» HIGHER coordination number can be achieved by aluminium Aluminiumhas high ionization energy Aluminium belongs to III GROUP It cannot form a trimer ANSWER :A

Discussion

11.	Aluminium (III) chloride forms a dimer because :
Answer» aluminium has high ionisation energy it cannot form higher higher coordination number can be ACHIEVED by aluminium aluminium belongs to III group. Answer :C

Discussion

12.	Aluminium hydroxide, magnesium hydroxide, erythromycin, cimetidine, ranitidine.
Answer» Solution :ERYTHROMYCIN. It is ANTIMICROBIAL WHEREAS OTHERS are antacids.

Discussion

13.	Aluminium hydroxide is soluble in excess of sodium hydroxide forming the ion
Answer» `AlO_(2)^(+3)` `AlO_(2)^(-3)` `AlO_(2)^(-)` `AlO_(3)^(-)` ANSWER :C

Discussion

14.	Aluminium forms [AlF_(6)]^(3-)ion but boron does not form [BF_(6)]^(3-)ion.
Answer» SOLUTION :Maximum co-ordination NUMBER of boron is four as it does not have d-orbitals, while the maximum COORDINATION number of aluminium is 6. Thus, Al forms `[AlF_(6)]^(3-)`ion while boron does not form `[BF_(6)]^(3-)` ion.

Discussion

15.	Aluminium forms :
Answer» ELECTROVALENT COMPOUNDS only COVALENT compounds only Electrovalent and covalent compounds both Coordinate compounds only Answer :C

Discussion

16.	Aluminium does not react with :
Answer» `NAOH` `HCL` `N_2` `HNO_3` ANSWER :D

Discussion

17.	Aluminium displaces hydrogen from dilute HCl whereas silver does not. The e.m.f. of a cell prepared by combining Al//Al^(3+) and Ag//Ag^(+) is 2.46V. The reduction potential of silver electrode is +0.80V. The reduction potential of aluminium electrode is
Answer» `+1.66V` `-3.26V` `3.26V` `-1.66V` Solution :AL is more reactive than AG, i.e., CELL reaction is `Al+3Ag^(+) to Al^(3+)+3Ag` `E_(cell)=E_("cathode")^(@)-E_("anode")^(@)` `=E_(Ag^(+)//Ag)^(@)-E_(Al^(3+)//Al)^(@)` `2.46=0.80-E_(Al^(3+)//Al)^(@)` or `E_(Al^(3+)//Al)^(@)=-1.66V`

Discussion

18.	Aluminium displaces hydrogen from dilute HCl whereas silver does not. The e.m.f. of a cell prepared by combining Al//Al^(3+) and Ag//Ag^(+)is 2.46 V. The reduction potential of silver electrode is + 0.80 V. The reduction potential of aluminium electrode is
Answer» `+1.66 V ` `-3.26 V ` `+ 3.26 V` `- 1.66 V ` ANSWER :D

Discussion

19.	Aluminium displaces hydrogen from dilute HCl whereas silver does not. The e.m.f. of a cell prepared by combining Al//Al^(3+) and Ag//Ag^(+) is 2.46V. The reduction potential of silver electrode is +0.80V. The reduction potential of aluminium electrode.
Answer» `+1.66V` `-3.26V` `3.26V` `-1.66V` Solution :Al displaces H from HCL but SILVER cannot it means Al is situated above the AG in ECS, HENCE Al will acts as anode and Ag will act as cathode. `E_(cell)^(o)=E_("cathode")^(o)-E_("anode")^(o)=E_(Ag^(+)//Ag)^(o)-E_(Al^(3+)//Al)^(o)` `2.46=0.8-E_(Al^(3+)//Al)^(o),E_(Al)^(o)=0.8-2.46=-1.66V`.

Discussion

20.	Aluminium displaces hydrogen from acids but copper does not. A galvanic cell prepared by combining Cu//Cu^(2+) and Al//Al^(3+) has an e.m.f. of 2.0 V at 298 K. if the potential of copper electrode is +0.34V, that of aluminium is
Answer» `+1.66V` `-1.66V` `+2.34V` `-2.3V` ANSWER :B

Discussion

21.	Aluminium displaces hydrogen from acids, but copper does not. A galvanic cell prepared by combining Cu\| Cu^(2+) and Al\|Al^(3+) has an emf of 2.0 V at 298 K. If the potential of copper electrode is + 0.34 V, that of aluminium electrode is
Answer» `-2.3 V ` `+2.34V` `-1.66` V `1.66` V Solution :`Al \|Al^(3+) \|\|Cu^(2+) \|Cu` `E_(cell)^(@) = E_((Cu^(2+) \|Cu))^(@) - E_((Al^(3+)\|Al))^(@)` `2.00 = 0.34 - E_((Al^(3+)\|Al))^(@)` `THEREFORE E^(@) (Al^(3+)\|Al) = 0.34 - 2.0 = -1.66 V`

Discussion

22.	Aluminium displaces hydrogen from dilute HCI whereas silver does not Thee.m.f. of a cell prepared by combiningAl/Al ^3+and Ag/Ag ^+is 2.46 V. The reduction potential of silver electrode is + 0.80 V. The reduction potential of aluminium electrode
Answer» `+1.66V` `-3.26V` `3.26V` `-1.66V` ANSWER :D

Discussion

23.	Aluminium displaces hydrogen from acids, but copper does not. A galvanic cell prepared by combining Cu//Cu^(2+) and Al//Al^(3+)has an emf of 2.0 V at 298K. If the potential of copper electrode is +0.34V, that of Aluminium electrode is
Answer» `-2.3V` `+2.34V` `-1.66V` `1.66V` ANSWER :C

Discussion

24.	Aluminium displaces hydrogen from acids, but copper does not. A galvanic cell prepared by combining Cu//Cu^(2+) and Al//Al^(3+) has an emf of 2.0V at 298K. If the potential of copper electrode is +0.34V and that of Aluminium electrode is
Answer» `-2.3V` `+2.34V` `-1.66V` `1.66V`. Solution :Cellrepresentation is `Al\|Al^(2+)\|\|C u^(2+)\|CU` `E_("CELL")=E_(Cu^(2+))+_(//Cu)-E_(Al^(3))+_(//Al)` `2.0V== 0.34V-E_(Al^(3+)//Al)` `E_(Al^(3+)//Al)=0.34V-2.0V=-1.66V`

Discussion

25.	Aluminium displaces hydrogen from acids but copper does not. A galvainc cell prepared by combining Cu//Cu^(2+) and Al//Al^(3+) has an emf of 2.0 V at 298 K. If the potential of copper electrode is +0.34 then that of the aluminiumelectrode is:
Answer» `+1.66`V `-1.66` V `+2.34`V `-2.3`V Answer :C

Discussion

26.	Aluminium displaces hydrogen from acid, but copper does not. A Galvanic cell prepared by combining Cu//Cu^(2+) and Al//Al^(3+) has an emf of 2.0V at 298K. If the potential of copper electrode is 0.34V, that of aluminium electrode is
Answer» `-1.66V` `+1.66V` `-2.3V` `+2.34V` Solution :EMF = `E^(@)` (cathode) `-E^(@)` (ANODE) `=E^(@) (CU^(+2)//Cu) - E^(@) (Al^(+3)//Al) = 2V` `rArr E^(@) (Al^(+3)//Al) = -2 + 0.34 = -1.66V`

Discussion

27.	Aluminium crystallizes in an fcc structure. Atomic radius of the metal is 125 pm. What is the length of the edge of the unit cell ?
Answer» Solution : For a face centred CUBIC CLOSE PACKED structure, Radius (r) = `a// 2sqrt2` `:.` LENGTH of the side of the unit cell, `a = 4/sqrt2 r = 2sqrt2 r = 2xx 1.4142 xx 125 xx 10^(-12) m = 3.535 xx 10^(-10) m` = 353.5 pm

Discussion

28.	Aluminium crystallizes in an fcc structure. Atomic radius of the metal is 125 pm. How many such unit cells are there in 1 m^3 of aluminium?
Answer» Solution :Volume of ONE UNIT cell = `a^3 = (3.54 xx 10^(-10))^3 m^3 = 4.436 xx 10^(-29) m^3` Number of unit cells in 1.0 `m^3` of Al (1.0 m) = `((0.1 m^3))/((4.436 xx 10^(-29) m^3))=2.25 xx 10^(28)`

Discussion

29.	Aluminium crystallizes in an fcc structure. Atomic radius of the metal is 125 pm. Calculate the edge length of the unit cell of the metal.
Answer» SOLUTION :`a = 2 sqrt(2) R` `a = 2 sqrt(2) xx 125` a = 353.5 pm

Discussion

30.	Aluminium crystallizes in a face-centred cubic unit cell with an edge length of 4.094 A. Calculate the approximate Avogadro constant.
Answer» ANSWER :`5.83 XX 10^(23)`

Discussion

31.	Aluminium crystallizes in an FCC structare. Atomic radius of the metal is 125pm. Calculate the edge length of unit cell of the metal.
Answer» SOLUTION :The RELATIONSHIP between a and R (RADIUS of the SPHERE) is `a=2sqrt2xxr=2sqrt2xx125="353.5pm"`

Discussion

32.	Aluminium crystallizes in a cubic lattice with an edge of 404 pm and density of metal is 2.70 g/ cm^(3). What type of cubic is formed by aluminium ?
Answer» Solution : If there is "n" aluminium atoms per unit cell : `Density (rho)=(NM)/(N_(A)a^(3))` `implies`2.70=`(nxx270)/(6.023xx10^(23)(4.04xx10^(-8)cm))^(3)` `impliesn=6.023xx10^(22)(4.04xx10^(-8))^(-3)= 3097~~4` Hence, Al forms face-centred cubic (FCC) lattice. the coordination number of Al in FCC is 12 i.e., each Al atom has twelve other Al atoms in its nearest neighbour. An atom of aluminium (SOLID BLACK) PRESENT on the centre of middle vertical face is equidistant from the twelve adjoining atoms, hence, coordination number of an atom in FCC arrangement is twelve.

Discussion

33.	Aluminium crystallizes in a cubic close packed structure. Its metallic radius is 125pm. Calculate the edge length of unit cell.
Answer» SOLUTION :`"GIVEN,Radius (r ) = 125 pm"` `"Edge LENGTH of UNIT cell (a)"=?` Since aluminium crystallizes in Face CENTERED cubic `r=(asqrt2)/(4)(or) r=(a)/(2sqrt2)` `a=rxx2xxsqrt2` `=125xx2xx1.414` `a=353.5" pm"`

Discussion

34.	Aluminium crystallizes in a ccp structure. Its metallic radius is 125pm. The number of unit cells in 1.00 cm^(3) of Al are
Answer» `2.27 xx 10^(22)` `1.13 xx 10^(20)` `2.26 xx 10^(26)` `1.13 xx 10^(23)` Solution :For ccp STRUCTURE `a = 2 sqrt(2) R = 2 xx 1.414 xx 125 = 353.5 `pm or `353.5 xx 10^(-10) `cm Volume of unit CELL `= ( 353.5 xx 10^(-10))^(3)` `= 4.42 xx 10^(23) cm^(3)` No. of unit cells in 1 `cm^(3)`

Discussion

35.	Aluminium crystallises in a cubic close-packed structure. Its metallic radius is 125 pm. (i) What is the length of the side of the unit cell ? (ii) How many unit cells are there in 1.00 "cm"^3 of aluminium ?
Answer» Solution :Aluminum CRYSTALLIZE in a cubic close-packed structure. Its metallic radius is 125 pm. (i) In a cubic close-packed structure the edge length `(a) = 2sqrt(2)r` `= 2 xx 1.41 xx 125` = 354 pm. (ii) Volume of UNIT cell `= a^3 = (354)^3 xx 10^(-30) "cm"^3` `therefore` Number of unit CELLS in `1 "cm"^3` of aluminium`= (1)/((354)^3 xx 10^(-30))` `= 2.25 xx 10^(22)`.

Discussion

36.	Aluminium crystallises in a cubic close-packed structure. Its metallic radius is 125 pm. (i) What is the length of the side of the unit cell ? (ii) How many unit cells are there in 1.00 cm^(3) of aluminium ?
Answer» Solution :(i) Cubic close - packing is the same as FACE - centred cubic. For fcc, `a=2sqrt2r = 2xx4.414xx125=354" PM"` (ii) Volum e of UNIT cell `=(354xx10^(-10)CM)^(3)=4.44xx10^(-23)cm^(3)` Number of unit cells in `1cm^(3)=(1)/(4.44xx10^(-23))=2.25xx10^(22)`

Discussion

37.	Aluminium crystallies in a cubic close packed structure. Radius of the atom in the metal is 125 pm. (i) What is the length of the side of the unit cell ? (ii) How many unit cells are there in 1 cm^(3) of aluminium ?
Answer» Solution :r = 125 pm = `125 xx 10^(-10)` CM (i) For ccp, edge length of unit cell, `a = (4R)/(sqrt(2))` `= (4 xx 125 xx 10^(-10))/(1.414)` = `353.60 xx 10^(-10)` cm `= 354 xx 10^(-10)` cm (ii) NUMBER of unit cells in 1 `cm^(3)` `= ("Total volume")/("Volume of 1 unit cell" (a^(3)))` `= (1 cm^(3))/((354 xx 10^(-10))^(3))` `= 2.254 xx 10^(22)` Unit cells

Discussion

38.	Aluminium containing alumina as impurity can be refined by poling or not. Why?
Answer» SOLUTION :Aluminium containingaluminacannot be refined by poling. Aluminium is more ELECTROPOSITIVE , thushydrocarbonsreleased from green wood poles and CARBON cannot reduce ALUMINA.

Discussion

39.	Aluminium carbide reacts with water to give :
Answer» `C_2H_2` `C_2H_4` `CH_4` `C_2H_6` ANSWER :C

Discussion

40.	Aluminium can be prepared by:
Answer» ELECTROLYTIC REDUCTION of aluminia in presence of Cryolite & fluorspar. Reduction of `AlCl_3(s)` by potassium amalgam. Reduction of aqueous SOLUTION of `Al_(2)(SO_(4))_(3) (aq)` by zinc metal Thermal decomposition of aluminium oxide. Solution :N//A

Discussion

41.	Aluminium becomes passive in nitric acid because it :
Answer» IS a noble metal Has POSITIVE REDUCTION potential Forms a thin film of oxide None of these Answer :C

Discussion

42.	Aluminium appears like gold when it is mixed with :
Answer» `50% NI` `90% CU` `90% Sn` `50% CO` Answer :B

Discussion

43.	Aluminiumamalgam usedas areducingagent,isobtainedby :
Answer» Dippingaluminiumfoilinmercuricchloridesolution Mixingaluminiumnitratewithmercury mixingaluminium nitratewithmercuricoxide addingmercurry to aluminiumchloridesolution ANSWER :A

Discussion

44.	Alumininum is prepared in large quantities by
Answer» HEATING cryolite in alimited equantity of air Reducing alumininum OXIDE with coke Reducing ALUMINIUM oxide with sodium Electrolysing alumininum oxide DISSOLVED in fused electrolyte Answer :D

Discussion

45.	Alumina with considerable impurity of silica is purified by .......
Answer» Hall-Heroult process Hoope's process Serpeck's process Bayer's process SOLUTION :In Serpeck.s process, the silica is REDUCED to Si which volatises of at this TEMPERATURE. The reduction is CARRIED out by carbon. `SiO_2 + 2C to Si + 2CO`

Discussion

46.	Alumina on heating with carbon in nitrogen atmosphere gives :
Answer» AL +CO `Al+CO_2` ALN +CO `Al+CO+N_2` ANSWER :C

Discussion

47.	Alumina may be converted into anhydrous aluminium chloride by:
Answer» Heating it with CONC. HCl Heating in a CURRENT of DRY chlorine Heating it with rock salt Mixing it with CARBON and heating the MIXTURE in a current of dry chlorine Answer :D

Discussion

48.	Alumina is the nature of :
Answer» Acidic Basic Amphoteric Neutral Answer :C

Discussion

49.	Alumina is concentrated by dissolving in concentrated solution of NaOH and then by passing CO_2 through it. What is this process known as?
Answer» SOLUTION :LEACHING.

Discussion

50.	Alumina is __________.
Answer» `AL(OH)_(3)` `AlCl_(3)` `ALN` `Al_(2)O_(3)` ANSWER :D

Discussion

Explore topic-wise InterviewSolutions in Current Affairs.

Aluminium is most abundant in earth crust yet it is obtained from bauxite because

Aluminium is mainly extracted from :

Aluminium is extracted from alumina (Al_2O_3) by electrolysis of a molten mixture of

Aluminium is extracted from alumina (Al_(2)O_(3)) by electrolysis of a molten mixture of

Aluminium is extracted from alumina (Al_(2)O_(3)) by electrolysis of a molten mixture of ……….

Aluminium is extracted from alumina (Al_(2)O_(3)) by electrolysis of a molten mixture of :

Aluminium isextractedfromalumina (Al_2 O_3)byelectrolysisofa moltenmixture of

Aluminium is diagonally related to:

Aluminium is diagonally related to (in periodic table)

Aluminium (III) chloride froms a dimer because

Aluminium (III) chloride forms a dimer because :

Aluminium hydroxide, magnesium hydroxide, erythromycin, cimetidine, ranitidine.

Aluminium hydroxide is soluble in excess of sodium hydroxide forming the ion

Aluminium forms [AlF_(6)]^(3-)ion but boron does not form [BF_(6)]^(3-)ion.

Aluminium forms :

Aluminium does not react with :

Aluminium displaces hydrogen from dilute HCl whereas silver does not. The e.m.f. of a cell prepared by combining Al//Al^(3+) and Ag//Ag^(+) is 2.46V. The reduction potential of silver electrode is +0.80V. The reduction potential of aluminium electrode is

Aluminium displaces hydrogen from dilute HCl whereas silver does not. The e.m.f. of a cell prepared by combining Al//Al^(3+) and Ag//Ag^(+)is 2.46 V. The reduction potential of silver electrode is + 0.80 V. The reduction potential of aluminium electrode is

Aluminium displaces hydrogen from dilute HCl whereas silver does not. The e.m.f. of a cell prepared by combining Al//Al^(3+) and Ag//Ag^(+) is 2.46V. The reduction potential of silver electrode is +0.80V. The reduction potential of aluminium electrode.

Aluminium displaces hydrogen from acids but copper does not. A galvanic cell prepared by combining Cu//Cu^(2+) and Al//Al^(3+) has an e.m.f. of 2.0 V at 298 K. if the potential of copper electrode is +0.34V, that of aluminium is

Aluminium displaces hydrogen from acids, but copper does not. A galvanic cell prepared by combining Cu| Cu^(2+) and Al|Al^(3+) has an emf of 2.0 V at 298 K. If the potential of copper electrode is + 0.34 V, that of aluminium electrode is

Aluminium displaces hydrogen from dilute HCI whereas silver does not Thee.m.f. of a cell prepared by combiningAl/Al ^3+and Ag/Ag ^+is 2.46 V. The reduction potential of silver electrode is + 0.80 V. The reduction potential of aluminium electrode

Aluminium displaces hydrogen from acids, but copper does not. A galvanic cell prepared by combining Cu//Cu^(2+) and Al//Al^(3+)has an emf of 2.0 V at 298K. If the potential of copper electrode is +0.34V, that of Aluminium electrode is

Aluminium displaces hydrogen from acids, but copper does not. A galvanic cell prepared by combining Cu//Cu^(2+) and Al//Al^(3+) has an emf of 2.0V at 298K. If the potential of copper electrode is +0.34V and that of Aluminium electrode is

Aluminium displaces hydrogen from acids but copper does not. A galvainc cell prepared by combining Cu//Cu^(2+) and Al//Al^(3+) has an emf of 2.0 V at 298 K. If the potential of copper electrode is +0.34 then that of the aluminiumelectrode is:

Aluminium displaces hydrogen from acid, but copper does not. A Galvanic cell prepared by combining Cu//Cu^(2+) and Al//Al^(3+) has an emf of 2.0V at 298K. If the potential of copper electrode is 0.34V, that of aluminium electrode is

Aluminium crystallizes in an fcc structure. Atomic radius of the metal is 125 pm. What is the length of the edge of the unit cell ?

Aluminium crystallizes in an fcc structure. Atomic radius of the metal is 125 pm. How many such unit cells are there in 1 m^3 of aluminium?

Aluminium crystallizes in an fcc structure. Atomic radius of the metal is 125 pm. Calculate the edge length of the unit cell of the metal.

Aluminium crystallizes in a face-centred cubic unit cell with an edge length of 4.094 A. Calculate the approximate Avogadro constant.

Aluminium crystallizes in an FCC structare. Atomic radius of the metal is 125pm. Calculate the edge length of unit cell of the metal.

Aluminium crystallizes in a cubic lattice with an edge of 404 pm and density of metal is 2.70 g/ cm^(3). What type of cubic is formed by aluminium ?

Aluminium crystallizes in a cubic close packed structure. Its metallic radius is 125pm. Calculate the edge length of unit cell.

Aluminium crystallizes in a ccp structure. Its metallic radius is 125pm. The number of unit cells in 1.00 cm^(3) of Al are

Aluminium crystallises in a cubic close-packed structure. Its metallic radius is 125 pm. (i) What is the length of the side of the unit cell ? (ii) How many unit cells are there in 1.00 "cm"^3 of aluminium ?

Aluminium crystallises in a cubic close-packed structure. Its metallic radius is 125 pm. (i) What is the length of the side of the unit cell ? (ii) How many unit cells are there in 1.00 cm^(3) of aluminium ?

Aluminium crystallies in a cubic close packed structure. Radius of the atom in the metal is 125 pm. (i) What is the length of the side of the unit cell ? (ii) How many unit cells are there in 1 cm^(3) of aluminium ?

Aluminium containing alumina as impurity can be refined by poling or not. Why?

Aluminium carbide reacts with water to give :

Aluminium can be prepared by:

Aluminium becomes passive in nitric acid because it :

Aluminium appears like gold when it is mixed with :

Aluminiumamalgam usedas areducingagent,isobtainedby :

Alumininum is prepared in large quantities by

Alumina with considerable impurity of silica is purified by .......

Alumina on heating with carbon in nitrogen atmosphere gives :

Alumina may be converted into anhydrous aluminium chloride by:

Alumina is the nature of :

Alumina is concentrated by dissolving in concentrated solution of NaOH and then by passing CO_2 through it. What is this process known as?

Alumina is __________.