1.

The correct decreasing order ofoxidation number ofoxygen in compounds BaO_2, O_3, KO_2 and OF_2 is :

Answer»

`BaO_2 GT KO_2 gt O_3 gt OF_2`
`OF_2 gt O_3 gt KO_2 gt BaO_2`
`KO_2 gt OF_2 gt O_3 gt BaO_2`
`BaO_2 gt O_3 gt OF_2 gt KO_2`

SOLUTION :(B) OXIDATION no. of O are+2,0,-1/2 and- I RESPECTIVELY


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