1.

Aluminium displaces hydrogen from acids, but copper does not. A galvanic cell prepared by combining Cu| Cu^(2+) and Al|Al^(3+) has an emf of 2.0 V at 298 K. If the potential of copper electrode is + 0.34 V, that of aluminium electrode is

Answer»

`-2.3 V `
`+2.34V`
`-1.66` V
`1.66` V

Solution :`Al |Al^(3+) ||Cu^(2+) |Cu`
`E_(cell)^(@) = E_((Cu^(2+) |Cu))^(@) - E_((Al^(3+)|Al))^(@)`
`2.00 = 0.34 - E_((Al^(3+)|Al))^(@)`
`THEREFORE E^(@) (Al^(3+)|Al) = 0.34 - 2.0 = -1.66 V`


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