1.

Aluminium displaces hydrogen from acid, but copper does not. A Galvanic cell prepared by combining Cu//Cu^(2+) and Al//Al^(3+) has an emf of 2.0V at 298K. If the potential of copper electrode is 0.34V, that of aluminium electrode is

Answer»

`-1.66V`
`+1.66V`
`-2.3V`
`+2.34V`

Solution :EMF = `E^(@)` (cathode) `-E^(@)` (ANODE)
`=E^(@) (CU^(+2)//Cu) - E^(@) (Al^(+3)//Al) = 2V`
`rArr E^(@) (Al^(+3)//Al) = -2 + 0.34 = -1.66V`


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