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Find the equation of the tangent to the parabola y2 = 8x at t = 1 on it |
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Answer» Given equation of the parabola is y2 = 8x Comparing this equation with y2 = 4ax, we get 4a = 8 a = 2 t = 1 Equation of tangent with parameter t is yt = x + at2 ∴ The equation of tangent with t = 1 is y(1) = x + 2(1)2 y = x + 2 ∴ x – y + 2 = 0 |
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