Explore topic-wise InterviewSolutions in Current Affairs.

This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.

1.

Bromargyrite is a mineral of

Answer»

Pb
Sn
`I_2`
`AGBR`

ANSWER :D
Discussion
2.

Broadly speaking there are four types of stereisomers namely conformational isomers geometrical isomers, enantiomers and diastereomers.Although conformational isomers , have same configuration geometrical isomers have different atoms attached to each of the doubly bonded carbon atom, and enantiomers are due to chirality in the molecule Enantiomers are also known as optical isomers and diastereomers are those stereoisomers which are not enantiomers.In simple compound, number of stereoisomers.In chiral molecule is given by the reaction 2^n, where n is the number of dissimilar chiral carbon. Observe the following structures and answer the questions given below : The correct names for the above structure is :

Answer»

(2S, 3E)-3-penten-2-ol
(2R, 3E)-3-penten-2-ol
(2R, 3Z)-3-penten-2-ol
(2S, 3E)-3-penten-2-ol

Solution :In naming of the above compound, follow the rules for priority ORDER (E,Z) and (R,S) SYSTEM.
Discussion
3.

Briquettes used in modern vertical retort process are made up of _________.

Answer»

`ZnSO_(4) (40%) ` + CLAY (60%)
`ZnO (40%) +` coke/charcoal (60%)
ZNS (40%) + coke/charcoal (60%)
ZnS (40%) + clay (60%)

Answer :B
Discussion
4.

Bring out the following conversions: a. Toluene to Benzaldehyde b. Acetylene to acetaldehyde c. Formaldehyde to Methyl alcohol d. Propanoic acid to Acetic acid.

Answer»

Solution :The conversions are CARRIED out as under:

B. `underset("Acetylene")(HC-=CH)+H_(2)Ounderset(HgSO_(4))overset(H_(2)SO_(4))(to)CH_(3)-underset("Acetaldehyde")overset(O)overset(||)(C)-H`
c. `underset("Formaldehyde")(HCHO)overset(LiAlH_(4))(to)underset("Methyl alcohol")(CH_(3)OH)`
Discussion
5.

Bring out the following conversion: a. Acetyl chloride to Acetaldehyde b. Ethanol to Acetaldehyde c. Acetic acid to Acetaldehyde d. 2-Butanol to 2-Butanone.

Answer»

Solution :The conversions are achieved as under:
a. `UNDERSET("Acetyl chloride")(CH_(3)COCl)+H_(2)underset("Xylene")overset(Pd-BaSO_(4))(to)underset(.Acetaldehyde")(CH_(3)CHO)+HCl`
B. `underset("ETHANOL")(CH_(3)CH_(2)OH)underset(573K)overset(Cu)(to)CH_(3)-underset("Acetaldehyde")overset(O)overset(||)(C)-H+H_(2)`
c. `underset("Acetic ACID")(CH_(3)COOH)overset(LiAlH_(4))(to)underset("Ethanol")(CH_(3)CH_(2)OH)underset(573K)overset(Cu)(to)CH_(3)-underset("Acetaldehyde")overset(O)overset(||)(C)-H`
d. `CH_(3)-underset(2-"Butanol")overset(OH)overset(|)(CH)-CH_(2)-CH_(3)underset(573K)overset(Cu)(to)CH_(3)-underset(2-"Butanone")overset(O)overset(|)(C)-CH_(2)-CH_(3)+H_(2)`
Discussion
6.

Bring about the following conversions : Nitrobenzene to benzoic acid

Answer»

SOLUTION :
Discussion
7.

Bring about the following conversions : Benzyl chloride to 2-phenyl ethanamine

Answer»

SOLUTION :
Discussion
8.

Brine solutionon electrolysiswill give

Answer»

`NAOH `
`O_ 2 `
`Cl_ 2 `
`H_ 2`

SOLUTION :NaOH,` Cl_ 2AND H _2`.Only` O_ 2`is notobtained.
Discussion
9.

Brine is electrolysed by using inert electroldes. The reaction at anode is

Answer»

`Cl^(-)(AQ) to 1//2 Cl_(2)(g) +e^(-), E_("Cell")^(@) =1.36 V`
`2H_(2)O(aq) to O_(2)(g)+4H^(+)(aq)+4e^(-), E_("Cell")^(@)=1.23 V`
`NA^(+)(aq)+e^(-)to Na(s), E_("Cell")^(@)=2.71 V`
`H^(+)(aq.) +e^(-) to 1//2 H_(2)(g), E_("Cell")^(@)=0.00 V`

SOLUTION :It is the correct ANSWER.
Discussion
10.

Brine is electrolysed by using inert electrodes. The reaction at anode is ........

Answer»

`Cl_((aq))^(-) to 1/2 Cl_(2(g)) - e^(-) , E_(("CELL"))^(Theta) = 1.36 V`
`2H_2O_((l)) to O_(2(g)) + 4H_((aq))^(+) + 4e^(-) , E_(("cell")^(Theta) = 1.23 V`
`Na_((aq))^(+) + e^(-) to Na_((s)) , E_(("cell")"^(Theta) = 2.71 V`
`H_((aq))^(+) + e^(-) to 1/2 H_(2(g)) , E_("(cell)")^(Theta) = 0.00V`

Solution :During ELECTROLYSIS of brine, the oxidation of OXYGEN and chlorine both are possible at ANODE. However, the oxidation of oxygen requires over voltage and so chloride ions are prefrentially oxidised at anode to `Cl_2`.
Discussion
11.

Brine is electrolysed by using inert electrodes. The reaction at anode is…………….

Answer»

`Cl^(-) (a) to (1)/(2) Cl_(2)(g) +e^(-), ""E_("cell")^(0) = 1.36V`
`2H_(2)O(l) to O_(2)(g)+4H^(+)+4E^(-),""E_("cell")^(0) = 1.23V`
`Na^(+) (aq) +e^(-) to Na (s), ""E_("cell")^(0) = 2.71V`
`H^(+)(aq) + e^(-) to (1)/(2)H_(2) (g), ""E_("cell")^(0) = 0.00V`

Answer :A
Discussion
12.

Brineiselectrolysedby usinginertelectrodes.The reaction atanodeis ........

Answer»

` C l^(-)(aq)to(1)/(2) Cl_ 2(g)+e ^(- ) ,E^(@ )""_("Cell") =1.36 V`
`2 H_2 O (l)toO_2 (g) +4H^(+) +4E^(- ) , E^(@)""_("Cell") =1.23 V `
` Na ^( +) (aq)+e ^( -) toNa (s) , E ^(@)""_("cell") =2.71V`
` H ^(+ ) (aq)+e ^(- ) to(1)/(2) H_ 2 O(g), E^(@)""_("cell") = 0.00 V`

SOLUTION :Althoughoxidationpotentialof` Cl ^(-)` ionsis higherthanthatof` H_ 2 O `, YET oxidationof ` Cl ^- `ionsoccursinpreferenceto` H_ 2O `sincedue toovervoltageof` O_ 2` (i.e.,waterneedsgreatervoltagefor oxidation to ` O_2 `asitisakineticallyslowprocess) muchhigher potentialthan`1* 36 `V isactuallyneededfor the oxidationof`Cl^(-) `ionsto` Cl_ 2`.
Discussion
13.

Brine is electrolysed by using inert electrodes. The reaction at anode is _____.

Answer»

`Cl^(-)(aq) to (1)/(2) Cl_(2)(G) +E^(-), "" E_("CELL")^(@)=1.36V`
`2H_(2)O(l) to O_(2)(g)+4H^(+)+4e^(-), "" E_("Cell")^(@)=1.23 V`
`NA^(+)(aq)+e^(-)to Na(s), "" E_("Cell")^(@)=2.71V`
`H^(+)(aq)+e^(-) to (1)/(2)H_(2)(g), "" E_("Cell")^(@)=0.00V`

Answer :A
Discussion
14.

Brine helps in food perservation by

Answer»

KILLING the germs
destroying the ENZYME action
sealing the FOOD with layer of salt and pervent the direct contact
reducing the avaible water for the GROWTH of microbes

Answer :D
Discussion
15.

Brine is chemically:

Answer»

CONC. SOLUTION of `Na_2CO_3`
Conc. Solution of `Na_2SO_4`
Conc. Solution of NaCl
Conc. Solution of ALUM

ANSWER :C
Discussion
16.

Briefly explain why electronic configuration of lanthanoids are not known with certainty ?

Answer»

Solution :`4f 5d ` subshells are very CLOSE in ENERGY. +ve ELECTRONS can JUMP from 4f to 5d or vice-versa.
Discussion
17.

Briefly explain why electronic configuration of lanthanoids are not known with certainty.

Answer»

Solution :In the lanhanoids, 4f and 5d subshells are very close in energy. The OUTERMOST 6s orbital remains filled with 2 electrons `( 6s^(2))`. The electron can easily JUMP from 4f to 5d or vice-versa. Further, irregularities in ELECTRONIC CONFIGURATION are also RELATED to the stabilities of `f^(0), f^(7)` and `f^(14)` occupacy of f-orbitals. Hence, their electronc configuration are not known with certainity.
Discussion
18.

Briefly explain why the following reaction does not occur

Answer»

Solution :By itself, `(CH_(3))_(3)CO^(-)`is not a good enough LEAVING group to allow iodide to ATTACK the methyl carbon in an `S_(N)2`fashion. PROTONATION of the oxygen converts the leaving group to methanol `(CH_(3)OH)`, which is good enough to leave when iodide attacks.
Discussion
19.

Briefly explain the effects of temperature on the solubility of solids in liquids.

Answer»

SOLUTION :If the PROCESS of dissolution is exothermic, the SOLUBILITY decreases with the increase in TEMPERATURE.
(ii) If the process of dissolution is endothermic, the solubility INCREASES with the increase in temperature.
Discussion
20.

Briefly explain the acidic nature of phenols.

Answer»

Solution :The acidic nature of phenols can be explained on the BASIS of resonance.

Due to resonance in phenol the `O-` atom of `-O-H` group acquires slight `+ve` charge and `H-` atom is RELEASED as proton. ALSO phenoxide ion is more stabilised due to resonance.
`therefore"The equilibrium (1) will shift towards R.H.S. giving more of "H^(+)" ions."`
Discussion
21.

What is the name of the method that is used in manufacturing of sodium hydroxide? Explain the method.Write the equations of the reactions involved in this process

Answer»


ANSWER :REFER THEORY SECTION 6.7 (E)
Discussion
22.

Briefly discuss Schottky defects and give examples.

Answer»

SOLUTION :When imperfections or defects in a crystal are caused by a DEPARTURE from the periodic ARRANGEMENT in the VICINITY of an atom or a group of atoms, the imperfections are called point defects. The imperfections are caused either by missing or dislocations of a. constitutent particle to a position meant for ANOTHER particle or shifting to an interstitial position. Point defects are of two common types :
1. Schottky defects 2. Frenkel defects.
1. Schottky defects. This defect arises if some of the atoms or ions are missing from their normal lattice sites. The lattice sites which are unoccupied are called latrice vacancies or holes. Since the crystal is to remain electrically neutral, equal number of cations and anions are missing. The ideal AB crystal is shown in Fig. The existence of two holes, one due to a missing cation and the other due to a missing anion, is shown in Fig. Schottky defect is more common in strongly ionic compounds having a high coordination number.

For example, NaCl and CsCl ionic solids have Schottky defects. Because of the presence of vacancies in crystals, its density is markedly lowered.
2. Frenkel defects. This defect arises when an ion is missing from its own position and occupies an interstitial site. The existence of one hole due to a missing cation its proper position and occupying an interstitial position is shown in Fig. In this case also, the crystal remains electrically neutral. Frenkel defects generally occur in

compounds in which anions are much larger than the cations and the co-ordination number is low. These defects can be found in silver halides because of the small size in the `Ag^(+)` ion.
Discussion
23.

BrF_(5) undergoes hydrolysis then the products formed are

Answer»

`HBrO_(2),HF`
`HOBr,HF`
`HBrO_(3),HF`
`HBrO_(4),HF`

ANSWER :C
Discussion
24.

BrF_3 is a liquid which considerably undergoes self ionization to form cationic and anionic species.Based on VSEPR theory, number of 90 degree F-Br-F bond angles is ……. In anionic species. 2BrF_3 hArr [BrF_2]^++ [BrF_4]^(-)

Answer»


SOLUTION :
Discussion
25.

Brewery and sugar factory waste alter the quality of a water body by increasing

Answer»

pH
Temperature
Turbidity
COD and BOD

Answer :D
Discussion
26.

Breding arc method cannot be used to prepare colloidal solutionof which of the following ?

Answer»

`Pt`
`Fe`
`Ag`
`Au`

Solution :Electrical disintegration of Bredigs are METHOD is used for preparing colloidal solution of metal like gold silver, platinum. Etc. In this method electric arc is struck between electrodes of metal immersed in the dispersion medium. The intense heat produced vaporizes some of the METALS which then condenses to form particles of colloidal size. As iron do not vaporise easily, it cannot be prepared by this method. A colloidal solution of `Au,Ag` and `Pt` can also be prepared by reducing its SALT solution with suitable reducing agent.
`2AuCl_(3)+3SnCl_(2)rarrunderset("Gold sol")(2Au+3SnCl_(4))`
Discussion
27.

Bredig's arcmethod cannot be used for the preparation of colloidal sol of :

Answer»

Cu
Mg
Ag
Na

Answer :B::D
Discussion
28.

Bredig's arc method involves

Answer»

Only DISPERSION of metal
Only CONDENSATION of metal
Dispersion as WELL as condensation
Neither dispersion nor condensation

Answer :C
Discussion
29.

Bredig's arc method cannot be used to prepare colloidal solution of

Answer»

Pt
Fe
Ag
Au

Solution : Bredig.s arc method cannot be used because at HIGH TEMPERATURE, IRON REACTS with water which is in the FORM of steam.
Discussion
30.

Brass is mixture of …… metals.

Answer»

Zn, NI
Cu, SN
Cu, Zn
Cu, Zn, Ni

ANSWER :C
Discussion
31.

Brass is an example of a the defect

Answer»

SCHOTTKY DEFECT
Frenkel defect
Interstitial defect
SUBSTITUTION impurity defect

Solution :It is an ALLOY of copper and ZINC metal
Discussion
32.

Brass is an alloy of ul"copper and tin"

Answer»

SOLUTION :COPPER and ZINC
Discussion
33.

Brass is an alloy of ___________ and ___________.

Answer»

ZN and Cu
Cu and Sn
Sn and Zn
Cu, Zn and Sn

Answer :A
Discussion
34.

Brass is an alloy of :

Answer»

ZN and Cu
Cu and SN
Zn and Sn
Cu, Zn and Sn

ANSWER :A
Discussion
35.

Brass is a mixture of

Answer»

CU and SN
Cu and ZN
Sn and Zn
Cu and carbon

Answer :B
Discussion
36.

Brass is :

Answer»

A COMPOUND
An amalgam
An ELEMENT
An ALLOY

ANSWER :D
Discussion
37.

Brass contains which metals?

Answer»

SOLUTION :COPPER and ZINC
Discussion
38.

Brass contains

Answer»

(Cu+Sn)
(Cu+Ni)
(Cu+Zn)
(Mg+AL)

ANSWER :C
Discussion
39.

Brass contains ___________.

Answer»

SOLUTION :`90%` CU and` 10% ZN`
Discussion
40.

Brandy is distilled form fermented fruits, rum is distilled form molasses, Bourbon whisky form corn, rye whisky form rye, sotch whisky form barley, Irish whisky form potatoes, Saki form rice, and beer form….

Answer»

Malt
Yeast
Grapes
Apples

Solution :NA
Discussion
41.

Bragg's law is given by the equation:

Answer»

`nlambda = 2 SIN theta`
`nlambda = 2d sin theta`
`2d = nlambda sin theta`
`nlambda = d sin theta`

ANSWER :B
Discussion
42.

The PH of a solution is defined by the equation:

Answer»

`nlambda=2sintheta`
`nlambda =2dsintheta`
`2d=nlambdasintheta`
`nlambda=dsintheta`

ANSWER :B
Discussion
43.

Bragg's equation is:

Answer»

`nlambda=2thetasintheta`
`nlambda=2dsintheta`
`2nlambda=dsintheta`
`LAMBDA=(2d/n)SINTHETA`

ANSWER :B
Discussion
44.

Bragg’s equation has no solution if:

Answer»

`nlambda=2d`
`nlambdagt2d`
`nlambdalt2d`
All

Answer :B
Discussion
45.

Bragg’s equation is- (A) ngamma=20sin theta(B) ngamma=2d sin theta 2ngamma=d sin theta(D)gamma=(2d//n) sin theta

Answer»

Solution :(B) BRAGG’s EQUATION is `ngamma` = `2d SIN THETA`.
Discussion
46.

Br_(2)(l) reacts with Cl_(2) (g) to form BrCl_(3) ,simultaneously .How many moles of Cl_(2)(g) reacts completely with 3 moles of Br_(2)(l) to form BrCl and BrCl_(3) in 5 :1 molar ratio .

Answer»


ANSWER :4
Discussion
47.

Br_(2) water in NaOH soin .Oxidises Mn(OH)_(2) to a…. Ppt due to theformationof MnO(OH)_(2)

Answer»

BLACK
violet
Blue
white

Answer :a
Discussion
48.

Br_2+NaOHrarrNaBrO_3+H_2O In the above balanced chemical equation, number of moles of Br_2 reduced to bromide is

Answer»

1.5
2.5
3
5

Answer :B
Discussion
49.

Br_(2) reacts with O_(2) in either of the following ways depending upon supply of O_(2) Br_(2) + (1)/(2) O_(2) rarr Br_(2) O Br_(2) + (3)/(2) O_(2) rarr Br_(2) O_(3) If 4 moles of Br_(2) and 10 moles of O_(2) are taken in a container then calculate the number of moles of reactant left complete reaction.

Answer»

<BR>

Solution :`{:(Br_(2),+,(3)/(2)O_(2),RARR,Br_(2)O_(3),),("Moles",4,,(3)/(2) xx 4,,),(,,,= 6 "moles",,):}`
Moles of REACTANT `(O_(2))` left = 4 moles
Discussion
50.

Br_(2)+H_(2)O rarr Br^(-) + BrO_(3) In the above reaction, following takes place a

Answer»

Bromine UNDERGOES OXIDATION & REDUCTION
Bromine is oxidised only
Bromine is REDUCED only
None

Answer :A
Discussion