1.

The correct decreasingorder of SN^(1) reactivity of the folliwng is: I. PhCH_(2)X. II. CH_(2) = CHCH_(2)X III. Me_(2)CHX, IV. C_(2)H_(5)X

Answer»

`(I) GT (II) gt (III) gt (IV)`
`(IV) gt (III) gt (II) gt (I)`
`(II) gt (I) gt (III) gt (IV)`
`(IV) gt (III) gt (I) gt (II)`

Solution :`SN^(1)` reactivity order is:
BENZYL gt ALLYL `gt 2^(@) gt 1^(@)` halide.


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