Explore topic-wise InterviewSolutions in Current Affairs.

This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.

1.

The correct difference between first- and second -order reactions is that-

Answer»

a first ORDER REACTION can be catalysed , a second order reaction cannot be catalysed
the half-life of a first order reaction does not depend on `[A]_(0)`, the half-life of a second order reaction does depend on `[A]_(0)`.
the RATE of a first order reaction does not depend on reactant concentrations, the rate of a second order reaction does depend on reactant concentrations
the rate of a first order reaction does depend on reactant concentrations , the rate of a second-order reaction does not depend on reactant concentrations

Answer :B
2.

The correct difference between first and second order reaction is that

Answer»

The rate of a FIRST order reaction does not DEPEND on reactant CONCENTRATION , the rate of a second order reaction does depend on reactant concentrations
The half life of a first order reaction does not depend on `[A]_(0)` : the half life of a second order reaction does depend on `[A]_(0)`
A first order reaction can be catalyzed , a second order reaction cannot be catalyzed
The rate of a first order reaction does depend on reactant concentrations , the rate of a second order reaction does not depend on reactant concentrations

Solution :`(t_(1//2)) 1^(st)` order = Independent of concentration
`(t_(1//2)) 2^(nd)` order `prop (1)/([A]_(0))`
3.

The correct difference between first and second order reaction is that……….

Answer»

the rate of a first-ORDER reaction does depend on reactant concentration ,the rate of a SECOND-order reaction does not depend on reactant concentrations
the rate of a first-order reaction does not depend on reactant concentration ,the rate of a second-order reaction does depend on reactant concentrations
a first-order reaction can be CATALYZED,a second -order reacion cannot be catalyzed
the half-LIFE of a first-order reaction does not depend on `[A]_(0)` the half-life of a second-order reaction does depend on `[A]_(0)`

Solution :Half life time of a
First life order reaction `(t_(1)/(2))=(0.693)/(K)`
Half life time of a
Second order reaction `(t_(1)/(2)),t_((1)/(2))prop(1)/([A_(o)])`
4.

The correct descending order of the heat liberated(in kJ) during the neutralisation of the acids CH_3COOH (W), HF (X), HCOOH(Y) and HCN (Z) under identical conditions is (Given K of CH_3COOH=1.8xx10^(-5) , HCOOH = 1.8xx10^(-4) , HCN =4.9xx10^(-10) and HF=3.2xx10^(-4) )

Answer»

`Y gt X gt Z gt W`
`X gt Y gt W gt Z`
`W gt X gt Y gt Z`
`Z gt W gt Y gt X`

Solution :From the `K_a` values, strength of acids is in the order: HF `gt` HCOOH `gt` `CH_3COOH` `gt` HCN
Stronger the ACID, higher is the heat liberated during the neutralisation as lesser energy is used for ionisation.
`therefore`The CORRECT order of heat liberated is
`X gt Y gt W gt Z`
5.

The correct description of bonds in C_2H_2 Molecule is:

Answer»

`sp^3d`
`sp^3`
`sp^2`
sp

Answer :B
6.

The correct decreasing order ofoxidation number ofoxygen in compounds BaO_2, O_3, KO_2 and OF_2 is :

Answer»

`BaO_2 GT KO_2 gt O_3 gt OF_2`
`OF_2 gt O_3 gt KO_2 gt BaO_2`
`KO_2 gt OF_2 gt O_3 gt BaO_2`
`BaO_2 gt O_3 gt OF_2 gt KO_2`

SOLUTION :(B) OXIDATION no. of O are+2,0,-1/2 and- I RESPECTIVELY
7.

The correct decreasingorder of SN^(1) reactivity of the folliwng is: I. PhCH_(2)X. II. CH_(2) = CHCH_(2)X III. Me_(2)CHX, IV. C_(2)H_(5)X

Answer»

`(I) GT (II) gt (III) gt (IV)`
`(IV) gt (III) gt (II) gt (I)`
`(II) gt (I) gt (III) gt (IV)`
`(IV) gt (III) gt (I) gt (II)`

Solution :`SN^(1)` reactivity order is:
BENZYL gt ALLYL `gt 2^(@) gt 1^(@)` halide.
8.

The correct decreasing order of preference of functional groups during the IUPAC nomenclature of polyfunctional compounds is:

Answer»

` -COOH,-SO_(3)H,-CONH_(2),-CHO`
`-SO_(3)H,-COOH,-CONH_(2),-CHO`
`-CHO,-COOH,-SO_(3)H,-CONH_(2)`.
`-CONH_(2),-CHO,-SO_(3)H,-COOH`

Answer :A
9.

The CORRECT decreasing order of energy releasedwhen an electron is added to neutral gaseous halogens is _________.

Answer»

`F GT CL BR gt I`
`Cl gt Br gt F gt I`
` F gt Br gt Cl gt I`
`Cl gt F Br gt I`

ANSWER :D
10.

The correct decreasing order of calorific values is

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`C_(2)H_(2)gtC_(4)H_(10)gtC_(3)H_(8)gtC_(2)H_(4)`
`C_(4)H_(10)gtC_(3)H_(8)gtC_(2)H_(4)gtC_(2)H_(2)`
`C_(2)H_(4)gtC_(3)H_(8)gtC_(4)H_(10)gtC_(2)H_(2)`
`C_(3)H_(8)gtC_(2)H_(4)gtC_(4)H_(10)gtC_(2)H_(2)`

ANSWER :D
11.

The correct decreasing order of basic strength of the following species is_____ H_(2)O,NH_(3),OH^(-),NH_(2)^(-)

Answer»

`NH_(2)^(-) GT OH^(-) gt NH_(3) gt H_(2)O`
`OH^(-) gt NH_(2)^(-) gt H_(2)O gt NH_(3)`
`NH_(3) gt H_(2)O gt NH_(2)^(-) gt OH^(-)`
`H_(2)O gt NH_(3) gt OH^(-) gt NH_(2)^(-)`

Solution :ANILINE is a weaker BASE than `NH_(3)` is more basic than `H_(2)O`, therefore, `NH_(2)^(-)` is a stronger base than `OH^(-)`. Thus, the decreasing order of basic strength is option (a), i.e., `NH_(2)^(-) gt OH^(-) gt NH_(3) gt H_(2)O`.
12.

The correct decreasing order of basic strength of the following species is ….. H_(2)O, NH_(3), OH^(-),NH_(2)^(-)

Answer»

`NH_(2)^(-)GT OH^(-) gt NH_3gtH_2 O`
`OH^(-)gt NH_(2)^(-)gt H_2 Ogt NH_3`
`NH_(3) gt H_2 Ogt NH_(2)^(-)gt OH^(-)`
`H_(2) O gtNH_(3) gt OH^(-) gt NH_(2)^(-)`

Solution :`H_2 O` is a STRONGER ACID than `NH_3` or `NH_3`is more basic than water. Conjugate base of WEAKER acid `NH_3`, i.e., `NH_(2)^(-)`is a stronger basethan the conjugate base of stronger acid `(H_2 O)` i.e, `OH^(-)`.
Hence, the order of basic strength is `NH_(2)^(-)gtOH^(-)gtNH_3gtH_2 O`
13.

The correct decreasing order of basic strength of the following species is: H_(2) O, NH_3 , OH^(-) ,NH_(2)^(-)

Answer»

`NH_(2)^(-)gt OH^(-) gt NH_3gtH_2 O`
`OH^(-)gt NH_(2)^(-)gt H_2 OGT NH_3`
`NH_(3) gt H_2 Ogt NH_(2)^(-)gt OH^(-)`
`H_(2) O gtNH_(3) gt OH^(-) gt NH_(2)^(-)`

SOLUTION :`H_2 O` is a stronger acid than `NH_3` or `NH_3`is more basic than WATER. Conjugate base of weaker acid `NH_3`, i.e., `NH_(2)^(-)`is a stronger basethan the conjugate base of stronger acid `(H_2 O)` i.e, `OH^(-)`.
Hence, the order of basic STRENGTH is `NH_(2)^(-)gtOH^(-)gtNH_3gtH_2 O`
14.

The correct decreasing order of acidity of nitro alkane is ……………….. .

Answer»




SOLUTION :
15.

The correct decreasing order of acidic character of following phenols is

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(`AAK_MCP_36_NEET_CHE_E36_019_A01`)

ANSWER :C
16.

The correct decreasing order of 1^st ionizationenergy of 13-group elements is

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`BgtAlgtGagtIngtTl`
`BgtTlgtGagtAlgtIn`
`BgtGagtAlgtTlgtIn`
`AlgtBgtGagtIngtTl`

ANSWER :B
17.

The correct corresponding order of names of four aldoses with configuration given below respectively, is

Answer»

L-erythrose, L- threose, D- erythrose, D-threose
D-threose, D-erythose, L- threose, L- erythrose
L-erythrose, L-threose, D- erythrose, D-threose
D- erythrose, D-threose, L- erythrose, L- threose

Solution :The structure of an aldotetrose is
`HOCH_(2) (CHOH)_(2) CH_(2) OH`
It contains two different ASYMMETRIC `C` ATOMS RESULTING into two PAIRS of enantiomers (four optical isomess):
18.

The correct decreasing order for the acidic strength of oxides of nitrogen is

Answer»

`N_(2)O_(5)gtN_(2)O_(3)gtN_(2)O_(4)gtNOgtN_(2)O`
`NOgtN_(2)OgtN_(2)O_(3)gtN_(2)O_(4)gtN_(2)O_(5)`
`N_(2)OgtNOgtN_(2)O_(3)gtN_(2)O_(4)gtN_(2)O_(5)`
`N_(2)O_(5)gtN_(2)O_(4)gtN_(2)O_(3)gtNOgtN_(2)O`

SOLUTION :`N_(2)O_(5)gt N_(2)O_(4)gtN_(2)O_(3)gtNOgtN_(2)O`
19.

The correctcorrespondingorderof namesof four aldoeswithconfigurationgivenbelowRespectively is ,

Answer»

L- ERYTHROSE, L - THREOSE , L- Erythrose , D- Threose
D - Threose , D - Erythrose , L - Threose , D- Erythose
L - Erythrose , L - Threose , D - Erythrose , D - Threose
D - Erythrose ,D - Throese , L - Erythrose ,L - Threose

ANSWER :D
20.

The correct corresponding order names of four aldoses with configuration given below. {:(""CHO),("|"),(H-C-OH),("|"),(H-C-OH),("|"),(""CH_(2)OH):}""{:(""CHO),("|"),(" "HO-C-OH),("|"),(""H-C-OH),("|"),(""CH_(2)OH):} {:(""CHO),("|"),(" "OH-C-OH),("|"),(" "OH-C-OH),("|"),(""CH_(2)OH):}""{:(""CHO),("|"),(""H-C-OH),("|"),(" "OH-C-OH),("|"),(""CH_(2)OH):} respectively, is :

Answer»

L-erythrose, L-threose, D-erythrose, D-threose
D-erythrose, D-threose, L-erythrose, L-threose
L-erythrose, L-threose, L-erythrose, D-threose
D-threose, D-erythrose, L-threose, L-erythrose

SOLUTION :D-erythrose, D-threose, L-erythrose, L-threose
21.

The correct combination of names for isomeric alcohols with molecular formula C_(4)H_(10)O is/are

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tert-butanol and 2-methylpropan-2-ol
tert-butanol and 1,1-dimethylethan-1-ol
n-butanol and butan-1-ol
isobutyl alcohol and 2-methylpropan-1-ol

Solution :OPTION (b) is WRONG since 1,1-dimethylethan-1-ol is neither a COMMON nor an IUPAC name. thus, option (a,c,d) are CORRECT.
22.

The correct compounds statement is /are :

Answer»

`X is CH_3-oversetoverset(O)(||)C-Oph`

S is `3^@` amine
Y and Z can be DISTINGUISHED by LUCAS test

Solution :
23.

The correct configuration of the compound is ……

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(2R, 3R)
(2R, 3S)
(2S, 3R)
(2S, 3S)

ANSWER :D
24.

The correct combination is

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II,III,R
II,IV,P
II,II,S
IV,I,P

Answer :D
25.

The correct combination of IV,

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<P>(IV) (III) (P)
(IV) (iv) (Q)
(IV) (i) (P)
(IV)(iv) (P)

ANSWER :A
26.

The correct combination is

Answer»

I,III,S
II,IV,Q
III,IV,Q
IV,II,P

Answer :C
27.

The correct combination in which the reaction proceeds through radical intermediate is/are :

Answer»

<P>(I)(i)(S)
(II)(ii)(P)
(III)(iii)(Q)
(IV)(iii)(R)

SOLUTION :
28.

The CORRECT combination is :

Answer»

<P>(I) (II) (P)
(I) (i) (P)
(I) (ii) (R )
(II) (ii) (P)

ANSWER :A
29.

The CORRECT combination is :

Answer»

(II) (i) (Q)
(II) (III) (S)
(II) (iii) (R )
(III) (IV) (Q)

Answer :C
30.

The correct code for stability, of oxidation states for given cations is: (i) Pb^(2+) gt Pb^(4+) ,Tl^(+) lt Tl^(3+) (ii) Bi^(3+) lt Sb^(3+) , Sn^(3+) lt Sn^(4+) (iii) Pb^(3+) gt Pb^(4+),Bi^(3+) gt Bi^(3+) (iv) Tl^(3+) lt ln^(3+), Sn^(2+) gt Sn^(4+) (v) Sn^(2+) lt Pb^(2+) , Sn^(4+) gt Pb^(4+) (vi) Sn^(2+) lt Pb^(2+), Sn^(4+) lt Pb^(4+)

Answer»

V and VI
I, III and VI
III and V
II and IV

Answer :C
31.

The correct combination for a titration in which conductance at equivalent point is lower than initial

Answer»

(I)(II)(Q)
(I)(iii)(S)
(III)(IV)(R)
(IV)(ii)(S)

SOLUTION :NA
32.

The correct combination from the following given statements about chemisorption I) It is unilayered adsorption II) It is irreversible and takes place slowly III) It occurs rapidly The correct combination is

Answer»

Both I and II are CORRECT
Both II and III are correct
Both I and III are correct 
 All are correct 

ANSWER :A
33.

The CORRECT combination among the following is:

Answer»

<P> (IV) (III) (P)
(IV) (iii) (P)
 (III) (II) (Q)
(II)(iv) (S)

Answer :B
34.

The correct charge on an co-ordination number of 'Fe' in K_(3)[Fe(CN)_(6)] is

Answer»

`+2, 4`
`+3,6`
`+2,6`
`+3,3`

Solution :(a) `K_(3) [Fe(CN)_(6)]`
O.N. of K=+1
O.N. of Fe = x
O.N. of CN=`-1`
Sum=O
`K_(3)Fe(CN)_(6)`
`(3 XX 1) + (x) + 6(-1)=0`
`x=+3`
(b) `6CN^(-)` ions are attached to Fe and hence C.N. of Fe=6
35.

The correct order of boiling points of the given hydrides of 16^(th) group elements is

Answer»

`H_(2) O GT H_(2) S gt H _(2) Se gt H _(2) TE`
`H_(2)S gt H_(2)O gt H_(2) Te gt H_(2) Se`
`H_(2) O gt H_(2) Te gt H _(2) Se gt H_(2)S`
`H_(2)O gt H_(2) S gt H_(2) Se gt H_(2) Te`

ANSWER :C
36.

The correct basicity order of thefollowing lanthanoid ions is

Answer»

`La^(3+) gt Lu^(3+) gt Ce^(3+) gt Eu^(3+)`
`Ce^(3+) gt Lu^(3+) gt La^(3+)gt Eu^(3+)`
`Lu^(3+) gt Ce^(3+) gt Eu^(3+) gt La^(3+)`
`Lu^(3+) gt Ce^(3+) gt Eu^(3+) gt Lu^(3+)`

Solution :It is the correct order and is dueto Lanthanoid CONTRACTION .
For DETAILS, consult section 11.
37.

The correct bhasicity order of the folloiwing lanthanide ions is

Answer»

`LA^(3+) gt LU^(3+) gt CE^(3+) gt Eu^(3+)`
`Ce^(3+) gt Lu^(3+) gt La^(3+) gt Eu^(3+)`
`Lu^(3+) gt Ce^(3+) gt Eu^(3+) gt La^(3+)`
`La^(3+) gt Ce^(3+) gt Eu^(3+) gt Lu^(3+)`

Answer :D
38.

Explain, why. alkyl halides have higher boiling points than the corresponding hydrocarbons?

Answer»

ALKYNE GT ALKANE gt ALKENE
Alkane gt Alkene gt Alkyne
Alkne gt Alkene gt Alkane
Alkene gt Alkyne gt Alkane

Answer :B
39.

The correct ascending order of adsorption of the following gases on the same mass of charcoal at the same temperature and pressure is

Answer»

`CH_(4)lt H_(2)SO_(2)`
`H_(2)lt CH_(4)lt SO_(2)`
`SO_(2)lt CH_(4)lt H_(2)`
`H_(2)lt SO_(2)lt CH_(4)`

SOLUTION :More easily a gas is liquefiable, higher is its cirtical TEMPERATURE and greater is its adsorption. Critical temepratures in K are
`{:(H_(2)lt " "CH_(4)lt " "SO_(2)), (33.2 " "190.6 ""430.3):}`
or ease of liquefaction is `H_(2)lt CH_(4) lt SO_(2).`
Hence, ascending ORDER of adsorption is `H_(2) lt CH_(4)lt SO_(2).`
40.

The correct arrangement of following acids of phosphorus in the increasing order of oxidation state of phosphorous is

Answer»

HYPOPHOSPHORIC acid LT orthophosphorous acid lt pyrophosphoric acid
HYPOPHOSPHOROUS acid lt pyrophosphoric acid lt orthophosphorous acid
Pyrophosphoric acid lt hypophosphrous acid lt orthophosphorous acid
Pyrophosphoric acid lt orthophosphorousacid lt hypophosphorous acid

ANSWER :1
41.

The correct arrangement for the ions in the increasing order of their radii is

Answer»

`NA^(+), Cl^(-), Ca^(2+)`
`Ca^(2+), K^(+), S^(2-)`
`Na^(+), Al^(3+), Be^(2+)`
`Cl^(-), F^(-), S^(2-)`

Solution :
The species `Ca^(2+), K^(+)` and `S^(2-)` are isoelectronic.
For isoelectronic ions, the radius decreases as the nuclear charge increases.
Hence, the increasing order of their RADII is
`Ca^(2+) LT K^(+) S^(2-)`
42.

The correct arrangement of the species in the decreasing order of the bond length between carbonand oxygen in them is

Answer»

`CO, CO_(2), HCO_(3)^(-), CO_(3)^(2-)`
`CO_(2), HCO_(3)^(-), CO, CO_(3)^(2-)`
`CO_(3)^(2-), HCO_(3)^(-), CO_(2), CO`
`CO, CO_(3)^(-), CO_(2), HCO_(3)^(-)`

Answer :C
43.

The correct answer upto required number of significant figures of 0.083 x 10.1 is :

Answer»

0.8383
0.84
0.83
0.083

Solution :`0.083 XX 10.1= 0.8383= 0.84 ` (UPTO 2 SIGNIFICANT DIGITS)
44.

The correct answer upto proper number of significant digits : (2.50 x 10^(-2) km) + (3.7 xx 10^2 cm)is :

Answer»

6.20 KM
28.7 m
49.50 CM
cannot be calculated

Solution :`(2.50 XX 10^(-2) km)+ (3.7 xx 10^2 cm)`
`(25.0 m) + (3.7 m) = 28.7 m `
45.

The correct answer upto appropriate number of significant figures for 50.0 x 0.0160 + 19 is:

Answer»

19.8
19
20.
`20.0`

SOLUTION :`50.0 XX 0.0160= 0.800`
`0.800 + 19 = 19.8 " or" 20`
46.

The correct answer of 126/8.0 is (upto proper number of significant figures) :

Answer»

15.75
16
15.7
none of these

Solution :`(126)/(8.0) = 15.75 = 16` (UPTO 2 SIGNIFICANT DIGITS) . It may be noted that exact numbers (e.g. 126) have no effect on the number of significant figures .
47.

The correct acidity order of the following is

Answer»

IIIgtIVgtIIgtI
IVgtIIIgtIgtII
IIIgtIIgtIgtIV
IIgtIIIgtI

Solution :
Carboxylic acids are more ACIDIC than phenols (exception as pictric acid which is a PHENOL) Electron withdrawing groups exerts acid -strengthening effect while Electron supplying group EXERT acid -WEAKENING effect. The -I effect of Cl of DOMINATING over its +R effect.
48.

The correct acidic strength order of the following compounds is (a)CH_3COOH (b)H_2CO_5 ©C_2H_5OH (d)C_6H_5OH (e)H_2O (f) C_2H_2

Answer»

` agt B GT d gt e gt C gt f`
` a gt d gt c gt b gt e gt f`
` a gt b gt c gt d gt e gt f `
` a gt b gt d gt c gt e gt f`

ANSWER :A
49.

The correct –I effect order is:-

Answer»

`-NH_(2) lt -OH lt -F`
`-overset(o+)(N)R_(3) GT -C-=N gt -OH gt -C-=CH`

All of these

Answer :D
50.

The correcr order of ease of elimination of following groups in the E2 reaction is

Answer»

`-FGT -Clgt -BRGT -I`
`-IGT -Brgt -Fgt _Cl`
`-Igt -Brgt -Clgt -F`
`-Fgt -Clgt -Igt -Brgt`

Answer :C