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(c) Inflation gap

When the liability to pay and burden of a tax lie on same person, is treated as a Direct Tax. ExIncome Tax, Corporation Tax etc. 

Excess Demand is not a desired situation because it does not lead to any increase in level of aggregate supply as the economy is already at full employment level. Excess demand has the following effect on output, employment and general price level: 

1. Effect on Output : Excess demand does not affect the level of output because economy is already at full employment level and there is no ideal capacity in the economy. 

2. Effect on Employment : There will be no change in the level of employment as the economy is already operating at full employment equilibrium and there is no involuntary unemployment. 

3. Effect on General Price Level : Excess demand leads to rise in the general price level (known as inflation) as aggregate demand is more than aggregate supply.

1. 2FeCl₃ + 3NH₄OH(aq) → Fe₂O₃ . xH₂O(s) + 3NH₄Cl
2. 6XeF₄ + 12H₂O → 4Xe + 2XeO₃ + 24HF + 3O₂

Answer:Sc, Zn, Cd

Slope of line represents 1/n value, i.e reverse of number of a layers of a adsorption.

2-bromo cyclopentane carbaldehyde

Second order

Nitrogenous base is linked to first carbon. 

Phosphate is linked to fifth carbon.

Marks to be allotted for creatively touching on following aspects of communication 

• Verbal Communication 
• Non – Verbal Communication
• Paralanguage 

1. Al₂O₃ → 2Al³⁺
   2Al³⁺ + 6e^– → 2Al
   Thus, 6F of electricity is required.
2. Cu₂Cl₂ → 2Cu⁺
   2Cu⁺ + 2e^– → 2Cu
   Thus, 2F of electricity is required.

Faraday’s first law of electrolysis : The amount of any substance deposited or liberated at the electrode is directly proportional to the quantity of electricity passing through the electrolyte.

Cu²⁺ + 2e^– → Cu

:. Quantity of charge required for reduction of 1 mol of Cu²⁺ = 2F

The sequence is 103, 110, ......, 999

∴ 999 = 103 + (n – 1) × 7 

⇒ n = 129

Therefore (129+1)/2 = 65th term is the middle term

Middle term = 103 + (64) × 7 = 551

Sum of first 64 terms = 32 [206 + 63 × 7] = 20704

Sum of last 64 terms= 32 [1116 + 63 × 7] = 49824

The sequence is 10, 13, ..... 94. 

94= 10 + (n – 1) 3 ⇒ n = 29

Therefore (29 + 1)/ 2 = 15th term is the middle term

Middle term = 10 + 14 × 3 = 52

Sum of first 14 terms = 14/2 [20 + 13 × 3] = 413

Sum of the last 14 terms = 14/2 [110 + 13 × 13] = 1043

 1/x-2+2/x-1=6/x

1(x-1)+2(x-2)/x²-x-2x+2=6/x

x-1+2x-4/x²-3x+2=6/x

3x-5/x²-3x+2=6/x

3x²-5x=6x²-18x+12

6x²-3x²-18x+5x+12=0

3x²-13x+12 = 0

3x²-9x-4x+12 = 0

3x(x-3)-4(x-3) = 0

(3x-4)(x-3)=0

x=3 or 4/3

1,200 = 4 × 3 × (2 × 5)² 

= 2⁴ × 3 × 5² 

The smallest natural number is 3.

Double fertilization : 

It occurs when one male nucleus fertilizes (fuses) with egg cell to form zygote cell and other male nucleus fuses (fertilizes) with two polar nuclei to cause triple fusion. As these two types of fertilization take place at the same time in the ovule of the plant, it is known as double fertilization.

After fertilization:

(i) Ovary develops into fruit.

(ii) Ovules develop into seeds.

(a) 5A, 

(b) 15A

void AddUp(int Arr[], int N)

{

for(int i = 0; i<N; i++)

{

if(i82==0)

Arr[i]+ = Arr[i+1];

else

Arr[i]+ = 10;

}

}

void SUMMIDCOL(int MATRIX[ ][10], int N, int M)

{

int j, SUM=0;

j=M/2:

for(int i=0: i<N;i++)

SUM + = MATRIX [i][j];

cout<<"SUM of MIddle Column : "<<SUM;

}

(i)  DISTINCT  TID

101

103

102

104

105

(ii)  TIDCOUNT(*)MIN(FEES)

101      2    12000

(iii)  COUNT(*)SUM(FEES)

4      65000

void PUSHGIFT( )

{

GIFT *G = new GIFT;

cout<<"Enter gift code and description";

cout>>G->GCODE;

gets(G->GDESC);

if (TOP == NULL)

{

TOP = G:

}

else

{

G->Link = TOP

TOP = G;

}

}

void PURETEXT()

{

fstream fpl;

fpl. open("MYNOTES.txt", ios::in | ios::out): 

if(!fpl)

{

cout<<"Cannot open file"<<end1;

exit (0);

}

char ch;

char c;

while(!fpl.eof())

{

c=fpl.get();

if(c=='K')

{

fpl.seekg(-1, ios::cur);

fpl.put('C'):

}

}

fp1.clear();

fp1.seekp(0, ios::beg);

cout<<"\n After replacing character\n"); 

while(!fpl.eof())

{

fp1.get(ch);

cout<<ch;

fpl.close();

}

Output

42

84

void COUNTPICS( )

{

int count = 0;

PHOTOS obj;

ifstream fpl;

fp1.open("PHOTOS.DAT", ios::binary);

while (fpl.read((char*)&obj. sizeof(obj)))

{ if(strcmp(obj.GETPTYPE(),"PORTRAIT")==0) 

count++;

}

cout<<"The total number of PHOTOS of type PORTRAIT is "<<count;

fpl.close();

}

Cartesian Product has been used to produce the output.

Degree of the FINAL RESULT = 5

Cardinality of the FINAL RESULT = 9

Output

Client Number: 8 of 200

(i) SELECTION

Degree of table RESULT = 3

Cardinality of table RESULT = 2

• Do not share user id and password with anyone
• Avoid doing transactions from cyber café and other public places.

UPDATE Student SET Marks = 50 WHERE Roll number = 2;

ALTER TABLE Student ADD Game_Played VARCHAR (30) ;

SELECT DISTINCT (Location) FROM Employee ;

The correct code is :

SELECT ID, Salary FROM empsalary

WHERE Salary = 56000 ;

struct student

{

char name [10];

float marks [3];

int maxmarks;

float total=0.0, percentage=0.0;

}s;

void main ()

{

int i;

cout << “enter name”;

for (i=0; i<3;i++)

{

cin>>s.marks [i];

s. total + = s.marks [i];

}

cout<<"Enter total marks";

cin>>s.maxmarks;

s. percentage = (s.total*s.maxmarks)/100;

cout << “ student details “<<endl;

cout <<”Name” << s. name;

cout <<” marks” << s.marks [1] << “/t”

<<

s. marks [2] << “\t” << s. marks [3] <<

endl;

cout << “ percentage:” << s. percentage;

cout << “ Total:” << s. total;

}

(a) super() function is used to call the methods of base class which have been extended in derived class. Also, it is the importance of derived class __init__() to invoke the base class __init__()

(b) Single level Inheritance

# include <iostream.h>

void main( )

{

int a[3] [3], b[3] [3], mult [3] [3], i,

j, k;

cout << "Enter elements of matrix 1"

<< endl;

for(i = 0; i <3;i++)

for(j = 0; j <3; j++)

{

cout << "Enter element at position" <<

i + 1 << j + 1 << " : ";

cin >> a[i] [j];

}

cout << "Enter elements of matrix 1"

<< endl;

for(i = 0; i <3;i++)

for(j = 0; j <3; j++)

{

cout << "Enter element at position" <<

i + 1 << j + 1 << " : ";

cin >> b[i][j];

}

for(i = 0; i <3;i++)

for(j = 0; j <3; j++)

{

mult [i] [j] =0;

}

// Multiplying matrix a and b and

storing in array mult.

for(i = 0; i <3;i++)

for(j = 0; j <3; j++)

for(k = 0; k < 3; k++)

{

mult[i] [j] += a[i] [k] * b[k] [j];

}

cout << endl << "Output Matrix: " <<

endl;

for(i = 0; i <3;i++)

{ for(j = 0; j <3; j++)

{

cout << " " << mult[i][j];

} cout << endl;

}

}

def findname(name):

if phonebook.has_key():

del phonebook[name]

else:

print”Name not found”

print "Phonebook Information"

print "Name",'\t',"Phone number"

for i in phonebook.keys():

print i,'\t',phonebook[i]

void main ()

{

int N, a[10], pos = -1, x = 0;

cout <<” enter array size “;

cin >> N;

for (int i = 0; i<N; i++)

cin >> a[i];

cout <<” enter value to be searched”;

cin >> x;

for (i = 0; i < N; i++)

if (a[i] == x)

{

pos = i; found = 1;

cout << x << “ found @ “ << i+1 << “

position”;

break;

}

if ( found = = 0)

cout << x<< “not found in array”;

}

def divide(x, y):

try:

result = x / y

except ZeroDivisionError:

print "division by zero!"

else:

print "result is", result

In the above example:

try block consists of code that can raise an error. When y(denominator) gets a 0 value, ZeroDivisionError is raised which is handled by except clause. In case of no exception else statement is executed.

In case there is no error the statement(s) in else clause are executed.

def arrangelements(X):

L=len(X)

for i in range(L):

if a[i]<0 and i!=0:

j=i

while j!=0 and a[j-1]>0 :

a[j],[j-1]=a[j-1],a[j]

j=j-1

def addbook(self):

a=input("enter book number: ")

book.bk.append(a)

def removebook (self):

if (book.bk==[]):

print "Queue empty"

else:

print "deleted element is: ",book.bk[0]

del book.bk[0]

def Fibonacci (max):

a, b = 0, 1

while a <= max:

yield a

a, b = b, a + b

def generatefibo(n)

for i in Fibonacci (n):

print i,

$ symbol is used to be placed in front of the column letter and row number in a cell reference to make it absolute reference.

The whole mail merge process can be divided into following main steps:

(i) Creating a Main Document or Template.

(ii) Creating a Data Source.

(iii) Defining the Merge Fields in the main document.

(iv) Merging the Data with the main document.

Main Document : It is the main document that contains the text that is to be send to all the recipients.

Data Source : It consists of a mailing list containing the contact details of all the recipients like name, address, city, pin code, telephone number etc.

<?xml version = "1.0"?> is correct processing instruction (PI) of a XML document.

She should use Find & Replace tool as follows:

1. To display the Find & Replace dialog box, use the keyboard shortcut Control+F or select Edit > Find & Replace.

2. Type the text which we want to find in the “Search for” box.

3. To replace the text with different text, type the new text in the “Replace with” box.

4. We can select various options such as matching the case, matching whole words only, or doing a search for similar words.

5. When we have set up our search, click Find. To replace text, click Replace instead.

Follow the steps for spell checking :

Click on 'Tools' in the menu bar and then 'Spelling and Grammar' from the drop-down menu, or press Alt + T and then press Alt + S, to open the 'Spelling' window.

Misspelled words will be highlighted with red colour. A number of suggestions will be available in the suggestion box. Choose the desired one and select Change/Change All/Auto Correct option as per the requirement and click on Close button to close the spelling dialogue box.

Documents can also be spell-checked any time by pressing F7.

(i) Landscape

(ii) Portrait