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plss Solve for x: 1/(x–2)+2/(x–1)=6/xsolve it |
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Answer» 1/x-2+2/x-1=6/x 1(x-1)+2(x-2)/x2-x-2x+2=6/x x-1+2x-4/x2-3x+2=6/x 3x-5/x2-3x+2=6/x 3x2-5x=6x2-18x+12 6x2-3x2-18x+5x+12=0 3x2-13x+12 = 0 3x2-9x-4x+12 = 0 3x(x-3)-4(x-3) = 0 (3x-4)(x-3)=0 x=3 or 4/3 |
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