Calculate the Gibbs free energy for the reaction of conversion of ATP into ADP at 293 Kelvin the change in enthalpy is 19.07 Kcal and the change in entropy is 90 cal per Kelvin.(a) 7.3 cal(b) -5.3 Kcal(c) 7.3 Kcal(d) -7.3 KcalI got this question during an internship interview.I'm obligated to ask this question of Gibbs Energy Change and Equilibrium in section Thermodynamics of Chemistry – Class 11

Calculate the Gibbs free energy for the reaction of conversion of ATP

1.	Calculate the Gibbs free energy for the reaction of conversion of ATP into ADP at 293 Kelvin the change in enthalpy is 19.07 Kcal and the change in entropy is 90 cal per Kelvin.(a) 7.3 cal(b) -5.3 Kcal(c) 7.3 Kcal(d) -7.3 KcalI got this question during an internship interview.I'm obligated to ask this question of Gibbs Energy Change and Equilibrium in section Thermodynamics of Chemistry – Class 11
Answer» Right ANSWER is (d) -7.3 Kcal To EXPLAIN: We have ΔG = ΔH – TΔS; by SUBSTITUTING ΔH = 19.07 kcal and ΔS = 90 cal/K, we get ΔG = 19.07 Kcal – 293(90 cal/K) = 19.07 Kcal – 26.37 Kcal = -7300 cal = -7.3 Kcal. The Gibbs FREE energy CHANGE is -7.3 Kcal.

Discussion

No Comment Found

Related InterviewSolutions

Write 1 Faraday in terms of coulombs.(a) 96500 C(b) 95600 C(c) 9560 C(d) 9650 CThis question was addressed to me in an interview.I'd like to ask this question from Gibbs Energy Change and Equilibrium in section Thermodynamics of Chemistry – Class 11
In the equation, ΔG = – 2.303 RT logK, what is K?(a) change in temperature(b) kelvin(c) equilibrium constant(d) change in enthalpyThe question was asked during a job interview.I'm obligated to ask this question of Gibbs Energy Change and Equilibrium in division Thermodynamics of Chemistry – Class 11
What is the relation between Gibbs free energy and the EMF of the cell?(a) ΔG = -nFEcell(b) G = -nFEcell(c) ΔG = -nEcell(d) ΔG = -nFcellI had been asked this question in an international level competition.Query is from Gibbs Energy Change and Equilibrium in chapter Thermodynamics of Chemistry – Class 11
Calculate the Gibbs free energy for the conversion of oxygen to Ozone at room temperature if KP is given as 2.47 x 10^-29.(a) 163 kJ/mol(b) 163 J/mol(c) 163 kJ(d) 163 k/molI have been asked this question in class test.My question comes from Gibbs Energy Change and Equilibrium topic in chapter Thermodynamics of Chemistry – Class 11
The Gibbs free energy is positive when a change in enthalpy and change in entropy are positive at ____________(a) high temperatures(b) low temperature(c) all temperatures(d) only at 0 KelvinThis question was posed to me in homework.This interesting question is from Gibbs Energy Change and Equilibrium topic in portion Thermodynamics of Chemistry – Class 11
Which of the following is not a type of exergonic reaction?(a) formation of table salt from Sodium and chlorine(b) combustion reaction(c) chemiluminescence(d) photosynthesisI have been asked this question in class test.I'm obligated to ask this question of Gibbs Energy Change and Equilibrium in chapter Thermodynamics of Chemistry – Class 11
The melting of ice into liquid water is an example of tube _______________ reaction.(a) endergonic(b) exergonic(c) exothermic(d) endothermicThis question was addressed to me in an internship interview.The above asked question is from Gibbs Energy Change and Equilibrium topic in division Thermodynamics of Chemistry – Class 11
In a reaction, the change in entropy is given as 2.4 cal/K and the change in Gibbs free energy is given as 3.4 kcal, calculate the change in heat at the temperature of 20-degree centigrade?(a) 3.4 kcal(b) 3.4 cal(c) 3.4 kJ(d) 3.4 JI got this question by my college professor while I was bunking the class.My question is taken from Gibbs Energy Change and Equilibrium topic in chapter Thermodynamics of Chemistry – Class 11
Calculate the Gibbs free energy for the reaction of conversion of ATP into ADP at 293 Kelvin the change in enthalpy is 19.07 Kcal and the change in entropy is 90 cal per Kelvin.(a) 7.3 cal(b) -5.3 Kcal(c) 7.3 Kcal(d) -7.3 KcalI got this question during an internship interview.I'm obligated to ask this question of Gibbs Energy Change and Equilibrium in section Thermodynamics of Chemistry – Class 11
Find out whether the following reaction is spontaneous or not at 127 degrees centigrade? N2(g) + 3H2(g) \(\rightleftharpoons\) 2NH3(g); ΔH = 92.22 kJ/mol and ΔS = -198.75 J/K-mol.(a) it is spontaneous(b) it is not spontaneous(c) it may be spontaneous(d) cannot predictThis question was posed to me by my school teacher while I was bunking the class.The doubt is from Gibbs Energy Change and Equilibrium in section Thermodynamics of Chemistry – Class 11

Discussion

No Comment Found

Related InterviewSolutions

Reply to Comment