1.

Ce^(4+) is stable . This is because of

Answer»

half-filled d-orbitals
all paired electrons in d-orbitals
empty orbital
FULLY filled d-orbital

Solution :The electronic configuration of Ce is
`Ce_(58) = [Xe] 4 f^(1) 5d^(1) 6s^(2)` (predicted)
or = `[Xe] 4f^(2) 5d^(0) 6s^(2) `(observed)
`Ce^(4+) = [Xe] 4 f^(0) 5d^(0) 6s^(0)`
Since , in +4 OXIDATION state , all (IE, 4f , 5d and 6s) orbitals are empty and Ce gains the stable configuration of nearest inert gas , `Ce^(4+)` is most stable .


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