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The correct descending order of the heat liberated(in kJ) during the neutralisation of the acids CH_3COOH (W), HF (X), HCOOH(Y) and HCN (Z) under identical conditions is (Given K of CH_3COOH=1.8xx10^(-5) , HCOOH = 1.8xx10^(-4) , HCN =4.9xx10^(-10) and HF=3.2xx10^(-4) ) |
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Answer» `Y gt X gt Z gt W` Stronger the ACID, higher is the heat liberated during the neutralisation as lesser energy is used for ionisation. `therefore`The CORRECT order of heat liberated is `X gt Y gt W gt Z` |
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