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Aluminium crystallizes in an fcc structure. Atomic radius of the metal is 125 pm. How many such unit cells are there in 1 m^3 of aluminium? |
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Answer» Solution :Volume of ONE UNIT cell = `a^3 = (3.54 xx 10^(-10))^3 m^3 = 4.436 xx 10^(-29) m^3` Number of unit cells in 1.0 `m^3` of Al (1.0 m) = `((0.1 m^3))/((4.436 xx 10^(-29) m^3))=2.25 xx 10^(28)` |
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