1.

Aluminium displaces hydrogen from acids, but copper does not. A galvanic cell prepared by combining Cu//Cu^(2+) and Al//Al^(3+) has an emf of 2.0V at 298K. If the potential of copper electrode is +0.34V and that of Aluminium electrode is

Answer»

`-2.3V`
`+2.34V`
`-1.66V`
`1.66V`.

Solution :Cellrepresentation is
`Al|Al^(2+)||C u^(2+)|CU`
`E_("CELL")=E_(Cu^(2+))+_(//Cu)-E_(Al^(3))+_(//Al)`
`2.0V== 0.34V-E_(Al^(3+)//Al)`
`E_(Al^(3+)//Al)=0.34V-2.0V=-1.66V`


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