Explore topic-wise InterviewSolutions in Current Affairs.

This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.

1.

Cesium bromide crystallizes in cubic arrangement like CsCl. Given the ionic radii of Cs^(+) and Br^(–) are 1.88 Å and 1.82 Å respectively, determine the packing fraction.

Answer»

SOLUTION : Here Cs+ ion is at body centre and Br– at the corners, therefore the relationship is
`2(r_(+)+r_(-))=sqrt(3a)`=2(1.88+1.82) Å,
Packing fraction `(phi)=(4)/(3)PI((r_(+)^(3)+r_(-)^(3))/(a^(3)))`
`=(4)/(3)pi((1.88^(3)+(1.82)^(3))/(4.27)^(3))=0.6807`
Discussion
2.

Celloboiseis obtained by

Answer»

COMPLETE HYDROLYSIS of cellulose
partial hydrolysis of cellulose
complete hydrolysis of glycogen
partial hydrolysis of raffinose

Answer :B
Discussion
3.

Certain unripe fruits like green apples and plums contain which acid?

Answer»

`H_2SO_4`
HCL
`CH_3COOH`
Malic ACID

ANSWER :D
Discussion
4.

Certain reactions regarding H_(2)SO_(4) are given H_(2)SO_(4)+NaOH to NaHSO_(4)+H_(2)O""H_(2)SO_(4) +2NaOH to Na_(2)SO_(4) +2H_(2)O C_(12)H_(22)O_(11)+H_(2)SO_(4) to 12C+11H_(2)O These reactions shows that

Answer»

it is a dibasic acid
CHARRING agent
it is a dehydrating agent
it can form two types of salts

Solution :`H_(2)SO_(4)` - Dibasic and forms two types of salts.
`NaOH+H_(2)SO_(4) to NaHSO_(4)+H_(2)O`
`NaHSO_(4)+NaOH to Na_(2)SO_(4) +H_(2)O`
It act as dehydrating agent with sucrose. It is CALLED CHARING of SUGAR.
`C_(12)H_(22)OH+H_(2)SO_(4) to 12C+11H_(2)O`
Discussion
5.

Celloboise contain

Answer»

1-4-`BETA`-GLUCOSIDE BOND
2-4-`ALPHA`-glucoside bond
1-4-`alpha`-glucoside bond
2-4-`beta`-glucoside bond

ANSWER :A
Discussion
6.

Certain quantity of current is passed through 2 voltameters connected in series and containing XSO_4 (aq) and Y_2SO_4 (aq) respectively. If the atomic masses of X and Y are in the ratio of 2 : 1 the ratio of the masses of Y liberated to that of X is

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`1:1`
`1:2`
`2:1`
`3:2`

Solution :(A) `X^(2+)+2e^(-)TOX,Y^(+)e^(-)toY`
2 `mol e^(-)` produce X=1 mol=1`xx` Mg
2 mol `e^(-)` produce Y=2`xxM//2=Mg`
HENCE, RATIO of the MASSES of Y:X is M:M or 1:1
Discussion
7.

Certain organic compound on combustion produces three gaseous oxides A, B and C. A and C turned lime water milky, B turned anhydrous CuSO_(4) blue and C truned K_(2)Cr_(2)O_(7) solution green. The elements present in organic compounds are

Answer»

C, N, O
C, H, S
C, H only
C, S only

Answer :B
Discussion
8.

Cellobiose on hydrolysis produces

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`ALPHA`-D-glucose
`alpha`-D-fructose
`BETA`-D-glucose
`beta`-D-fructose

Answer :C
Discussion
9.

Certain organic compound dissolves readily in H_2 SO_4 and also gives violet colour with FeCl_3 (aq). The compound is most likely

Answer»

Isopropy alcohol
VINY alcohol
ALLYL alcohol
BENZYL alcohol

Answer :B
Discussion
10.

Certain moles of CO_(2) is dissolved in excess of NaOH. The resulting solution is divided into two equal parts. One part needs 30 ml of 2.5 N HCl and other part needs 40 ml of 2.5 N HCl using phenolphthalein and methyl orange indicator respectively. The mass of CO_(2) dissolved is

Answer»

`2.5 XX 10^(-2)`
`5 xx 10^(-2)`
`10xx10^(-2)`
`1.5 xx 10^(-2)`

SOLUTION :N/A
Discussion
11.

Cellbiose contain

Answer»

C-1-C-4 GLYCOSIDIC bond
C-1-C-3 glycosidic bond
C-2-C-4 glycosidic bond
C-3-C-4 glycosidic bond

Answer :A
Discussion
12.

Certain nitrogeneous compound with molecular mass (180) shown an increase in its molecular mass to 348 after treatment with acetyl chloride. The number of possible -NH_(2) groups in the molecule is

Answer»

5
4
3
6

Solution :The chemical reaction INVOLVED is as follows :
`-NH_(2)+Cl-OVERSET(O)overset("||")(C)-CH_(3) underset(+CH_(3)CO)overset(-H)(rarr)-NH-overset(O)overset("||")(C)-CH_(3)`
NET INCREASE in mol. mass on acylation of one `-NH_(2)` GROUP = Mol. mass of `CH_(3)CO` group.
-At. mass of H
`=43-1=42`
Actual increase in mol. mass on acylation
`=348-180=168`
No. of group `CH_(3)-overset(O)overset("||")(C)-` added `=168//42=4`
the compound has `4-NH_(2)` groups.
Discussion
13.

Cell wall of bacteria is made of

Answer»

CELLULOSE
CELLOBIOSE
STARCH
GLYCOGEN

SOLUTION :Cellulose
Discussion
14.

Certain order of reaction rate constant is at 500K and 700K temperature are 0.02S^(-1) and 0.07S^(-1) respectively. Calculate Ea and K of this reaction.

Answer»


ANSWER :`E_a=18230.8J,A=1.61`
Discussion
15.

Certain groups like cyanides and nitrites possess two nucleophilic centres. What are they called ?

Answer»

SOLUTION :AMBIDENT nodeophiles
Discussion
16.

Cell voltages and half-cell potentials are often compeared under standard conditions called the standard state at a specified temperature (298K). The standard state requires all reagents to be pure with all gases at unit fugacity, all ions at unit activity and all electrical connections between half-cells to be made with platinum. Suppose following are half cell reaction, with respective emf (s) are -0.25 V and -0.3V. Cell reaction I underset("1 atm")(Pt(H_(2))|HCl) Cell reaction II underset("1 atm")(Pt(H_(2))|H_(2)SO_(4)) Zinc gives H_2 with H_2SO_4 and HCI but not with HNO3 because:

Answer»

zinc acts as OXIDIZING agent when reacts with `HNO_3`
`HNO_3` is a weaker ACID than `H_2SO_4 and HCI`
in electrochemical series zinc is above than HYDROGEN
`NO_(3)^(-)` is REDUCED in PREFERENCE to hydronium ion

Answer :D
Discussion
17.

Certaindicarboxylic acids spontaneously eliminate water when heated forming cycioc anhydirides. But for the reaction to be successfully. The cyclic anhydrides product must normally have a ring size of fivee or six members. There are two important reasons, first, the second carboxyl group can serve as the acid catalyst (by intramolecular proton transfer), as well as the nucleophile. And second, the high temperature involved reduce the need for catalyst. Which of the following dicarboxylic acid would you expect to form cyclic anhydride?

Answer»




ANSWER :C
Discussion
18.

Certain element has electronic configuration of [Xe] 4f^(14) 5d^(1) 6s^(2), then this element is….

Answer»

TRANS urenic element
Transitional element
Lanthanoid
Actinoids

Answer :C
Discussion
19.

Certain diseases are caused by enzyme defiencies. Explain giving one example.

Answer»

SOLUTION :Phenylketoneura and ALBINISM.
Discussion
20.

Cell voltages and half-cell potentials are often compeared under standard conditions called the standard state at a specified temperature (298K). The standard state requires all reagents to be pure with all gases at unit fugacity, all ions at unit activity and all electrical connections between half-cells to be made with platinum. Suppose following are half cell reaction, with respective emf (s) are -0.25 V and -0.3V. Cell reaction I underset("1 atm")(Pt(H_(2))|HCl) Cell reaction II underset("1 atm")(Pt(H_(2))|H_(2)SO_(4)) pH value of cell reaction Il is

Answer»

4.23
5.23
5.08
5.32

Answer :C
Discussion
21.

Certain chemical tests were perfoemd on the pain-relief drug ibuprofen. The results of these tests are given in the table below: Which one of the following functional groups do these results suggest that ibuprofen contains ?

Answer»




ANSWER :D
Discussion
22.

Cell voltages and half-cell potentials are often compeared under standard conditions called the standard state at a specified temperature (298K). The standard state requires all reagents to be pure with all gases at unit fugacity, all ions at unit activity and all electrical connections between half-cells to be made with platinum. Suppose following are half cell reaction, with respective emf (s) are -0.25 V and -0.3V. Cell reaction I underset("1 atm")(Pt(H_(2))|HCl) Cell reaction II underset("1 atm")(Pt(H_(2))|H_(2)SO_(4)) pH value of cell reaction I is

Answer»

4.23
5.23
5.08
5.32

Answer :A
Discussion
23.

Certain bimolecular reactions which follow the first order kinetics are called

Answer»

First ORDER REACTIONS
Unimolecular reactions
BIMOLECULAR reactions
PSEUDOUNIMOLECULAR reactions

Solution :It is the characteristic of pseudo-unimolecular reactions .
Discussion
24.

Cell reaction is spontaneous when

Answer»

`E_(red)^(@)` is negative
`E_(red)^(@)` is positive
`TRIANGLEG^(@)` is negative
`triangleG^(@)` is positive

Solution :In ORDER to have a SPONTANEOUS reaction`(TRIANGLE G^(@) lt 0)`
`E_(cell)^(@)` must be positivewhere
`E_(cell)^(@)=E_(cathode)^(@)-E_(anode)^(@) rarr triangle G_(cell)^(@)=- (triangle G^(@) lt 0)`
Discussion
25.

Certain bimolecular reaction which follow the first order kinetics are called…

Answer»

FIRST ORDER reactions
unimolecular reactions
bimolecular reactions
pseudounimolecular REACTION

ANSWER :D
Discussion
26.

Cerium (Z= 58) is an important nember of the lanthanoids . Which of the following statements about cerium is incorrect ?

Answer»

The `+4` oxidation state of CERIUM is not known in solutions
The `+3` oxidation state of cerium is more stable than the `+4` oxidation state
The common oxidation states of cerium are `+3 and +4`
Cerium (IV) ACTS as an OXIDIZING agent

Answer :B
Discussion
27.

Cell reaction : 2Fe_((S))+O_(2(g))+4H_((aq))^(+) to 2Fe_((aq))^(2+)+2H_(2)O_((l)),E^(@)=1.67V where [Fe^(2+)]=10^(-3)M,P(O_(2))=0.1 atm and pH=3, then what is cell potential at 25^(@)C ?

Answer»

1.47 V
1.77 V
1.87 V
1.57 V

Solution :1.57 V
Discussion
28.

Cerium (Z=58) belongs to

Answer»

s-block
p-block
d-block
f-block

Answer :D
Discussion
29.

Cell reactiomn is spontaneous when

Answer»

`E_("red")^(@)` is POSITIVE
`DeltaG^(@)` is NEGATIVE
`Delta G^(@)` is positive
`E_("red")^(@)` is negative

Solution : (B) `DeltaG^(@)` must be negative for spontaneity of cell.
Discussion
30.

Cerium (Z= 58) is an important member of the lanthanoids . Which of the following statements about cerium is incorrect ?

Answer»

The COMMON oxidation STATES of cerium are `+3` and `+4`
The `+3` oxidation state of cerium is more stable than `+4` oxidation state.
The `+4` oxidation state of cerium is not KNOWN in solution
Cerium (IV) acts as an oxidaizing agent.

Solution :`Ce^(4+)` EXISTIN solution THOUGH it tends to change to more stable `Ce^(3+)`
Discussion
31.

Cerium (Z = 58) is an important member of the lanthanoids. Which of the following statement about cerium is incorrect ?

Answer»

The + 4 oxidation state of cerium is not known in solutions.
The +3 oxidation state of cerium is more stable than +4 oxidation state.
The common oxidation states of cerium are +3 and +4.
Cerium (IV) acts as an OXIDISING agent.

Solution :In `KMnO_(4)`, the oxidation state of MN is +7, which is the HIGHEST possible oxidation state of Mn. Therefore, it cannot be further oxidisedby `O_(3)`.
Discussion
32.

Cell potential of Pt_((S))|H_(2)(g," 1 bar")|HCl_((aq))|AgCl_((S)) is 0.92 V. Concentration of HCl solution is 10^(-6) molal, then find out standard potential of (AgCl//AgCl^(-)) electrode. (at 298K temperature, ((2.303RT)/(F)=0.06V).

Answer»

0.94 V
0.20 V
0.76 V
0.40 V

Solution :Anode : `H_(2) to 2H^(+) +2overline(e)`
CATHODE : `([overline(e)+AgCl_((S))toAg_((S))+CL^(-)]xx2)/(2AgCl+H_(2) to 2H^(+)+2Ag+2Cl^(-))`
`E_(cell)=E_(cell)^(@)-(0.06)/(2)log[H^(+)]^(2)[Cl^(-)]`
`0.92=[E_(AgCl|AgCl^(-))^(@)-E_(H^(+)|H^(2))^(@)]-0.03log(10^(-6))^(2)(10^(-6))^(2)`
`0.92=[E_(AgCl|AgCl^(-))^(@)-0.03log10^(-24)]`
`E_(AgCl|AgCl^(-))^(@)=0.92+0.03(-24)`
`=0.20V`
Discussion
33.

Cerium (Z = 58) is an important member of lanthanoids. Which of the following statement about cerium is incorrect 1)

Answer»

The common oxidation states of CERIUM is + 3 and + 4
The + 3 oxidation STATE of cerium is more stable than the + 4 oxidation state
The + 4 oxidation state of cerium is not known in SOLUTIONS
Cerium (iv) acts as an oxidising AGENT

Answer :C
Discussion
34.

Cell potential for the following reaction is 0.03305V, then find out x at 298 K temperature. Zn|Zn^(2+)(0.1M)||Cd^(2+)(xM)|Cd

Answer»


ANSWER :0.01M
Discussion
35.

Cell membrane is chemically composed by

Answer»

phospholipids
fats
proteins
carbohydrates

Answer :A
Discussion
36.

Cerium shows most common oxidation state

Answer»

`+2,+4`
`+3,+4`
`+2,+3`
`+4,+5`

ANSWER :B
Discussion
37.

Cell equation : A+ 2B^(-) to A^(2+) + 2B , A^(2+) + 2e^(-) to AE^@ = +0.34V and log_(10)K = 15.6 at 300 K for cell reaction find E^@ for B^1 + e^- to B

Answer»

`0.80`
`1.26`
`-0.54`
`-10.94`

ANSWER :A
Discussion
38.

Cerium shows +4 oxidation state, in which of the following configuration ?

Answer»

`F^(0)`
`f ^(6)`
`f ^(7)`
`f ^(14)`

Answer :A
Discussion
39.

Cerium can show the oxidation state of +4 because :

Answer»

It resmbles ALKALI metals
It has very low VALUE of I.E.
Of its tendency to attain NOBLE gas configuration of xenon
Of its tendency to attain` f^@` configuration

Answer :D
Discussion
40.

Cell membrane contains

Answer»

Alternate LAYERS of phospholipid and coline
Double layers of phospholipid
Double layers of phospholipid with POLAR ENDS PROJECTED outside
Double layers of phospholipid with polar ends projected inside

Answer :B
Discussion
41.

Cell constant of a conductivity cell is ?

Answer»

Conductance/ SPECIFIC conductance
Specific conductance/ Resistance
Specific conductance/ Conductance
Specific conductance `XX (1000)/(N)`

Solution :CELL constant = `B = (l)/(a) = (k)/(R)`
Discussion
42.

Ceric ammonium sulphate and potassium permanganate are used as oxidising agents in acidic medium for oxidation of ferrous ammonium sulphate to ferric sulphate. The ratio of number of moles of cerric ammonium sulphate required per mole of ferrous ammonium sulphate to the number of moles of KMnO_(4) required per mole of ferrous ammonium sulphate, is

Answer»

`5.0`
`0.2`
`0.6`
`2.0`

Solution :`Fe^(2+)+Ce^(4+) rarr Fe^(3+)+Ce^(3+)`
`5 Fe^(2+)+Mn O_(4)^(-)+8 H^(+) rarr 5 Fe^(3+)+ Mn^(2+) + 4H_(2)O`
`:. ("MOLES of cerric ammonium sulphate")/("Moles of potassium permagnate")=1/(1//5)=5.0`
Discussion
43.

Cell equation : A+2B^(-) rarr A^(2+)+2B, A^(2+)+2e^(-) rarr A" "E^(@)=+0.34V " and " log_(10)K=15.6 at 300 K for cell reactions find E^(@) " for " B^(+)+e^(-) rarr B

Answer»

`0.80`
1.26
-0.54
-10.94

Answer :A
Discussion
44.

CeO_2 is present in:

Answer»

Crookes glass
Pyrex glass
Flint glass
All of these

Answer :A
Discussion
45.

Celestine is an ore of:

Answer»

Ba
Ca
Sr
Mg

Answer :C
Discussion
46.

CuSO_4 reacts with KCN solution forming a complex. Co-ordination number of copper in the complex is:

Answer»

2
3
4
6

Answer :C
Discussion
47.

Cellulose upon acetylation with excess acetic anhydride/H_(2)SO_(4) (catalytic) gives cellulose triacetate whose structure is

Answer»




Solution :CELLULOSE has `beta`-glycosidic linkages between `C_1` of ONE glucose UNIT and `C_(4)` of the other. It has three free OH GROUPS at 2,3 and 6 positions, therefore , `Oac` groups appear at `C_2,C_3and C_6` positions, Thus , option (a) is correct.
Discussion
48.

Ce^(4+) is stable . This is because of

Answer»

half-filled d-orbitals
all paired electrons in d-orbitals
empty orbital
FULLY filled d-orbital

Solution :The electronic configuration of Ce is
`Ce_(58) = [Xe] 4 f^(1) 5d^(1) 6s^(2)` (predicted)
or = `[Xe] 4f^(2) 5d^(0) 6s^(2) `(observed)
`Ce^(4+) = [Xe] 4 f^(0) 5d^(0) 6s^(0)`
Since , in +4 OXIDATION state , all (IE, 4f , 5d and 6s) orbitals are empty and Ce gains the stable configuration of nearest inert gas , `Ce^(4+)` is most stable .
Discussion
49.

Ce^(4+) ion is

Answer»

oxidising agent
REDUCING agent
redox agent
ONE of the above

Solution :We know that, `Ce^(4+)` is possible by loss of four electrons. It has tendency to revert into +3 oxidation state by gain of electrons. Hence all tetra POSITIVE ions are oxidising agents.
Discussion
50.

Cellulose trinitrate is used in preparation of :

Answer»

FOOD
Explosives
Rayon
None

ANSWER :B
Discussion