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The enthalpy, internal energy during a process and change in volume are 500 units, 400 units, and 2 units. What is the pressure that is exerted on the gas during this process?(a) 20 units(b) 80 units(c) 100 units(d) 50 unitsThe question was posed to me in an interview.This is a very interesting question from Thermodynamics topic in division Thermodynamics of Chemistry – Class 11

Answer»

The correct answer is (d) 50 UNITS

Explanation: We know thatΔH = ΔU + PΔV; ΔH is the enthalpy, ΔU is the internal energy, ΔV is the CHANGE in volume and P is the PRESSURE. So by SUBSTITUTING the enthalpy, internal energy during a process and change in volume as 500 units, 400 units and 2 units, we get pressure as 50 units.



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