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Calculate the Gibbs free energy for the conversion of oxygen to Ozone at room temperature if KP is given as 2.47 x 10^-29.(a) 163 kJ/mol(b) 163 J/mol(c) 163 kJ(d) 163 k/molI have been asked this question in class test.My question comes from Gibbs Energy Change and Equilibrium topic in chapter Thermodynamics of Chemistry – Class 11

Answer»

The correct choice is (a) 163 kJ/mol

Explanation: The chemical EQUATION for the conversion of oxygen to Ozone is 3/2O2 → O3. We have the equation, ΔG = – 2.303 RT LOG KP. So by SUBSTITUTING we get ΔG = – 2.303 x 8.314 J/K-mol x 293K x 2.47 x 10^-29 = 163000 J/mol = 163 kJ/mol.



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