In case of the decomposition of hydrogen molecule into two hydrogen atoms, the enthalpy of atomization is same as the _________(a) bond dissociation enthalpy(b) enthalpy of formation(c) enthalpy of combustion(d) enthalpy of sublimationThe question was posed to me during an interview for a job.My enquiry is from Thermodynamics in chapter Thermodynamics of Chemistry – Class 11

In case of the decomposition of hydrogen molecule into two hydrogen at

1.	In case of the decomposition of hydrogen molecule into two hydrogen atoms, the enthalpy of atomization is same as the _________(a) bond dissociation enthalpy(b) enthalpy of formation(c) enthalpy of combustion(d) enthalpy of sublimationThe question was posed to me during an interview for a job.My enquiry is from Thermodynamics in chapter Thermodynamics of Chemistry – Class 11
Answer» Right OPTION is (a) BOND DISSOCIATION enthalpy For explanation: In case of the decomposition of hydrogen molecule the enthalpy is the same as enthalpy of atomization as well as bond dissociation enthalpy because the bond association enthalpy refers to the breakage of H-H Bond. So that TWO hydrogen atoms are formed whereas enthalpy of atomization is the breakage of hydrogen molecules in ORDER to form two atoms.

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