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Find out whether the following reaction is spontaneous or not at 127 degrees centigrade? N2(g) + 3H2(g) \(\rightleftharpoons\) 2NH3(g); ΔH = 92.22 kJ/mol and ΔS = -198.75 J/K-mol.(a) it is spontaneous(b) it is not spontaneous(c) it may be spontaneous(d) cannot predictThis question was posed to me by my school teacher while I was bunking the class.The doubt is from Gibbs Energy Change and Equilibrium in section Thermodynamics of Chemistry – Class 11

Answer» RIGHT ANSWER is (b) it is not spontaneous

Explanation: We have ΔG = ΔH – TΔS; by substituting ΔH = 92.22 kJ/mol and ΔS = -198.75 J/K-mol, we get ΔG = 92.22 kJ/mol – 400k(-198.75 J/K-mol) = 92.22 kJ/mol + 79.5 kJ/mole = 171.72 KJ/mol. As Gibbs free ENERGY is positive the reaction is NON spontaneous.


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