1.

Find the equation of the tangent to the parabola y2 = 8x at t = 1 on it

Answer»

Given equation of the parabola is y2 = 8x 

Comparing this equation with y2 = 4ax, we get 

4a = 8 

a = 2 

t = 1 

Equation of tangent with parameter t is yt = x + at2 

∴ The equation of tangent with t = 1 is 

y(1) = x + 2(1)2 

y = x + 2 

∴ x – y + 2 = 0



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