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In the equation, ΔG = – 2.303 RT logK, what is K?(a) change in temperature(b) kelvin(c) equilibrium constant(d) change in enthalpyThe question was asked during a job interview.I'm obligated to ask this question of Gibbs Energy Change and Equilibrium in division Thermodynamics of Chemistry – Class 11

Answer»

Correct CHOICE is (c) equilibrium constant

The best I can explain: In the above equation ΔG = – 2.303 RT logK, G is the change in standard Gibbs free energy, R is the universal gas constant, T is TEMPERATURE, K is the equilibrium constant while LOG stands for the logarithm of base 10.



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