1.

Cell potential of Pt_((S))|H_(2)(g," 1 bar")|HCl_((aq))|AgCl_((S)) is 0.92 V. Concentration of HCl solution is 10^(-6) molal, then find out standard potential of (AgCl//AgCl^(-)) electrode. (at 298K temperature, ((2.303RT)/(F)=0.06V).

Answer»

0.94 V
0.20 V
0.76 V
0.40 V

Solution :Anode : `H_(2) to 2H^(+) +2overline(e)`
CATHODE : `([overline(e)+AgCl_((S))toAg_((S))+CL^(-)]xx2)/(2AgCl+H_(2) to 2H^(+)+2Ag+2Cl^(-))`
`E_(cell)=E_(cell)^(@)-(0.06)/(2)log[H^(+)]^(2)[Cl^(-)]`
`0.92=[E_(AgCl|AgCl^(-))^(@)-E_(H^(+)|H^(2))^(@)]-0.03log(10^(-6))^(2)(10^(-6))^(2)`
`0.92=[E_(AgCl|AgCl^(-))^(@)-0.03log10^(-24)]`
`E_(AgCl|AgCl^(-))^(@)=0.92+0.03(-24)`
`=0.20V`


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