Saved Bookmarks
| 1. |
Write SQL queries for TRAINERTIDTNAMECITYHIREDATESALARY101SUNAINA MUMBAI1998-10-1590000102ANAMIKADELH1994-12-2480000103DEEPTICHANDIGARG2001-12-21 82000104MEENAKSHI DELHI2002-12-25 78000105RICHAMUMBAI 1996-01-1295000106MANIPRABHACHENNAI2001-12-1269000COURSECIDCNAMEFEESSTARTDATETIDC201AGDCA120002018-07-02101C202ADCA150002018-07-15103C203DCA100002018-10-01102C204DDTP90002018-09-15 104C205DHN200002018-08-01101C206O LEVEL180002018-7-25105(i) SELECT DISTINCT TID FROM COURSE;(ii) SELECT TID, COUNT(*), MIN(FEES) FROM COURSE GROUP BY TID HAVING COUNT(*)>1;(iii) SELECT COUNT(*), SUM(FEES) FROM COURSE WHERE STARTDATE< ‘2018-09-15’; |
|
Answer» (i) DISTINCT TID 101 103 102 104 105 (ii) TIDCOUNT(*)MIN(FEES) 101 2 12000 (iii) COUNT(*)SUM(FEES) 4 65000 |
|