1.

The correct charge on an co-ordination number of 'Fe' in K_(3)[Fe(CN)_(6)] is

Answer»

`+2, 4`
`+3,6`
`+2,6`
`+3,3`

Solution :(a) `K_(3) [Fe(CN)_(6)]`
O.N. of K=+1
O.N. of Fe = x
O.N. of CN=`-1`
Sum=O
`K_(3)Fe(CN)_(6)`
`(3 XX 1) + (x) + 6(-1)=0`
`x=+3`
(b) `6CN^(-)` ions are attached to Fe and hence C.N. of Fe=6


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